Percent Seeking High School Electromagnetism Induction

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1) Motion is a kind of selling property of an object, and the motion of an object does not require force to maintain a deficit state.

2) The law states that any object has inertia.

3) Objects that are not subject to force do not exist. Newton's first law cannot be directly verified experimentally. But it is based on a large number of experimental phenomena and is discovered through the logical reasoning of the mind.

It tells people about another new way to study physical problems: by observing a large number of experimental phenomena and using human logical thinking, we can find the laws of things from a large number of phenomena.

4) Newton's first law is the basis of Newton's second law, and it cannot simply be regarded as a special case when Newton's second law is not subject to external forces, Newton's first law qualitatively gives the relationship between force and motion, and Newton's second law quantitatively gives the relationship between force and motion.

2.Inertia: The property of an object to remain in a state of uniform linear motion or at rest.

1) Inertia is an inherent property of an object, that is, all objects have pin source inertia, which has nothing to do with the force and motion state of the object. Therefore, one can only "exploit" inertia and cannot "overcome" it. (2) Mass is a measure of the magnitude of an object's inertia.

3.Newton's second law: The acceleration of an object is proportional to the net force of the external force and inversely to the mass of the object.

Although this problem can be analyzed with high school knowledge, calculus must be used for quantitative calculation.

When the electric bond k is dialed to a, there is an electric current in the conductor rod, and the ampere force is upward, and the conductor rod (resistance r) pq can just be stationary, indicating that the ampere force is balanced with gravity, mg = b*[e r]*l

When K is dialed to B, the conductor rod is reduced by gravity due to the lack of current, and once the conductor rod moves, it will generate induced electromotive force. An induced current is generated, and with the current, there is ampere.

Suppose the velocity of the conductor rod at any time is V, the current is I, and BLV=IR

mg-bil=ma=mdv/dt

perform calculus calculations;

b2l2v-mgr]dt=mrdv

dv/[mgr-b2l2v]=dt/mr

dv/[mgr-b2l2v]=∫dt/mr

in[mgr-b2l2v]-in[mgr-b2l2*0]=[b2l2/mr]dt

Thus the velocity of the conductor rod at any time is obtained;

v = [mr b2l2] [b2l2t mr power of 1-e].

The displacement of the conductor rod at any time is obtained;

S= VDT=[MR B2L2][B2L2T to the power of T-[MR B2L2]E].

Due to the incomplete data of the question, it cannot be calculated.

Who says integrals are used for quantitative calculations? In fact, this question is a test of deformation skills.

When dialing to A, there is.

bil=mg ①

And i=e r, so bel r=mg, deformed to mgr l=be(*) etc. will be used).

When dialed to B, the conductor rod is done, and the acceleration is gradually reduced, and finally the speed is constant, the speed is the maximum, and the sweeping area within 1s is also the largest. At maximum speed, there is.

bi'l=mg ②

i'r=e' ③e'It is an induced electromotive force.

e'=blv ④

, v=mgr (b 2*l 2) substituting (*) into v=e bl and the swept area within 1s δs=δx*l δt=vl=e b is just e, b is known, and δs=square meters.

When the electric bond K is dialed to A, the conductor rod (resistance R) Pq can just be stationary.

mg = bel/r

When K is dialed to B, the conductor rod PQ does a variable acceleration motion, so the area swept by the uniform motion is the largest.

mg=bil

where i=e r=blv r

So. mg=(bl)^2v/r

v=mgr (bl) 2 can be obtained

Maximum area. s=vtl=mgr/(b)^2l

s=u/t=

Finally, there is a constant velocity of the electromotive force generated by cutting the magnetic inductance line is v at which point the velocity is maximum.

The maximum area of u=ts can be calculated.

The main point is that the motion of electrons is counted as one piece, Ohm's law is counted as one piece, and then the electromagnetic magnetic field force is counted as one piece.

Electron motion is usually mixed with magnetic field forces to make big problems, and then use analytic geometry to calculate trajectories and so on, remember those electromagnetic force formulas and centripetal force formulas, and the left and right hands are responsible.

Ohm's law generally doesn't have any questions that are too in-depth, so I ask how to lower the resistance and then change the meter, etc., just be careful, but it's really not algebraic.

One of the more troublesome aspects of electromagnetism is that the left and right hands should not be confused, one computing power and one calculation direction.

The rest of the mess is rote memorization, and that's it.

