How to revise math and will soon graduate from primary school 20

2. Comprehension skills.

Mathematics is a science, comprehension is very important, without comprehension, your mathematics and all science will be difficult to learn. The development of comprehension skills is difficult, and you have to try to understand some philosophical theories and relatively abstract mathematical models that are difficult for you. The simplest training is also very difficult, and it is necessary to see that the auxiliary line can reflect its approach in less than 1 minute for a moderately difficult problem.

Secondly, we should not only understand the problems taught by the teacher, but also figure out the specific mental process of the teacher when doing the problems, which is the basic ability of why many people learn mathematics well.

3. Diligence I have seen many students who work hard but still can't study science. The frustrating thing about the math test is that it is easy to pass as long as you study carefully according to the teacher's requirements, but if you want to score 145 points, it is far from enough to rely on the teacher's practice. Even for poor students, there are still easy ways to learn.

Only by mastering the right methods can you be diligent and rewarding.

4. Method 1) Geometry.

Geometry learning is the most skilled for students at this stage, and I will introduce the tips for learning (solving) geometry problems.

1. Note-taking: In geometry class, students should not only learn to take notes and copy board books, but most importantly, they should sort out the basic graphics involved in the teacher's lecture after class. What is a basic shape? The basic shape is similar to the common guide line addition method mentioned by the teacher when we were doing geometry, except that the basic shape is the whole shape after adding the common guide line.

How do you filter the basic figures? In fact, it is very simple, combine the day's homework to sort out, screen, find out the similar auxiliary line addition method, or the similar solution method used, and organize it into the properties of the basic graph, that is, there are all the conditions and proof methods that can be proved by the basic graph. It's a long-term process, but it will keep you organized, correct and efficient in solving geometry problems after memorizing basic shapes and their properties.

2. Steps to solve the problem.

First, read the problem and represent the known conditions on a geometric diagram (preferably on scratch paper), and secondly, when doing the proof problem, represent the known conditions and the verification conditions on another diagram. At this time, when the problem is relatively simple, you can solve the problem directly to save time. However, if the problem is relatively complex and you can't think of it in 10 minutes, try to combine the two diagrams you have drawn, and try to connect the conditions between the two diagrams by auxiliary lines until the auxiliary lines are enough to prove it.

Choose the right method when doing evaluation problems. In order to find the area, we should try to use the properties of the basic graph or directly combine it with the known data by means of similar figures, congruence, translation, rotation, etc., and calculate all the conditions that can be directly or indirectly proved as much as possible, and then add appropriate auxiliary lines. The cultivation of this ability requires a large number of proof questions as a foundation to solve it easily.

Good luck. Welcome, thank you.

If more than 90 percent of the questions that can be corrected, you can read the 550 questions carefully several times, and strive to get them right, for example, if you are average in the application problem, or the geometry is not very good, do a few more questions. If you don't know how to do it at all, forget it, take as much as you can. The most important thing is that there is a lot of calculation in the primary school exam, and it is necessary to build confidence in your own numeracy ability before the exam.

It's best to sleep well before the exam, don't be careless, and don't get the right questions wrong.

First of all, review the knowledge points that have been learned, systematically summarize the knowledge points, and sort out and classify them. Secondly, do more practice questions for your weak links to strengthen your memory. Finally, it's a good idea to prepare a notebook to check for missing outs!

1:2 and two-thirds.

2:3 fountain pen yuan, ballpoint pen yuan.

The most important thing is formulas and theories. Of course, some multiplication rules need to be memorized. Be proficient in addition and subtraction calculations.

Read more textbooks and memorize more classic questions.

Memorize mathematical formulas and theorems, and learn all the problems in the classroom.

Let the red ball be x and the white ball be y, the first time you add the red ball you will be a and the second time you will add the white ball (a+80).

x:y=19:13 i.e. 13x-19y=0 (1)x+a):

y=5:3 i.e. 3x-5y+3a=0 (2)x+a):(y+a+80)=13:

11 is 11x-13y-2a=1040 (3).

2)*2+(3)*2 to get 39x-49y=3120 (4)4)Closed return height-(1)*3 to get 8y=3120 So y=390 The equation of the vertical car ruler can be found x=570, y=390, a=80, and the original white balls in the bag are 390.

There are 430 more girls than boys.

Specific steps: If there are x boys and y girls, then x y=518

1 25 x x) y 3 = 518 8 = 526 From the above two equations, we can calculate :

x=275y=243

So it turns out that there are more boys than girls = x-y = 275-243 = 32, remember to give me extra points!!

Suppose there are x males and (518-x) females.

x(1+25%)+515-x)=526

x=44 so 44 for boys and 474 for girls.

But there is a problem with this question, the number of boys has increased by 25 percent, so the total number has increased by 8, so it is impossible for there to be more boys than girls.

1.The title is that these children drew and divided 238 chocolates, 306 fast toffee... So.. The number of children is the common divisor of 238 and 306 (don't say you haven't heard of what is called the common divisor.) Since 238 = 2 * 7 * 17

So there can be 17, 34 children... Originally, there was a common divisor of 2... But if there are 2 children left, there should be no chocolate, there is 1 piece of toffee. ）

2.Except that both ends and both sides do not move... What are the 2 sides of this sentence?

Solution: A sugar 240-2 = 238 pieces B sugar 313-7 = 306 pieces 238 and 306 The greatest common divisor is 34 34 is the number of people who divide sugars.

Two, 31 times 4 = 124

124-4 = 120 meters.

The common multiple of 4 and 6 is 12 120 divided by 12 = 10 sides The last side does not move, and there are 10-1 = 9 sides that need to be moved.

-2 = 238 313-7 = 306 The greatest common factor between 238 and 306: 2*17=34

A: ...2. (31-1)*4=120 (m) 120 6+1=21 (surface) The least common multiple of 4 and 6: 2*2*3=12 120 12=10 (surface) 21-10-1=10 (surface).

A: ...

1.Find the greatest common divisor of 240-2 = 238 and 313-7 = 306, which is 34Because the most requested, look for the biggest.

and 6 The least common multiple is 12, which means that the flags at both ends of every 12 meters do not need to be moved, and the middle two sides must be moved. 4*30 12*2=20 faces.

Set gold x grams, silver (770-x) grams.

This results in Eq. 18 19x+9 10(770-x)=720

Do the math yourself.

It's a little simpler.

Set gold x grams, silver (770-x) grams.

x*1/19+（770-x）*1/10=770-720x=570

That is, 570 grams of gold, 770-570 grams of silver = 200 grams.

Set gold x grams, silver y grams, according to the title: x + y = 770

18/19*x+9/10*y=720

solution, get, x=570, y=200

That is, this alloy contains 570 grams of gold and 200 grams of silver.

You'd better do it yourself, or it won't be of much use to you.