Senior 1 Mathematics Mathematics Please answer in detail, thank you 11 21 5 58

The first one is the center of the garden (0,0) r=2

The second (1,2) r=1

Intersection (2, 2).

x=2,y=2

(a 2 + b 2) = 2, then: a 2 + b 2 = 4 substituting the second formula, 4 + 1 + 1-2 (a + b) = 1, a + b = 5 2, and then substituting the first formula, the solution is obtained.

a=[5+ root7] 4 b=[5- root7] 4a=[5- root7] 4 b=[5+ root7] 4or.

By the formula has a 2+b 2=4

The formula is a 2+b 2-2a-4b=-4a+2b=4

a=4-2b

Substituting b1=2

b2=6/5

a1=0 a2=8/5

Equation 1 is a circle with the origin (0,0) as the center and 2 as the radius;

Equation 2 is a circle with a point (1,2) as the center and 1 as the radius;

Draw two figures in the same coordinate system

It is easy to conclude that the two intersections are (0,2) and (-1, root number 3);

So the system of equations is solved as {(a1=0,b1=2),(a2=-1,b2=root number 3)}

It's only one level.,Can't upload specific**.,But it's pretty simple.,You should understand it.,Hehe.

a+1｜= a + 3

1) Formula: a + 1 = a + 3

2) Formula: - a - 1 = a + 3

1) The informant does not agree.

So the solution is exactly 2: a = 2

a's implicit remorse is equal to -2

4< = [(1 a-b)+(1 b-c)] (a-c) (less than or equal to) [(1 a-b)+(1 b-c)] (a-c) = 2 + b-c a-b + a-b b-c

b-c a-b+a-b b-c is greater than or equal to 2 (let m=b-c, n=a-b, then both are greater than zero, m2+n2 is greater than or equal to 2mn).

If it is an answer question, it is recommended to take the first answer below. If it is a fill-in-the-blank or multiple-choice question, it is recommended to use the special case method, for example, set a=3 b=2 c=1 and substitute it for comparison.