It's not too difficult to learn electricity in high school, the point is to find the feeling.

Voltage, resistance, resistivity, electric heat, electric power, thermal power, pure resistance circuit, impure resistance circuit, electromotive force, internal voltage, road-end voltage, internal resistance, magnetic field, magnetic induction intensity, ampere force, Lorentz force, magnetic inductance line, etc.

The notes on the teacher's blackboard are the best summary;

Mechanics, electricity, and electromagnetism are all important in physics;

The difficulty is the knowledge that requires balance;

I'm a college entrance examination student in '09, and I think the physics light back formula is useless, the key is to understand the process, how it came about, and if you don't understand it, you don't know when to use it.

My teacher said that physics is a difficult subject, and it is necessary to do some simple problems, find confidence from simple topics, and tap interest from self-confidence, interest is the best teacher.

I wish you a speedy breakthrough in physics.

The knowledge points involved in the general college entrance examination questions.

1.Celestial movements.

2.Kinematics.

3.Conservation of energy.

4.Electromagnetism.

5.Momentum is conserved.

I think the more difficult ones to learn are the electrical experiments, as well as the conservation of energy, the magnetic field is easier to learn, the movement of celestial bodies is easier, and the formula is OK to remember.

Electromagnetism formula.

2.Electric field strength: e=f q

3.Point charge electric field strength: e=kq r

4.Uniform electric field: e=u d

5.Electric potential energy: e = q

6.Potential difference: u

7.Work done by electrostatic force: w = qu

8.Capacitance definition: c=q u

9.Capacitance: c = s 4 kd

10.The motion of charged particles in a uniform electric field.

11.Accelerated uniform electric field: 1 2*mv = quv = 2 qu m

12.Deflection of uniform intensity electric field:

14.Vertical acceleration: a=qu md

15.Vertical displacement: y=1 2*at =1 2*(qu md)*(x v).

16.Deflection angle: =v v =qux md(v) 17Micro current: i = nesv

18.Non-electrostatic work of power supply: w= q

19.Ohm's law: i = u r

20.Series circuits.

21.Current: i = i = i =

22.Voltage: u = u +u +u +23Parallel circuits.

24.Voltage: u = u = u =

25.Current: i = i + i + i +

26.Resistors in series: r = r + r + r +

27.Resistors in parallel: 1 r = 1 r + 1 r + 1 r +28Joule's law: Q=i RT

p=i² r

p=u² /r

29.Electrical power: w=uit

30.Electric work: p=ui

31.Law of resistance: r = l s

32.Ohm's law for all circuits: =i(r+r).

U outside + U inside.

33.Ampere: f=ilbsin

34.Magnetic flux: =bs

35.Electromagnetic induction.

36.Induced electromotive force: e=nδ t

37.Wire cutting magnetic inductance line: δs=lvδt

e=blv*sinθ

38.Induced electromotive force: e=lδi δt

Commonly used formulas in electromagnetism.

Electric field strength: e=f q

Point charge electric field strength: e=kq r

Uniform electric field: e=u d

Electric potential energy: e

q Potential difference: u

Work done by electrostatic force: w = qu

Capacitance definition: c=q u

Capacitance: c = s 4 kd

The motion of charged particles in a uniform electric field.

Accelerated uniform electric field: 1 2*mv = quv

2 qu m deflection uniform electric field:

Vertical acceleration: a=qu md

Vertical displacement: y=1 2*at

1/2*(qu/md)*(x/v₀)²

Deflection angle: =v v =qux md(v) micro-current: i=nesv

Non-electrostatic work of power supply: w= q

Ohm's law: i = u r

Series circuits. Current: i

i = i voltage: u = u

U +U parallel circuit. Voltage: u = u = u =

Current: i = i + i + i +

Resistance in series: r

r₁+r₂+r₃+

Resistors in parallel: 1 r

1/r₁+1/r₂+1/r₃+

Joule's law: q=i

rtp=i²rp=u²

r electric power: w = uit

Electric work: p=ui

Law of resistance: r = l s

Ohm's law for all circuits: =i(r+r).

U outside + U inside.

Ampere: f=ilbsin

Magnetic flux: =bs

Electromagnetic induction. Induced electromotive force: e=nδ t

Wire cutting magnetic inductance line: δs=lvδt

e=blv*sinθ

Induced electromotive force: e=lδi δt