High School Chemistry, Reaction Quality Problems, A High School Chemical Reaction Problem

It can be calculated based on valency, or conservation of electrons. The amount of electronic species required to reduce the ag mixture is 2 * 2 * 50 1000mol =. So the amount of hydrogen substances corresponding to b g is.

Because the total amount of hydrogen ions in sulfuric acid is mol, and the hydrogen gas reacting with the mixture is equivalent to the hydrogen ions in the solution, that is, the hydrogen gas reacting with the mixture is mol, then the total amount of oxygen atoms in the mixture is mol, mass, so the solid mass after cooling is (. The 2ag mixture is.

Fe2O3 + 6H + = 2Fe 3+ +3H2Cuo + 2H + = Cu 2+ +H2OFrom the above two chemical equations, it is observed that one oxygen ion consumes two hydrogen ions;

The hydrogen ions that can be supplied by sulfuric acid: n(h +) = 2 x 2 mol l x l = mol, indicating that a g The mixture of iron oxide and copper oxide exactly contains mol o 2-, m(o 2-) = mol x 16 g mol = g.

Therefore, it can be known that the mixture of iron oxide and copper oxide A g contains iron and copper elemental co-(, then it can be known that the mixture of iron oxide and copper oxide b g contains iron and copper elemental co-b ( g.

Answer: The mass of the solid after cooling is b( g.

Phenol + CO3 (2-)-phenol ion + HCO3 (-).

Therefore, sodium phenol + CO2 + H2O cannot form positive salts, which is determined by the strength of acidity.

The mechanism is not clear, and it can be regarded as either electrophilic substitution or nucleophilic substitution.

If it is regarded as an electrophilic substitution, it is under the action of acid, the O of acetone obtains an H+, which makes the CO double bond open to form a carbocation (CH3)2C(OH)+. Carbocation is added at the paraposition of phenol to form a molecule of (CH3)2C(OH)-C6H4OH. Then hydroxyl O gives another H+, which is detached into water to form a new carbocation (CH3)2C(C6H4OH)+, which is added in the paraposition of another phenol, and finally (CH3)2C(C6H4OH)2.

If it is regarded as nucleophilic substitution, it is that after the phenolic hydroxyl group ionizes out of H+, the negative charge on O is transferred to the benzene ring paraposition, and the carbonyl group of acetone is nucleophilic addition to form (CH3)2C(OH)-C6H4OH. Later, another phenol also forms a para-negative charge, which performs nucleophilic substitution on the product just now, displacing the hydroxyl group to form (CH3)2C(C6H4OH)2

It is also possible to substitute the alcohol hydroxyl group for a second phenol para-hydrogen atom.

A one-time addition is impossible, and the unsaturation is not satisfied.

Is ammonia gas introduced into the aluminium salt solution?

The ionic reaction equation is: Al3++3NH3+3H2O=3NH4++AL(OH)3

The aluminum hydroxide precipitate cannot be dissolved in ammonia (ammonia is a weak alkali), so the white precipitate of excessive ammonia is insoluble.

AlCl3 +3NH3+3H2O = AL(OH)3 precipitation symbol +3NH4CL

Aluminum hydroxide and ammonium chloride are produced with aluminium chloride and ammonia gas and water.

nh3+h20=nh4oh

AlCl3 + 3NH4OH = 3NH4Cl + AL(OH)3 Al(OH)3 cannot be dissolved in ammonia, so it doesn't matter if there is too much, it can also be assembled into an ALC3 +3NH3+3H2O=AL(OH)3 precipitation symbol +3NH4Cl

Select DA: silver chloride: agCl + 2NH3·H2O = AG(NH3)2Cl + 2H2O

B: Copper hydroxide: Cu(OH)2+4NH3·H2O=Cu(NH3)4(OH)2+4H2O

C: Silver hydroxide: agoh+2NH3·H2O=AG(NH3)2OH+2H2O

So it's all dissolved.

And d: iron and ammonia cannot form complexes, so they are insoluble.

In a chemical reaction, when there is no external energy added, a principle is observed: from active to inactive, unstable to stable.

Fe(Oh)3 is insoluble in water and is a precipitate, which means that Fe(Oh)3 is more stable and less active in water than Fe(NH3)6 2(SO4)3, and it is not easy to participate in chemical reactions again.

Both form complexes (which we have also learned here).

Excuse me, I don't know how to draw that benzene picture, so I'll say in Chinese, okay?

