The six major precipitation equations, which are the four major precipitation equations

Common precipitation in junior high school chemistry:

AGCL white precipitate

Barium sulfate (BaSO4) white precipitate

Calcium carbonate, (calcium sulfite,) caCO3

Copper hydroxide (Cu(OH)2) blue precipitate,

Iron hydroxide Fe(OH)3 reddish-brown precipitate

Calcium hydroxide Ca(OH)2

A chemical equation that generates the precipitate.

A chemical equation that generates the precipitate.

CuSO4+2NaOH=Cu(OH)2 +Na2SO4 Blue precipitate generation, the upper part is a clear solution Mass conservation law experiment Ca(OH)2+CO2= CaCO3 + H2O Clarified lime water becomes turbid Apply CO2 test and lime mortar to paint the wall Ca(HCO3)2 CaCO3 +H2O+CO2 White precipitation, produce gas that makes the clarified lime water turbid Scale formation. Formation of stalactites.

HCl+AGNo3= AGCl +HNO3 produces a white precipitate, insoluble in dilute nitric acid Principle of testing Cl- Ba(OH)2+ H2SO4=BaSO4 +2H2O Produces white precipitate, insoluble in dilute nitric acid Principle of testing SO42- BaCl2+ H2SO4=BaSO4 +2HCl Produces white precipitate, insoluble in dilute nitric acid Principle of testing SO42- Ba(NO3)2+H2SO4=BaSO4 +2HNO3 Formation of white precipitate, insoluble in dilute nitric acid Principle of testing SO42- FeCl3+3NaOH=Fe(OH)3 +3NaCl solution yellow fades, there is reddish-brown precipitate to form AlCl3+3NaOH=Al(OH)3 +3NaCl There is a white precipitate to form MgCl2+2NaOH = Mg(OH)2 +2NaCl

CuCl2+2NaOH = Cu(OH)2 +2NaCl solution blue fades, there is a blue precipitate to generate CaO+ H2O = Ca(OH)2 White lumpy solid becomes powder, quicklime to prepare lime slurry Ca(Oh)2+SO2=CaSO3 + H2O has white precipitate to generate Junior high school generally does not use.

Ca(OH)2+Na2CO3=CaCO3 +2NaOH has white precipitate Industrial caustic soda, laboratory caustic soda in small quantities BA(OH)2+Na2CO3=BaCO3 +2NaOH has white precipitate Ca(OH)2+K2CO3=CaCO3 +2koH has white precipitate.

AgNO3+NaCl = AGCl +Na NO3 white precipitate insoluble in dilute nitric acid (similar reaction to other chlorides) It is used to test chloride ions in solutions.

BaCl2 + Na2SO4 = BaSo4 + 2NaCl white does not dissolve in the precipitate of dilute nitric acid (other sulfate-like reactions) It is used to detect sulfate ions.

CaCl2+Na2CO3= CaCO3 +2NaCl has a white precipitate to form MgCl2+Ba(OH)2=BaCl2+Mg(OH)2 has a white precipitate.

CuSO4+2NaOH = Cu(OH)2 +Na2SO4 blue precipitate generated, the upper part is a clear solution.

Experiments on the law of conservation of mass.

ca(oh)2+co2=

caco3↓+

H2O clarified lime water becomes turbid.

Apply CO2 inspection and lime mortar to paint the walls.

ca(hco3)2δ

caco3↓+h2o+co2↑

White precipitation, the production of clear lime water turbidity gas.

Limescale formation. Formation of stalactites.

hcl+agno3=

agcl↓+hno3

It produces white old plum color precipitate and is insoluble in dilute nitric acid.

Check the principle of cl-.

ba(oh)2+

h2so4=baso4↓+2h2o

Produces a white precipitate, insoluble in dilute nitric acid.

Examine the principle of SO42.

bacl2+

h2so4=baso4↓+2hcl

Produces a white precipitate, insoluble in dilute nitric acid.

Examine the principle of SO42.

Ba(NO3)2+H2SO4=BASO4 +2HNO3 generates a white precipitate, insoluble in dilute nitric acid.

Examine the principle of SO42.

FeCl3+3NaOH = Fe(OH)3 +3NaCl solution fades yellow and has reddish-brown precipitate.

AlCl3+3NaOH = Al(OH)3 +3NaCl has a white precipitate.

mgcl2+2naoh

mg(oh)2↓+2nacl

cucl2+2naoh

cu(oh)2↓+2nacl

The blue color of the solution fades, and a blue precipitate is formed.

cao+h2o

ca(oh)2

The white lumpy solid turns into powder

Quicklime prepares lime slurry.

ca(oh)2+so2=caso3↓+

H2O has a white precipitate generated.

