Help me with three C questions, thank you

Question 1: Something is missing here:

if（aelse k=b%a;

Probably wanted to write:

if(a>b) k=a%b;If a is greater than b, then k is equal to a and b;

else k=b%a;Otherwise, k is equal to b and a ;

"Remainder" is the number left after the previous number is divisible by the next number.

1.Right?

main（）

int x=1,y=3;* Let the integer variable x,y, where x=1, y=3*

printf（"%d,",x++）

The result of x++ is output, x++ means that x participates in the operation and adds 1, and the value of x is 2*

int x=0;x+=y*2;

Let x=0, calculate x+y*2, and assign the result to x, where the value of x is 6*

printf（"%d,%d, ",x,y）;* outputs the values of x and y, which are 6 and 3 respectively

printf（"%d,%d＼n",x,y）;

Finally, the values of x and y are output and then the line is wrapped. Because the x and y values here are not affected by the statement in {}, they are still 2 and 3*

main（）

int i;Set the integer variable i

int a[3][3]=;*Let the integer two-dimensional array a[3][3]*

for（i=0;i<3;i++）

loop, which starts when i=0 and adds 1 to the value of i when i<3, otherwise it jumps out of the loop*

printf（"%d ",a[2-i][i]）;*Output a[2-i][i] result*

First question, I don't know what you wrote. It's a mess!

In the second question, x++ outputs the value of x first and then x+1, so it outputs 1 first, and the current value of x is 2;

Inside x=0, x+=y*2 is equivalent to x=x+y*2, x=0, y=3, so x=6, output 6 and 3;

Finally x=2, y=3, output 2,3

The third question, a[3][3] is a two-dimensional array, in which the numbers are a[0][0]=1,a[0][1]=2,a[0][2]=3,a[1][0]=4,a[1][1]=5,a[1][2]=6,a[2][0]=7,a[2][1]=8,a[2][2]=9;

So the output is 753

There are a lot of mistakes in these questions.

a[3] is an array that means that there are 3 elements in array a.

x++ is to output x first and then x+1

0xeb

0xeb0xeb

0xeb result is 0x75

The same can be said. 0xec

0xec result is 0x76

So the first question is A

For the second question, choose D

You are welcome.