1) p-aminophenol.

Substitution reaction, nitro group becomes amino group.

2) Benzene + chlorine gas to generate monochlorobenzene, which replaces the reaction.

Monochlorobenzene + nitric acid to produce p-chloronitrobenzene, substitution reaction.

p-chloronitrobenzene undergoes hydrolysis under alkaline conditions to form p-nitrophenol, and the hydrolysis reaction (substitution reaction) p-aminophenol + glacial acetic acid forms the final product, substitution reaction.

If there is a mistake, the watchtower owner will give a correction, thank you.

Question 1: Mixture: air, salt water,

Pure: Oxygen.

Potassium hydroxide. Copper.

Sodium bicarbonate. Cane sugar.

Alcohol. Elemental: oxygen, copper.

Compound: Potassium hydroxide.

Sodium bicarbonate. Cane sugar.

Alcohol. Inorganic: potassium hydroxide.

Sodium bicarbonate. Alkali: potassium hydroxide.

Salt: sodium bicarbonate.

Organics: Sucrose.

Alcohol. Belonging to the electrolytes are: potassium hydroxide.

Sodium bicarbonate. Non-electrolytes are: sucrose.

Alcohol. Question 2:

Among the reactions listed above, the one that belongs to the chemical reaction is: 5, the one that belongs to the decomposition reaction is 2, the one that belongs to the displacement reaction: 3, and the one that belongs to the metathesis reaction: 1

The redox reactions are:3,4

1: Non-metallic compounds that can ionize H+ ions (some acids cannot ionize H+ but it contains H+, such as CH3COOH), the isotropy of acids is that they can react with alkali to form salts and water, and can react with metals. Acids are divided into strong and weak acids according to their acidity, and are divided into monobasic acids, dibasic acids, and polyacids according to the number of hydrogen ions.

According to whether it contains oxygen or not, it is divided into oxygenated acid and non-oxygenated acid.

2: Compounds containing hydroxide ions (a misconception is that NH3 is a base, in fact, it is not a base, its hydrate is ammonia is a base, and some people say that there is no hydroxide ion in ammonia, in fact, ammonia water will dissociate OH-ions after electrolysis), the general property of alkali is that it can react with acidic substances to form salt and water. Bases are divided into monobasic, dibasic and polybasic bases according to the number of oh-.

3: A substance composed of acid ions and metal ions is a salt.

For example, Na2CO3, Na is a metal ion.

CO3 is an acid ion.

(However, the special case of salt is the substance with ammonium, and in salt ammonium ions are regarded as metal ions, but they are only regarded as metallic ions, but they are not!) )

Salt is determined by chemical composition and has no general properties.

Salt is divided into: normal salt.

The product of complete neutralization of acid and alkali.

Metals, acids.

A certain "certain acid".

naclmg(no3)2

The product in which the hydrogen ions in the acid hydrochloric acid are partially neutralized.

Metal, H, acid root "a certain acid hydrogen so-and-so".

Acid type a certain acid so".

nahco3

nah2po4

A product in which hydroxide ions are partially neutralized in a basic saline.

Metals, OH, acids.

Basic acid some.

cu2(oh)2co3

4: Compounds containing two or more elements, and the compounds of aerobic elements (oh- are not counted), oxides are divided into metal oxides and non-metal oxides, and are divided into acidic oxides, basic oxides and amphoteric oxides according to their properties.

5: It can react with alkali, react with water to form corresponding acid, and react with alkaline oxide.

6: It can react with acids and is composed of metals and oxygen.

It reacts with acids to form salts and water, and oxides from more reactive metals are more likely to form alkalis with water.

1.The purpose of washing is to get out some soluble salts. (I personally think it should be washed with hydrochloric acid) 2Extraction, dispensing. Separate funnels.

3agno3+no+2h2o

4.Add the starch solution to the NAI first, and the solution will not change blue. Then add some strong oxidants, such as: FeCl3, Cl2, etc., and the solution turns blue. The presence of i-ions is indicated.

If the number of molecules is B, then the quantity of the substance is B NA, so the molar mass is Ana B, and the quantity of the substance of CG gas is BC ANA, so the volume is BC ANA VM

Na=A, B=C, (definition of Avogadro's constant) (d is the number of molecules of the gas c), so D=BC A, and in the same case, V of the gas is proportional to N, so Vc=BC A*Na*A=AC