Heroes help, graduate school entrance examination, mathematics 2 discourages me!!!!!!

The number two is not the most difficult. There are only high numbers and line generations, and there is no probability, so the span is not large. The important values of higher numbers are double and triple fractions, surface curve integrals, Green's formula, Lagrangian median, differential equations, etc.

Line generation is correlation, non-correlation, general solution, and so on. It is recommended that you understand the basic content of the book, and then read Li Yongle's review book, understand the example questions, do the exercises yourself after class, and then repeat the real questions at least twice. Basically, it's no problem to take a 110+ graduate school entrance examination in mathematics.

Do more, practice more, think more.

It is difficult to get a high score in mathematics for the postgraduate entrance examination, so you can set a score goal according to your own situation, focus on practicing the basic questions according to the goal, and strive to do everything right in a simple way, and you can get a passing score.

Otherwise, the pressure is high, the difficulty is high, and the basic score that should be obtained cannot be obtained, and the score of passing the line will be troublesome.

gaps. I reviewed math early, because I forgot most of the knowledge, I need to consolidate the basics, and then do a lot of exercises, there is basically no problem, but if you want to get a high score, sometimes you have to work harder than others.

In this case, it is recommended that you still find a teacher to take it, so that the efficiency of review is relatively high, and now there is not much time to go to graduate school. I've been in a hurry lately, this thing, fortunately, I found one today, it's still very good, just share it with you, it's in my space, you can do it yourself. If it is useful, remember to be sure.

a+√2e|＝|a－(－2)e|0, which means that a has an eigenvalue of 2.

at a 2e, find the determinant on both sides, get |a|^2＝16，|a|＝±4。

Again|a|0, so |a|＝－4。

Because aa* |a|e 4e, so a* 4 (a inverse) a has eigenvalues 2, a inverse has 1 2, so a* has eigenvalues 4 2 2 2

Take the determinant of ata as a and the determinant of a is -4 and then add |a+√2e|=0 left multiplication a* Propose the root number 2 The eigenvalue of a* can be found to be 2 times the root number 2

Sorry, I don't use math symbols, but I'll just do it.

408 12=34 (speed points).

You now set the speed of car D to be x, and then set car D to travel Y kilometers when car A, B and C start to set off, and car C has a speed of z.

Now look for the equivalence relation:

A catches up with D in six hours, so: 40*6=x*6+y B catches up with D in nine hours, so: 36*9=x*9+y C catches up in twelve hours, so: z*12=x*12+y simple ternary equation can be solved, you need z

The Handsome Wolf Hunting team will answer for you:

Set the schoolbag into x, the purchase price is 65x yuan, sell (x-5), the sales price is 76 (x-5), 76 (x-5) = 65x + 440

76x-65x=76×5+440

11x=820

x=820 11 is not an integer solution, and there is a problem with the problem data.

Arithmetic solution: (76 5+440) (76-65) is not an integer.

76 5 means that 5 are also sold, and all of them are sold to earn 76 5 + 440, each earning 76-65, and dividing them to get the number. )

Set this batch of schoolbags into x.

76（x-5)-65x=440

76x-380-65x=440

11x=820

x=820/11

The numbers are problematic???

1.Simple. All sold out. 5x(76-65) = 55 55+440=495 A pair of profits 76-65=11 495 divided by 11 to get what you count.

2.Solution: Set a total of x double.

76（x－5）－65x＝440

1) Profit per bag = 76-65 = 11 (yuan).

2) Profit of 440 yuan, the number of school bags sold = 440 divided by 11 = 40.

3) The number of school bags purchased = 40 + 5 = 45 (only).

The profit of each is 76-65=11 yuan.

There are 440 school bags sold 11=40.

So a total of 40 + 5 = 45 were entered.

F(x)+f(y)=f(xy).

f(x)+f(x-2)=f(x(x-2)) to the right of 3=3f(2)=f(2)+f(2)+f(2)=f(4)+f(2)=f(8).

Then there's f(x(x-2)) because of the multiplier function.

There are x(x-2) <8

The solution -2 considers the defined domain, and the result is 0

<> Song closed. Lookout and crack, thank you.

x 0, the numerator and denominator tend to 0, using Lopida's rule.

The derivative of the numerator is ln2 2 x + ln3 3 x and the denominator is 1

When x 0, the limit is ln6

1. Operate in the phone: Settings - Application Manager - Swipe Screen Options (All) - Find Information - Click to enter, clear the data and try it.

I didn't understand what you were going to do. If the 130,000 yuan is not good, it will be listed in a separate schedule and regarded as overtime wages. Or performance appraisal rewards, or engage in an innovative invention, evaluation competition, etc., and send it down.

One person, up to 5,000, he will get a maximum of 20,000 in those four months, so 20 people are 400,000.

And then, the difference is 130,000...

The monthly wage of each worker is 5,000 yuan, and 20 workers are 100,000 yuan, and 4 months are 400,000 yuanKilled.

I didn't say it had to be 20 people.

That's 530000 4 2500 = 53