How to measure the volume of an object with Archimedes 20

Correctly it should be:

How to find volume using Archimedes' principle?

Archimedes' principle: p liquid = g drain = p g v object.

Archimedes is dead, so you might as well think of something else.

From Archimedes' principle, f (buoyancy) = p (density of liquid) v (volume of discharged water and ignition) g (constant).then p=f vg 1If an object sinks in water, its volume is equal to the volume of its discharge water, and the volume of the object can be measured with a graduated cylinder first, and the volume of the object can be calculated as if the object is suspended in a liquid, then the density of the object is equal to.

Experiment 09 Measuring the density of solids and liquids.

Water vg = liquid vg =

The density can be found to be equal to.

That's pretty much it, and you write it yourself in a physics answer format.

The buoyant force experienced by the object in the liquid is equal to the gravitational force expelling the liquid, and the volume of the object is v and the volume is p

solution, p = 875 kg cubic meters.

First, determine the volume of the object according to the float in the water.

f float = , v matter = v row = f float g =

F float = in this liquid

Liquid = f float v g =

By Archimedes' principle.

It can be seen that f (buoyancy) = p (density of liquid) v (volume of discharged water) g (constant.

then p=f vg 1If the object sinks in water, then its volume and other things are clustered in the volume of its discharged water, and a graduated cylinder can be used first.

If the object is suspended in a liquid, then the density of the object is equal to the density of the liquid If the object floats in the liquid, then its buoyancy is equal to the gravitational force it is subjected to, and the gravity of the object is measured with a spring dynamometer, and its volume is measured with a graduated cylinder, and the density can be calculated by substituting it

Attached: A method for measuring the volume of an object with a graduated cylinder.

1 first pour a certain amount of water into the graduated cylinder, the volume is v1 2 and then put the object to be measured into the water of the graduated cylinder, and observe that the total volume is v2 3 The volume of the object is v3 v2 v1

The use of spring dynamometers is very simple, so I will not repeat them here

Put the object into a liquid (water recommended) with a known density, according to the buoyancy formula, the volume of water discharged by the object is known, the buoyancy can be measured, and the density of the liquid is also known, and the mass of the object can be calculated according to the mass formula.

The density of the object can be calculated.

Archimedes' principle defines that an object immersed in a stationary fluid (gas or liquid) is subjected to a buoyant force equal to the weight of the fluid discharged by the object, vertically upwards and through the centroid of the discharged fluid.

Mathematical expression: f float = g row = tu ·g · v row .

The buoyancy of the object = the gravity of the water = the density of the water * g * the volume of the water that the object is subjected to is determined by two factors: the density of the liquid and the volume of the liquid discharged by the object. It has nothing to do with the depth at which the object is immersed in the liquid, the mass and density of the object, and the shape of the object.

Steps:1The stone is hung under the spring dynamometer, and the indication of the dynamometer at this time is the gravity g2 of the stoneSubmerge the stone in water and write down the number f of the dynamometer at this time and calculate the density of the stone: the mass of the stone m = g g

The buoyancy of a stone submerged in water f floats = g-f

The volume of the stone block v = f float p water g = (g-f) p water g the density of the stone p = m v = g g = p water * g (g-f).