The answer to the preliminary round of the junior high school group of the 16th Hua Cup!

c b c a b c 891134 4 391 1026

The master flies by. By the way, the answers given in the open questions are too complicated, and you can just scale them down.

BS Organizing Committee.

The 16th Hua Luogeng Gold Cup Junior Mathematics Invitational Tournament.

Answers to preliminary questions (first set).

1. Multiple choice questions (10 points per question, out of 60 points) Answers 1 d 2 b 3 c 4 a 5 b 6 c 2. Fill-in-the-blank questions (10 points per question, out of 40 points.) Answer.

This is a 100% correct standard answer:

d b c a b c

Let's take a look at your score!

d b c b b a 891134 4 391 1026

My own answer = = I don't know if it's right or not, ask for it.

The answer is as follows: Multiple choice questions (1-6).

Fill-in-the-blank questions (7-10).

The results are already out......Hi Hi I'm 105 points....Guangzhou Tianhe....The multiple-choice question has already deducted 40 points......5 points (probably) were deducted for the quiz questions......It's already pretty good for me

Extra penguin goose goose

2011 Hua Cup Preliminary Round Answer Details:

1.The sum of any four consecutive natural numbers must be divided by 4 to balance 2, so only 102 satisfies the condition.

are all composite" condition can be ignored.

c2.It is easy to find that if the original number has n matches, it corresponds to the number 7-n.

The number of matches in the original number is 2,5,5,4,5,6,3,7,6,6, including 2,3,4,5,6,7, a total of 6 different numbers, so there are 6 different corresponding numbers.

c3.This belongs to the sum multiple problem, the large number is 6 times the decimal, so their sum is equal to 7 times the decimal number, that is, the decimal number is 6 7, the large number is 36 7, the product of the two numbers is 216 49, and the difference between the two numbers is 30 7 = 210 49, so the difference is 6 49.

d4.Nothing two people say can be true at the same time, so at most one person is telling the truth, if.

There is a person who reviewed, then Li said the truth and was in line with the topic; If no one reviews it, then Zhang is telling the truth and contradictory.

b5.If you look at the column where the ant is located, you can see that it should be in the middle column, and there are n and q on this column;

If you look at the row where the ant is, you can see that it should be in the middle row, so it is n.

b6.Add 3 computers, the time becomes 75%, that is, 3 4, which means that the number of computers increases to 4 3, an increase of 1 3, and there are 9 originally; If you reduce 3 computers, reduce to 2 3, time becomes.

3 2, increased by 1 2, so the original time was 5 6 2 = 5 3 (hours).

8.After the encounter, A needs 3 hours to return to A. The second time they meet, A is close to the point of meeting.

The distance is equal to the distance of A's hours, and B took hours to walk these distances, so A-B speed ratio.

For 7:5. It takes 3 hours for A and B to meet, so it takes 180 12 5 = 432 minutes for B to get there alone.

9.It is easy to know that the area of ABM and EFM is equal between parallel lines, and the area of CDN and EFN is equal.

And the sum of the areas of EFM and EFN is equal to EF (Mo+On) 2=26, so the area of the blank part.

The sum is 52 and the answer sought is 65.

1. Multiple choice questions. Each question is worth 10 points, and the full score is 60 points. Only one of the four options for each of the following questions is correct, please write the English letter indicating the correct answer in parentheses for each question).

1 The following emotes**.

The number of axes without symmetry is ( ).

a） 3 （b） 4 （c） 5 （d） 6

2 Six days before the start of school, Xiao Ming had not done his winter vacation math homework, and Xiao Qiang had completed 60 questions. At the beginning of the school year, both of them completed their math homework, and in these 6 days, Xiao Ming did 3 times as many problems as Xiao Zhang, and he did ( ) problems on average every day.

a） 6 （b） 9 （c） 12 （d） 15

3 According to the regulations of the Organizing Committee of the Chinese Basketball Professional League, the number of each team member can be selected from 0 55, but when choosing a two-digit number, each digit cannot exceed 5. So, there are ( ) numbers available for each team to choose from.

