The network ID with the IP address 129 11 35 49 27 is , and the address range of the available host

Updated on technology 2024-02-09
8 answers
  1. Anonymous users2024-02-05

    Hello! I am very honored to have the opportunity to ask your questions.

    2 5 = 32, 49 is between 32 and 64, so:

    The network ID is:

    Because the size of the block above is determined, 32 and 32 is the subnet number is not a valid host IP from 33, 64 is the next subnet number, and its previous bit is the broadcast number of the previous subnet, so it can't be used so the end IP is 62, so:

    The available host ID ranges are:

    If I am able to help you, please consider it as appropriate. Thank you! Good luck :-)

  2. Anonymous users2024-02-04

    The network ID is the first 27 bits to be a subnet.

    That is, the network number.

    The first three are eight digits, so the first three are 24 digits, plus the last three digits take apart the 49 amp binary.

    Take the first three digits as 1 and the last five digits as 0 for the network ID and calculate it yourself.

    The range is 49, the first three digits are the network, and the last five digits are 00000---11111

    Exclude all 0s and all 1s are ranges.

  3. Anonymous users2024-02-03

    Subnet mask. du:192 translates to binary zhi11000000

    Subnet Mask (Binary):

    Number of host DAOs: 2 to the 6th power = 64 - 2 = 62.

    The first 26 bits are the network ID, and the last 6 bits are the host ID.

  4. Anonymous users2024-02-02

    Answer]: In the IP address with a length of 32 bits, the first 26 bits are the network front branch extension, and the last 6 bits are the host number, so the number of host addresses included in Baozhou is 26 -2=62, and the host address range is obviously not part of this network book Qingluo.

  5. Anonymous users2024-02-01

    Answer]: It means that in the 32-bit state length IP address, the first 26 bits are the network prefix, and the last 6 bits are the host number, so the number of host addresses included is 26 -2=62, and the host address range is Zhifeng, which obviously does not belong to this network.

  6. Anonymous users2024-01-31

    Answer]: CIP address block, the network bits account for 26 bits, and the host bits account for 6 bits, so the number of IP addresses included is 2 6 = 64, and the number of available IP addresses (the number of host geoscale bridge addresses) is 2 6-2 = 62. The address block represents the range 000000— 111111(.

    Pay attention to the IP'The number of addresses is different from the number of hosts, and in general, the number of IP addresses includes the network address and the broadcast address. The host address (available host address) does not include the network address and the broadcast address.

  7. Anonymous users2024-01-30

    Answer]: In the IP address that represents the length of 32 bits, the first 26 bits are the network prefix, and the last 6 bits are the host number, and the number of host addresses contained in the difference is 26-2=62, and the host address range is, which obviously does not belong to this network.

  8. Anonymous users2024-01-29

    Late Answer] :d

    It means that in the 32-bit length IP address, the first 26 bits are the network prefix, and the last 6 bits are the hidden and Li host numbers, so the number of host addresses included is 26-2=62, and the host address range is, which obviously does not belong to this network.

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