Not in junior high school.

Ca(OH)2+Na2CO3=CaCO3 +2NaOH has a white precipitate to form.

The labor movement knows that caustic soda is made, and a small amount of caustic soda is made in the laboratory.

Ba(OH)2+Na2CO3=BaCO3 +2NaOH has a white precipitate generated.

ca(oh)2+k2co3=caco3↓

2koh has a white precipitate generated.

agno3+nacl

agcl↓+na

NO3 white is insoluble in the precipitation of dilute nitric acid (similar reaction to other chlorides) and is used to test chloride ions in solutions.

bacl2na2so4

baso4↓+2nacl

White precipitates that do not dissolve in dilute nitric acid (similar reactions to other sulfates) should be used to test sulfate ions.

cacl2+na2co3=

caco3↓+2nacl

There is a white precipitate generated.

MgCl2+BA(OH)2=BACl2+Mg(OH)2 is generated by achromatic precipitation next to white.

Sodium hydroxide with copper sulfate: 2NaOH + CuSO4 ==== Cu(OH)2 + Na2SO4

Sodium hydroxide with ferric chloride: 3NaOH + FeCl3 ==== Fe(OH)3 + 3NaCl

Sodium hydroxide with magnesium chloride: 2NaOH + MgCl2 ==== Mg(OH)2 + 2NaCl

Sodium hydroxide with copper chloride: 2NaOH + CuCl2 ==== Cu(OH)2 + 2NaCl

Calcium hydroxide with sodium carbonate: Ca(OH)2 + Na2CO3 === CaCO3 + 2NaOH

Sodium chloride solution and silver nitrate solution: NaCl + Agno3 ==== AgCl + Nano3

Sodium sulfate and barium chloride: Na2SO4 + BACL2 ==== BaSO4 + 2NaCl

Hydrochloric acid and silver nitrate solution reaction: HCl + AGnO3 === AGCL +HNO3

Sulfuric acid and barium chloride solution reaction: H2SO4 + BACl2 ==== BaSO4 +2HCl

Sodium hydroxide with copper sulfate: 2NaOH + CuSO4 ==== Cu(OH)2 + Na2SO4

Slaked lime deteriorates when placed in air: Ca(OH)2 + CO2 ==== CaCO3 + H2O

Slaked lime absorbs sulfur dioxide: Ca(OH)2 + SO2 ==== CaSO3 + H2O

Precipitation exposed to in junior high school: Fe(OH)3 reddish-brown precipitate Cu(OH)2 blue precipitate.

The other precipitates are white

[Chemical experiments] common precipitation formation.

CuSO4+2NaOH = Cu(OH)2+Na2SO4 blue flocculent precipitate.

Is it OK to use cucl2?

The ionic chemical equation that generates the precipitate.

Insoluble water-insoluble precipitates are: calcium carbonate, barium sulfate, copper hydroxide, silver chloride, iron hydroxide.

1 salt ten judgment late salt: such as na2c03 deca cacl2 = cac03 (shen) deca 2nacl 2Salt and alkali such as mgc12 decten mg(0h)2 (sinking) 3 salts and decatic acids, such as bac12 ten rent flushing h2s04 = bas04c sinking) deca2hcl 4 acidic oxides and bases such as c02 deca (0h) 2 = cac03 (sinking) ten h20

1. Calcium oxide is insoluble in water, it only reacts with water. Don't confuse !!

Because there are insoluble substances in the front, there is no precipitate in the back.

2. In the solution, the insoluble substance is generated from the soluble substance, and the standard is precipitated.

3. Not in the solution, not marked precipitation, only marked gas rise (when heated, the water is vapor and runs away...)

4. In the solution, a small amount of microlytic matter (it is clear lime water, which is usually considered to be a solution) is used to generate calcium sulfate, a microlytic orange positive substance, although it is also slightly soluble (but because it is a product, it is usually considered to be generated in large quantities, that is, precipitation).

So: copper hydroxide and calcium sulfate precipitate.

I don't understand what you mean, if it's an intra-group reaction, here's how:

1.The non-aged form CaCO3 precipitate because of the presence of hydrochloric acid.

The reason why BaCO3 is not formed is because of the presence of nitric acid. The formation of BaCO3 is not due to the presence of sulfuric acid. )