A math problem to find unknowns, a math problem with 10 unknowns, to find a solution!

Let's solve this problem first!

Divide by 3 times a number, and the result is, find this number.

Solution: Let this number be x

Then we should now have a column equation of 3x=I haven't touched such a column equation:. When solving this equation, it is clear that we should first think of 3x as a number, find out how much 3x is equal to, and then find x

With this example, I guess I don't need to say that you also know which is right.

If we follow the second approach, it is clear that this is not true

The first ...

It can't be: because: the original form can be seen as:

Go to the brackets. The solution is x=

Of course, the first pair, the form of the component is clear at a glance, and it is obvious that 3x is on the denominator, so it is divided by 3, and then divided by x, which is equal to. So it turned out to be true.

The first one is correct.

The second mistake is: x=

If 3x is an abbreviation of 3 x, then it means that 3x in the original formula is, so it should be divided by x, not multiplication.

In the first pair, 3x is a whole.

Based on the question, it can be assumed that the number of apple trees is x. Then the number of pear trees is x+24.

x÷（x+24）＝3/7

Solution: 7x 3x+72

4x＝72x＝18

18+24 42 trees.

According to calculations, the number of apple trees is 18 and the number of pear trees is 42.

I don't know if there's a problem with this question, but I'm pretty sure that the minimum value of each number is definitely not 0!

When Z=-1, B=C=D=E=F=G=X=Y=0, i.e., 24A-6 A B C D E F G x Y-124A-6 A 0>-1

23a-6≥0

a≥6/23

The value of a can change with the change of z, it can be infinitely large, but it cannot be infinitely small, and the minimum of a is 0. But all other unknowns can be negative, as long as they meet the requirements of 23a+12b+12c+10d+6e+24f+12g+12x+10y+6z 0

That is, |a |≥12b+12c+10d+6e+24f+12g+12x+10y+6z）|

That's all I can think about.,I'm not going to go deeper.,I'm just more interested in mathematics.,I believe the landlord is the same.,We can discuss it when we have time in the future!

Observe the inequality, 24a+12b+12c+10d+6e+24f+12g+12x+10y+6z a b c d e f g x y z

It can be seen that the minimum value of a is b, and the minimum value of b is c....

So, when all numbers take the minimum value, all numbers are z.

So we get kz z, k>0, so z must be 0

The smallest number of them has a minimum value of 0

The other numbers must also be 0, so that a, b, c....All are 0 inequalities.

So the minimum value of all letters is 0

If the sum is s, then a is used to replace other variables, and there are 128a>=s>=a, so a>=0, that is, the minimum value of a is 0, which is obtained when all variables are 0.

If b is substituted for c, d, etc., then there is 24a+104b>=s>=a, and b>=-23a 104 can be obtained

If a is substituted for b, c is substituted for d, e, etc., then there is 36a+92c>=s>=a, and c>=-35a 92 can be obtained

If a is substituted for b and c, and d is substituted for e and f, then there are 48a+80d>=s>=a, and d>=-37a 80 can be obtained

Similar can be obtained.

e>=--57a/70,f>=-63a/64,g>=-87a/40,x>=-99a/28,y>=-111a/16,z>=-121a/6

a b c d e f g x y z, and the unknowns are all positive, when a=b=c=....=z, I think your question is still lacking, because when a=b=...=z takes any positive number, it can satisfy 24a+12b+12c+10d+6e+24f+12g+12x+10y+6z a b c d e f g x y z

The question then becomes, what is the smallest positive number? There is no solution to this problem.

Because negative and complex numbers do not hold, so:

a=b=c=d=e=f=g=x=y=z=0 because lz says unknowns! =0, so: a=b=c=d=e=f=g=x=y=z=1 given the questioner's addition, when.

a=b=c=d=e=f=g=x=y=z=infinitesimal and the above two equations still hold.

Also, the person who asked this question has a problem.

For the minimum value, the inequality is given an equal sign.

All values are taken as 0

The minimum is 0 and I am not sure.

Let's talk about it, it's all 0 Give points The reason is that if a is a positive number is not as small as 0, and if it is a negative number, the sum of the previous numbers is even smaller and does not hold.

Hello hanshuo888! This problem can be solved by extracting the common factor -ab(a b 5-ab -b).

ab²（a²b^4-ab²-1）

ab²[ab²(ab²-1)-1]

1. This title is detailed steps, I hope you will adopt it! I wish you progress in your studies and progress every day, thank you.

Chong quietly talks about analysis] Luck Fight ax2-3bx-5=0

2a-3b)x-5=0

2a-3b)x=5

2a-3b)2x=5×2

4a-6b)x=10

4a-6b=10 x===If you are satisfied, don't forget to touch it!

Because this is a quadratic function, y=ax 2-3bx-5, when y=0, it intersects the x-axis of Kai Chai, and at the two points of Sakudan, it is its root, x1,2=[3b (9b, 2+20a)], 2a. It has a minimum value at x=, and the graph is invariant regardless of x, and the total spine is invariant, and there is a ua-vb=5, you are asking 4a-6b=?So it's still equal to 5

Substituting x=2 into 4x-6b-5=0 is good to do.

Z=a+8+67 is obtained by Z-67=A+8, Z=A+75 is substituted into Z-A=5*A to obtain A+75-A=5A, (A+75-A) 5A=1 is finally calculated as A=15, and A=15 is substituted into Z-A=5Xa

Get z-15=5*15 and finally get z=90

The conclusion after the most source closure is z = 90, a = 15, I don't understand that you can ask me about the hail crack, and I explained it very clearly, thank you.

Because < it must have been exceeded.

The equation is as follows: x=90 is solved

Please select the amount of electricity payable.

Set the electricity consumption of this month m kWh.

The solution is m=90

In September, the electricity consumption is 90°, and the electricity fee is yuan.

Let the electricity consumption in September be x degrees, and there is an equation.

Solve the equation to get x=90

If the electricity is 90 kWh, the electricity fee is 60 yuan.

However, we are now in a tiered electricity price, and the excess part is more.