Elementary school math, please help! Thanks

1.Solution: Let a be x, then b=(x-3) 11 Since a and b are both greater than 0 and positive, the minimum value of b is 4, the minimum value of x is 47, and the minimum value of a is 47.

2.Solution: Let a be x, then b=(x-9) 13b=x-189 solution x=204 Answer: a is 204.

3.Solution: There are x fruit baskets, each fruit basket has apples a and pears b, then (a+b)*x+12=57+80 solution (a+b)*x=125

Because each basket has as many fruits, 125 can only be broken down into 5*25, so there are either 5 fruit baskets with 25 fruits per basket or 25 fruit baskets with 5 fruits per basket.

The minimum value of b is 4

So, a is 11 4 + 3 = 47

The minimum value of a is 47

a=13×15+9=204

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Ibid., B:4, A: 47

Solve the equation (b+189) b-9=13 to get b:9 a:198 assuming that the remaining 12 fruit apples are a, pears are 12-a, assuming n apples, m pears are a fruit basket.

57-a）/n=（80-12+a）/m

So n is greater than m, assuming m=1, n=2, we get a=23, which is not true.

Suppose m = 2, n = 3, a = 7, 57-7 2 = 25 so there are 25 fruit baskets, 5 fruits in each basket... It's a bit hard, but it's easy to understand.

The simple way to do it is 57 + 80-12 = 125 in the form of 5 times 25, 5 or 25 fruit baskets. 5 is unreasonable, so 25.

3.5 or 1

Idea: The remainder is 3, the minimum divisor is 4, 4*11+3 = 47 columns of binary linear equations.

57 + 80 = 137, 137-12 = 125, the factor of 125 greater than 12 is only 25 and 125, 125 divided by 25 gives 5, 125 divided by 125 gives 1

Questions 1 and 2 are quite simple, let me talk about the third question, there are x fruit baskets, and there are 12 fruits left at the end to show that the sum of the remainder of 57 divided by x plus 80 divided by x is 12, and according to a theorem of divisor and remainder, it shows that (57+80) The remainder of x is 12. There are two options for x that meet the conditions, 25 and 5, respectively, 25 meets the topic, thank you, I hope it can help you.

Because a divided by b equals 11 ......3, so b is greater than 3 and a is 47 (which I think only integers can do).

In a one-dimensional equation, let b be x, and a be x plus 189, so x plus 189 equals 13x plus 9, so x=b=15, and a is 204

I can't do that, but can you tell us how many apples and pears are in a fruit basket?

1. 13＋9=21 2. a=204 3.

25 (Try slowly.) 57 80 = 137 137 - 12 remaining = 125 The number of fruit baskets must be greater than 12. Later, I tried it slowly, and I could get rid of it with 25.

1) A takes the minimum value and B takes 2, then a=11 2+3=25

2) Let a= +189 b= give 13 +9=x+189 x=15, then a=15+189=204

The remainder is 3, the minimum divisor is 4, 4*11+3=47a (a-189)=13....9

a=13(a-189)+9a=204

Find it from the factor of 125, and it must be greater than 12, only 25