The area of the regular polygon is 240 square centimeters, the circumference is 60 centimeters, and

Answer: 8cm

The polygon can be divided into n isosceles triangles.

Let the height be h, then there is 1 2*60 n*h=240 n, and the solution h=8 is the result.

Suppose the number of sides is n, s=240=n*s (for a triangle with 60 n as the bottom edge) 240=n*1/2*60 n*height (60 n bottom side length) The sum of the outer angles of the polygon = 360 degrees, an outer angle = 360 n, the inner angle is 180 degrees-360 n, and then the inner angle is divided by 2, why divide by 2, because it is a triangle, it is better to draw a diagram if you don't understand.

finishing high = tan (90-180 n) * (60 n 2) last 240 = ....Wrong, it turned out to be seeking height, so the answer is.

tan (90-180 n) * (60 n2) halo. I think too much

Let the side length of n regular polygon a=60 n and the centroid distance of the side be h, then the area s=n*1 2*a*h=n*1 2*60 n*h=30h=240

h=80

Connecting each side to the center of the circle gives a congruent n isosceles triangle (assuming it is a regular n-sided shape with an edge length a), then the "centroid h" is the height of each triangle. s(regular polygon) = n*s (isosceles triangle) = n*(h*a 2) = h*(n*a) 2=h*the circumference of the regular polygon 2=240, resulting in h=8cm

The area of a regular polygon s (1 2)*r*a*n

where r--- radius of the inner segment of the Kaiche circle, which is also the opening of the regular polygon, the early call distance;

a--- the side length of a regular polygon;

n--- number of sides of a regular polygon.

Because, an=regular polygon perimeter, known as an 60, s=240, r2*240 60 8

Answer: The centroid distance of the regular polygon is 8 (units of length) of its inscribed circle

Connecting the center to each apical Lu group point, the regular n-sided shape can be divided into n congruent triangles, the area = 1 trembling call 2*side heart distance * circumference, so side heart distance = 2 * s perimeter = 2 * 480 80 = 120

Because it is a positive imitation of the loss square, the area is equal to the product of the side of the god (if the side length is x, the area is x 2), so the side length is 1 cm, and the radius of the circumscribed circle is the distance from the midpoint of the square to the top corner, that is, the edge center distance of the root number is 2 times, and the side center distance is half of the side length of the bucket source. Hope, thank you

Regular quadrilateral, i.e., slow into a square.

Radius = 2, i.e. diagonal hand.

Half of the length is 2, and the side length can be 2 slag potato molds 2

The rest is fine.

Let one side be x, and the other side is (25 2x) Lu Shi 2, so [(25-2x) 2]*2=3x

Find x 5 and use 5*3=15

Therefore, the area is 15 (with shed cm2).

The centroid of a regular hexagon is 6 3, and the centroid and angular centroid and half of the side length form a triangle of 30 60 90 degrees.

If the side length is 12, the circumference of the source is 12*6=72, and the area is 6*6 3*6=216 Absolute chain 3

Let the high draft talk about the four sides of the Qi

4a=25,a=,s=

The area of a regular polygon s (1 2) times r times a times n

r is the radius of the inscribed circle, which is also the centroid distance of the regular polygon;

a is the side length of the vertical edge of the multi-century fissure;

n is the number of edge sources in the form of a regular multilateral search.

Because, an=regular polygon perimeter, known as an 60, s=240, r2x240 60 8

Answer: The centroid distance of the regular polygon is 8