Rabbit problem of classical algorithm problem, solving, logical problem of ten rabbits

Think of it this way: after the first month, that is, in the second month, one pair of rabbits becomes two pairs of rabbits, one of which is itself, and the other pair is the young rabbits it gave birth to In the third month, two pairs of rabbits become three pairs, one of which is the first pair, the other pair is the young rabbit it has just born, and the third pair is the big rabbit that the young rabbit has grown into In the fourth month, three pairs of rabbits become five pairs, and in the fifth month, five pairs of rabbits become eight pairs... This set of numbers starts with three numbers, each of which is the sum of two numbers, and in this way, the sixth month is 13 pairs of rabbits, and the seventh month is 21 pairs of rabbits......, Pebonacci gets a sequence, and people add a 1 to this sequence to become the "Pebonacci sequence", i.e.: 1, 1, 2, 3, 5, 8, 13, etcThe sequence is represented by an and has a1=a2=1, a(n+1)=an=a(n-1) (n 2).

The general formula is: (1 5)*.

The Fibonacci sequence also implies a number of interesting numerical patterns, such as multiples of 2 every two starting from the 3rd number, 3 multiples of 3 from the 4th number, and multiples of 5 every 4 from the 5th number, ......In addition, the most harmonious beauty of this sequence is that the further you go, the ratio of the adjacent terms will infinitely tend to the ratio of **, i.e., [5 (1 2)-1] 2.

It's very simple, but the process is a bit difficult to write.

Fibonacci numbers can be achieved with a recursive algorithm, and I personally think that this problem has some loopholes (rabbits are not divided into male and female, can rabbits be born).

Hypothetical Method:

1) Suppose it's all chickens: 2 35 = 70 (only).

Chicken feet are less than the total number of feet: 94 70 = 24 (pcs).

The number of feet that rabbits have more than chickens: 4-2=2 (only).

Number of rabbits: 24 2=12 (only).

Number of chickens: 35 12 = 23 (chickens).

2) Suppose all rabbits: 4 35 = 140 (only) more rabbit feet than the total number: 140-94 = 46 (only).

The number of feet that rabbits have more than chickens: 4-2=2 (only).

Number of chickens: 46 2 = 23 (chickens).

Number of rabbits: 35-23 = 12 (only).

The dog chased 250 paces and caught up with 70 paces.

250 70) * 30 = 107 steps.

3 Rabbits are killers 10 Rabbits are masterminds.

54 + 8 = 64 (pcs) is slow.

64 divided by 2 = 32 (pcs).

32—8=24 (pcs).

Answer: The white rabbit picked 32 mushrooms and the gray rabbit picked 24 mushrooms.