I would like to ask about the problem of base system conversion, and the question of base system con

Updated on technology 2024-02-09
9 answers
  1. Anonymous users2024-02-05

    01278050 to 00159786 that process is wrong, it should be 00158755, you can try it.

  2. Anonymous users2024-02-04

    After re-analysis, we found that the base system of 7 is the base system that satisfies the pieces of the Wisdom Mind.

    Basebase: 2 4 = 8 (decimal).

    But in the decimal system, 8 (decimal) is represented as 11, which is eligible.

    Next, we calculate the drawback 5 16 (base hepta):

    5 (basebase) = 5 (decimal) rent Biman.

    16 (decimal) = 1 7 1 + 6 7 0 = 7 + 6 = 13 (decimal).

    Multiply two decimal numbers by :

    5 13 = 65 (decimal).

    Convert 65 (decimal) to 7 decimal :

    The quotient is 1 and there is no remainder.

    So 65 (decimal) = 122 (decimal).

    So, according to this algorithm, 5 16 (base hexagram) = 122 (base hexabyte). From the options given, option C is the correct answer.

  3. Anonymous users2024-02-03

    The "base" in the title refers to the base number of a number, assuming that the base number is n. According to the conditions in the mountain model problem, an equation can be listed:

    2n+4 = n+1

    Simplify the equation:

    n = 3 Therefore, the operation in the problem is an operation in the base 3 system. Let's take a look at the 5x16 result using a known algorithm.

    First, 5 and 16 are represented as numbers in the base 3:

    5 (decimal) = 12 (ternary).

    16 (decimal) = 121 (ternary).

    Then follow the algorithm in 3 and multiply 122 and 121 by :

    x121 Therefore, the result of 5x16 is converted to 15 after the decimal Li Wei grasps.

  4. Anonymous users2024-02-02

    <> as shown in the figure, this is right, yes, this is to convert the hexadecimal directly to the floating-point number, which is caused by some precision error, because the conversion of floating-point number to hexadecimal is itself caused by error.

    Hope...

  5. Anonymous users2024-02-01

    2 decimal to :

    1101 = 1 2 to the 3rd power + 1 2 to the 2nd power + 0 2 to the 1st power + 1 2 to the 0 power.

    Decimal to 2: 13 is also used

    Click on ** to see) respectful chain.

    8decimal to decimal 10:

    123 = 1 8 to the 2nd power + 2 8 to the 1st power + 3 * 8 to the 0th power of the macro call.

    Decimal to 8:

    Also use (click on ** to see) bright base.

    16decimal to 10:

    12b = 1 16 to the 2nd power + 2 16 to the 1st power + 11*16 to the 0th power.

    10 to 16: 299 is also used

  6. Anonymous users2024-01-31

    A method of converting decimal integers to binary.

    The decimal to binary method.

    Remember.

  7. Anonymous users2024-01-30

    Bit weight refers to the unit value corresponding to each fixed position in the carry system.

    Chinese name. Base conversion.

    Fundamentals. Basic explanation.

    The method of counting by people using symbols.

    Radix. The number of digits used in the carry counting system.

    For example, a binary number 111 (note that the value is not equal to 111 in the decimal system above) ends with 1, which means that it must be ......+1, the preceding ellipsis part is a multiple of 2. So a binary number has 1 at the end, which means that its corresponding decimal number divided by 2 must be 1. Therefore, the remainder after the first division by 2 should be placed in the last digit of binary "one bit", which means that the sign on one bit is 1.

    2) If a decimal number 321 "ten" is 2, we want to convert it to (1) case. So let's erase the end of this decimal number, that is, subtract the 1 on the "single digit" and divide it by the base 10 to get 32. In this way, the "2" on the original "ten" fell to the "single".

    Then 32 is processed as (1).

    Thanks thanks.

  8. Anonymous users2024-01-29

    Conversion to binary is.

    Generally, there are many integer base conversions, and decimal numbers are not commonly used.

  9. Anonymous users2024-01-28

    Convert to binary.

    First, the integer part 2 takes the remainder.

    The decimal part *2 is rounded as an integer.

    Start the cycle here to the bottom.

    This is where the cycle begins.

    So the binary number is.

    All we need is binary.

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