Chickens and rabbits have a total of 14 heads, and rabbits and chickens have a total of 40 legs.

Suppose the chicken and the rabbit understand the human language, first let them both put away one leg, at this time there are 40-14 = 26 legs left, and then let them put away the second leg, at this time there are 26-14 = 12 legs left, since both legs of the chicken are folded up and fall to the ground, the remaining legs are the legs of the standing rabbit, so the rabbit is 12 2 = 6, and the number of chickens is 14-6 = 8!

Suppose the cage is full of chickens, and there are a total of legs 14 times 2 equals 2840 less minus 28 equals 12 legs For each additional rabbit with 2 more legs, the more legs are rabbits (12 divided by 2 equals 6).

The number of chickens is 14-6 = 8.

How many chickens and rabbits are there?

Solution 1: Suppose all 7 chickens have legs.

2 7 14 (strips), difference 20 14 6 (strips) legs, each rabbit is two retreats, there are rabbits: 6 2 3 (only).

There are 7-3 4 chickens (only).

Solution 2: Suppose all 7 rabbits have legs.

4 7 28 (strips), difference 28 20 8 (strips) legs, each chicken is two retreats, there are chickens: 8 2 4 (only).

There are push 7-4 3 (only).

Solution 3: If there are x chickens, there are rabbits (7-x), and if there are 2x+4(7-x)=20, there are rabbits 7-4=3 (only) if there are x=4

Let the number of rabbits be x and the number of chickens be yThen there is: x+y=14, 4x+2y=40, and the solution is x=6, y=8

Let the chicken be x, then the rabbit will be 14-x

2x+（14-x）*4=40

So x is equal to 8 so rabbit is equal to 6

We are a perfect match to say it comprehensively, you can have him, I won't talk about it.

There are 11 chickens and 9 rabbits.

Solution: If there are x chickens, then rabbits are: (20-x);

4（20-x）-2x=14

80-4x-2x=14

6x=66x=11

11 chickens;

There are 20-11 = 9 rabbits.

Let the chickens and rabbits be x and y.

x+y=20

4y-2x=14

x=11.

y=9. 11 chickens and 9 rabbits.

If there are x chickens and y rabbits, then there is a system of equations x+y 12, 2x+4y=40There are 4 chickens and 8 rabbits.

There are x chickens that are accompanied by bumpers.

2x-4*(40-x)=50

6x-160=50

6x=210

x=35.

Rabbit Xiaoqin = 40-35 = 5.

If it's all chickens, 7 2=14.

20-14) 2=3 rabbits.

Chickens 7-3=4.

How many chickens and rabbits are there?

Solution 1: Suppose all 7 chickens have legs.

2 7 14 (strips), difference 20 14 6 (strips) legs, each rabbit is two retreats, there are rabbits: 6 2 3 (only).

There are 7-3 4 chickens (only).

Solution 2: Suppose all 7 rabbits have legs.

4 7 28 (strips), difference 28 20 8 (strips) legs, each chicken is two retreats, there are chickens: 8 2 4 (only).

There are push 7-4 3 (only).

Solution 3: If there are x chickens, then there are rabbits (7-x), 2x+4(7-x)=20

If x=4 is solved, there are rabbits 7-4=3 (only).

If there are x chickens, then there are (7 x) rabbits, and the equation 2x+4(7-x) 20 is solved.

How many chickens and rabbits are there?

Solution 1: Suppose all 7 chickens have legs.

2 7 14 (strips), a difference of 20 14 6 (strip of bridge shed late) legs, each rabbit is two years behind, there are rabbits: 6 2 3 (only).

There are 7-3 4 chickens (only).

Solution 2: Suppose all 7 rabbits have legs.

4 7 28 (strips), difference 28 20 8 (strips) legs, each chicken is two retreats, there are chickens: 8 2 4 (only).

There is a push 7-4 3 (only Min Lee).

Solution 3: If there are x chickens in Hedan, there will be rabbits (7-x), and 2x+4(7-x)=20 will solve x=4 to have rabbits 7-4=3 (only).

There are as many chickens as rabbits, chickens have two legs and rabbits have four legs. A chicken plus a rabbit equals 6 legs.

So there are 9 chickens and 9 rabbits.

It's as simple as that, satisfied.