a） 34 （b） 35 （c） 40 （d） 56

4 In the three numbers 19, 197, 2009, the number of prime numbers is ( ).

a） 0 （b） 1 （c） 2 （d） 3

5 There are four equations below:

The correct equation is ( ).

a) and (b) and (c) and (d) and

6 Five children play a game, and each round of the game passes the toy in their original hand to another child according to the direction of the arrow below: c, at the beginning, holding the Fuwa, holding the Funiu, and when the wheel is passed, the child holding the Fuwa is ( ).

a) with (b) a and d (c) c and e (d) a and b

2. Fill-in-the-blank questions (10 points for each question, full score of 40 points).

7 In the following equation, the same Chinese character represents the same number, and different Chinese characters represent different numbers.

Tuan Tuan Yuan Yuan = Giant Panda.

Then the three-digit number represented by "Giant Panda" is ( ).

8 Arbitrarily select 3 out of 4 integers, find their average value, and then find the sum of this average value and the remaining 1 number, so that you can get 4 numbers and 423, then the sum of the original given 4 integers is ( ).

9 As shown in the figure below, AB is the diameter of the semicircle, O is the center of the circle, arc AC=arc CD=arc DB, M is the midpoint of the arc CD, H is the midpoint of the chord CD, if it is a point on the ob, the area of the semicircle is equal to 12 square centimeters, then the area of the shaded part in the figure is ( ) square centimeters.

10.Among the natural numbers greater than 2009, after being divided by 57, there are ( ) numbers with quotient equal to remainder.

Answer: Question number 1 2 3 4 5 6 7 8 9 10

Answer: 968 10 2 22

Test Center: Area and Equal Area Transformation

Topic: Combination of numbers and shapes

Analysis: pass the P point as PE BP, the perpendicular foot is P, cross BC to E, according to the bisector BP of AP perpendicular B to P, you can find ABP BEP, and know that APC and CPE are equal to the same height, you can prove that the area of the two triangles is equal, that is, the area of the triangle PBC can be proved

Answer: Solution: pass the point p as pe bp, the vertical foot is p, cross bc at e, ap perpendicular b bisector bp at p, abp = ebp, know bp = bp, apb = bp = 90 °, abp bep, ap = pe, apc and cpe are equal to the same height, s apc = s pce, the area of the triangle pbc = 12 triangle abc area = 12cm2, only the area of b in the option is 12cm2, so choose b

To make the preliminary round of the Hua Cup as small as possible, start with the smallest and make gradual adjustments.

The minimum preliminary round of the Hua Cup can be 10, then "ten" can be 8 or 9 if "ten".

Rule. Rabbit. Six. Beginning.

Single digit rounding. If "ten".

Rule. Rabbit. Six. Beginning.

Single digit rounding. In the first case, one of the three words rabbit, six, and the beginning must be 9, then the carry of the single digit can only be 1 (the sum of the remaining numbers can not reach 21), and the sum of the remaining two numbers is 11, and the choice is 4 and 7, or 5 and 6

When the tens are , the single digits are

When the ten digits are , they do not exist.

At this time, the smallest Hua Qi and Cup preliminary round trembling mark was 1042

In the second case, the sum of the ten digits is 11, and if the sum of the single digits is 21, then the single digit is , and the ten digits must be , which meets the conditions.

If the sum of the single digits is 11, the single digit is taken to , and the ten digit cannot be taken to meet the conditions.

At this time, the smallest preliminary round of the Hua Cup is 1026

To sum up, the smallest Hua Cup preliminary round is 1026

Solution: 2x=ya=3b

Original = 72b3x2 97b3x2 = 72 97

I did, I was the first prize in the 14 15 16 Hua Cup.

Solution: From the problem, we can know that 2x=y a=3b

Original = 72b3x2 97b3x2 = 72 97 I did it, I was the 14th 15th 16th Hua Cup first prize downstairs is too good at plagiarism, hey.

I want the answer to the seventeenth style question.