According to whether the types and order of amino acids on the Ig peptide chain are changeable, Ig c

Variable zone (VL zone) and stable zone (Cl zone).

The sequence of the radical pure amino Changchong acid of the polypeptide chain depends on (expressly).

Correct Answer: a

The order of amino acids in polypeptide chains in protein biosynthesis depends on:

Specificity. on the anti-password.

c.Specificity of aminoacyl-tRNA synthetase.

The middle nucleotides are arranged in the order of the cisteres.

Specificity. The answer is d

Summary. Polypeptide chain is a biological macromolecule composed of a series of basic units of amino acids, which plays an important structural and functional role in proteins. The first amino acid of a polypeptide chain determines its chemical properties and sequence orientation.

The 20 common amino acids include glycine, serine, glutamic acid, aspartic acid, alanine, isoleucine, leucine, threonine, lysine, tyrosine, histidine, cysteine, proline, arginine, asparagine, valine, prolyl acid, phenylalanine, tryptophan, and butyric acid. The difference in the structure of the polypeptide chain and the change of the amino acid sequence make each polypeptide chain acquire different functions and characteristics.

Can you add, I don't quite understand it.

Polypeptide chain is a biological macromolecule composed of a series of basic units of amino acids, which plays an important structural and functional role in proteins. The first amino acid of the polypeptide chain determines its chemical properties and sequence spring spike orientation. The 20 common amino acids include glycine, serine, glutamic acid, aspartic acid, alanine, isoleucine, leucine, threonine, lysine, tyrosine, histidine, cysteine, proline, arginine, asparagine, valine, prolyl acid, phenylalanine, tryptophan, and butyric acid.

The difference in the structure of the polypeptide chain and the change of amino acid sequence make each polypeptide cavity chain acquire different functions and characteristics.

This is the structure of the peptide bond.

Amino-acapitic acid.

The correct order of the atoms that form the backbone of the shouting polypeptide chain is: -n-ca-co-. Repeat in this sequence. CO is carbonyl carbon.

Amino acids condense to form peptide bonds.

m-n pcs. You think, every two amino acids form a stool silver peptide bond, let's take a step back and think, if m amino acids form a peptide chain, then there are m-1 peptide bonds, this is the primary school Olympiad problem (100 meters, every 10 meters a telephone pole, a total of 11, here the amino acids are the wire slag coarse cherry rod, easy to understand). Then to split this hypothetical peptide chain into n, then you have to cut n-1 and subtract (n-1) peptide bonds, so there are (m-1)-(n-1)=m-n.

First of all, 7 choose 4, a total of C(7,4) = 35 kinds of selection model state, the remaining three assumptions are originally 1,2,3 arrangement, to all not in the original Dan shouting position, only 2,3,1 and 3,1,2 two permeability balance arrangement methods, so different change methods a total of 35 * 2 = 70 kinds, choose C

The correct one is that the DA peptide bonds are reduced by 4 and each AA removed is reduced by two peptide bonds.

According to the general formula of AA, the molecular weight of a glycine residue is 12*2+16*1+14+1*3=57

The removal of one AA requires 1 molecule of water, an increase in molecular weight of 18, and the removal of one glycine residue molecule, a decrease of 39 peptide chains, and two 78

c add only two each.

When removing AA, water is also added to the peptide chain, and the number of O atoms remains the same.

Forehead ......Have you learned permutations and combinations? It's okay if you haven't studied, I'll probably explain ......n different elements, arrangement, do not remember the order, just like the amino acid formation polypeptide in your title, any new arrangement has different polypeptide formation, so there are a total of possible arrangement methods a(3,3), which can be calculated by factorial.

It's n*(n-1)*(n-2)*3*2*1) So, three amino acids, one for each of them, have a(3,3)=3!=3*2*1=6 dipeptide is understood as taking two of the three, how many ways to take it, and the dipeptide AB, AC, and BC composed of two different amino acids.

There are also six types of BA, BA, CA.

This is the knowledge of mathematical permutations and combinations.

For example, the dipeptides formed are:

aa 、ba 、ca

ab 、bb 、cb

AC, BC, CC (Note: AB and BA are different dipeptides. Because the amino and carboxyl groups used to form peptide bonds are different: AB, the carboxyl group of A is combined with the amino group of B; Ba, is the carboxyl group of B combined with the amino group of A).

Dipeptides, () have three options for each position, so there are both 3 2 for tripeptides, () there are three options for each position, so there are 3 3 for each position.

For n peptides formed from m amino acids, there are m options for each position, so there are m n species.

Please consider it in a permutation and combination method.

There are three empty spaces, ABC, 3 types in the first position, 2 types in the second position, and only 1 type in the third position.