Classical Physics Problem Buoyancy 25

I don't know if you're floating in the water, floating in the water, or floating on the surface?

If it floats in water, the volume of ice and water of the same mass should be greater than the volume of water, so the surface of the water should be lowered after the ice melts into water.

If it is only floating on the surface of the water, then the volume of the water should only be a part of the ice that sinks in the water, so when the ice is all melted, the volume of the water should increase, that is, the water surface should rise!

1.No change: If the temperature does not change.

2.Decrease: The temperature rises by no more than 4 degrees.

3.Elevation: The temperature rises too quickly by more than 4 degrees.

It can be illustrated according to the formula.

First of all, the density of water * g * the volume of ice under water = the mass of ice * g that is, the density of water * the volume of ice under water = the mass of ice - (1) and then when the ice melts into water, according to.

Mass of ice = density of water * volume after turning into water --2) Comparison of (1) and (2).

Found the volume after turning into water = the volume of ice under water.

PS: The input method is not good at typing Greek letters, it can only be expressed in Chinese like this.

If you cut off the part of the ice on the surface of the water, break it up into molecules, and fill it in the gap between the molecules of the ice below the surface, then the ice below becomes water.

Got it?

The water surface drops because ice is less dense than water.

If there is a material in the middle of the ice that is denser than water, it will sink last, and if there is a substance that is less dense than water or pure ice, the water surface will not change.

First of all, ice is less dense than water, it floats on the surface of the water, and the mass of the volume of water it discharges is equal to the mass of this piece of ice, so the volume of ice after melting is the volume of water it discharges, and the height of the water surface does not change.

The volume of the iron block is 200

cm, if it is completely submerged in water, the buoyancy is equal to the buoyancy if it is immersed in water by 4 5 volumes, and the buoyancy is equal to the buoyancy it receives if it is immersed in alcohol by 3 5 volumes.

The volume of the ball should be minus 3 cubic meters, i.e. is.

1) The buoyancy of the wood pellet submerged in water.

f float = water v discharge g = 1000kg m3

2) The pull force of the fine wire on the wooden balls.

The wood ball is subjected to a downward gravitational force g, a downward pull force f pull, and an upward buoyancy f float.

the relationship between the three forces; g + f pull = f float.

Pull force f pull = f float g =

3) Cut the thin line, when the wooden ball is at rest, when the volume of the wooden ball above the water surface floats, the buoyancy is equal to the gravity, f float = g=

f float = water v drain g

Volume v row of wood pellets immersed in water.

v row = f float ( water g) ==

The volume of the wood ball outcrops from the water.

v dew = v v row ==

400cm3

The buoyancy of the airship is the gravitational force on which it expells the air, and the air density is generally 43,000*.

If the weight is 15t, then the remaining load capacity is 43000*.

Using Archimedes' law of buoyancy, f float = pvg =

15t= g=

g goods = f float - g

Pull = Gravity - Buoyancy.

Gravity looks at density.

Buoyancy is related to volume.

You write down the force equation for the 3 balls and compare them in pairs.

The tensile force is equal to the gravitational force minus the buoyant force, f pull = g - f float = v copper (p ball copper - p water) = v iron (p ball iron - p water).