Sixth grade math problems, a total of four questions, can answer a few questions, ask for the proces

Solution: Original formula = (1-1 2) + (1-1 4) + (1-1 8) + (1-1 16) + (1-1 32) + (1-1 64) + (1-1 128).

6+1 128 (with fractions or fake fractions, you can change them yourself).

Solution: Produced in the first quarter: 250+250 (1+1 5)+250 (1+1 5) =910

Because the first quarter produced 5 12 for the whole year, the full year plan is: 910 (5 12) = 2184 (tons).

Solution: 3 8 320 3 10=400

Because) 400 320

So) can (because you can do 400 in ten hours, 400 is greater than 320).

Solution: Let the total number be x

1-[x/5+5+x/4+7+(x-x/5-x/4-5-7)×1/2]=x/8

Solution x=40

Complete. I don't know how to add me yet, tmnt

Simplification of the original = 769 128

Yes. So 8 hours to complete.

If you don't understand, you can ask, it helps, thank you!

Question 1 6 Question 2148

Can 320*(3 8) 3=40 hours 320 40=8 hours So 10 hours can be completed.

Question 40

1.The weight of a glass of water is (500-440) 2=30, then the weight of the cup is (440-30 3)=350 grams2.?? What do you mean??? Is the sum of two two-digit numbers 132?

3.column equations; If Xiao Ming is x years old, his father is x + 27 years old; Three years ago, Xiao Ming was x-3 years old, and his father was x+27-3=x+24 years old.

The equation is – (x-3) 5+3=x+24

Solution x=27

4. Is there less condition for the question?

5..Column equation: Let x people participate in long-distance running, then 15x=(x-4) 17+6, and the solution is x=31

1.If a gram is in a glass of water, then 440-3a = 500-5a, and the solution is a = 302Let the original 2-digit single digit be a, then the 10-digit is 2a, then this number is 20a+a, and after the conversion, it is 10a+2a, so 20a+a+10a+2a=132, then a=4, so the original two-digit number is 84

3.Let Xiao Ming be a year old this year, then Dad is A+27 years old this year, so A+27-3=5(A-3)+3, so A=9, so Xiao Ming is 9 years old this year, and Dad is 36 years old this year.

4.The average speed is 2 (1 20 + 1 30) = 24km h5If there is a person, then 15a = (a-4) * (15 + 2) + 6, so a = 31

1., let a glass of water weigh x and a bottle weigh y.

3x+y=440

5x+y=500

If you solve it, it will come out.

2.Let the single digit be x and the ten digit be 2x

So this number is 10 times 2x+x, right? That is, 20x+x=21x, after the swap, the single digit is 2x, and the ten digit is x

So this two-digit number is 10x+2x, right? It's 12x, so it adds up to 21x+12x=132, right?

It's out. Equal to 4

Then it's 21 times 4 = 84

I'm tired.

I'm waiting for Ha to fight with you.

Oh my God, is this still a 6th grade topic?!!

/4 ×（1-1/x×1/5）=1/5+1/x

1/4 ×（1-1/5x）=1/5+1/x

1/4-1/20x=1/5+1/x

Move the item to get 1 x + 1 20 x = 1 4-1 5

21/20x=1/20x=21

Application question 1: Do you buy 80 articles before buying?

Answer to question 1: x=21

Short-answer question 1: Solution: original formula = 1*3*24 (1+2*2*2+3*3*3)--1*2*4(1+2*2*2+3*3*3).

1.Shift, pass the score, get: x=21

1.Solution: Original formula = 1*3*24 (1+2*2*2+3*3*3) 1*2*4(1+2*2*2+3*3*3).

So: 1 2 3 20

You're asking the right question.

1.(200 14 4) (1 1 5 "1 5 means one-fifth, and I won't say it later.") 1 4) 80 (pcs).

Equation: Solution: Let the apprentice do x pieces.

1/5x+14）/（1/4）+x=200x=802.Calculation: 180 (3 5) = 180 (5 3) = 300 (km).

Equation: Solution: Let the distance between A and B be x kilometers.

x-180+20%x）=3(180-20%)2x-360+40%x =540-40%x2x+x =540+360

3x =900

x =300

3.Calculation: 420 (3 4 2 3 1) 175 (km) Equation: People also make mistakes, I forget. =

That's it = =

There is also the addition of verification and math that will not be added.

1. If the apprentice has done x, the master has made 200-x.

Then there is the equation (200-x) 4-x 5=14

36=9x/20

x=802, let A and B be separated by x

x-180+((

1.Design: The apprentice made x and the master made y.

x+y=200, (1 4)y-(1 5)x=14 solution: x=80 y=120

A: The apprentices made 80 of them.

2.Set: A and B are x kilometers apart.

x-(:3 solves: x=300

A: A and B are 300 kilometers apart.

3.The distance between car A and its destination after 5 hours is: 420 (1 4) = 105 (km).

After 5 hours, the distance between car B and the destination is: 420 (1 3) = 140 (km), at this time, the distance between the two cars: 420-(105+140)=175 (km).

1.Solution: Set up apprentices to do x.

200-x）1/4=1/5x+14

x=80 Answer: The apprentice made 80.

2.The ratio of the distance traveled to the total distance traveled is 3:5

The untraveled distance is 2 5

Solution: Set the whole journey x kilometers.

2/5x+20％x=180

x=300A; The total distance is 300 km.

1., apprentice do x

200-x)/4=x/5+14

50-x/4=x/5+14

x/5+x/4=50-14

9x/20=36

x=80 2, Analysis:

It is known that after a certain distance, there are still 180 kilometers away from place B, and then 20% of the whole journey is 1/5, and the ratio of the distance traveled to the distance not traveled is 3:2, so it can be seen that the distance traveled at this time is 3/5 of the whole journey, and the untraveled distance is 2/5 of the whole journey, so when there are 180 kilometers to go to place B, the untraveled distance is 3/5 of the whole journey

That is, 3/5 of the whole journey is equal to 180 kilometers.

Therefore, the distance between A and B is 180 (3/5) = 180 (5/3) = 300 km.

The composite formula can be listed as: 180 (20% + 2/5) = 180 (3/5) = 180 (5/3) = 300 km).

(3/4 2/3 1) 175 (km).

1.Analysis: Assuming that the 1 4 made by the master is equal to the 1 5 made by the apprentice, then the master has 4 fewer "14 parts" than the actual parts, that is, (14 4).

Answer: (200 14 4) (1 1 5 1 4) 80 (pcs).

A: The apprentice made 80 parts.

2.Analysis:

It is known that after a certain distance, there are still 180 kilometers away from place B, and then 20% of the whole journey is 1/5, and the ratio of the distance traveled to the distance not traveled is 3:2, so it can be seen that the distance traveled at this time is 3/5 of the whole journey, and the untraveled distance is 2/5 of the whole journey, so when there are 180 kilometers to go to place B, the untraveled distance is 3/5 of the whole journey

That is, 3/5 of the whole journey is equal to 180 kilometers.

Therefore, the distance between A and B is 180 (3/5) = 180 (5/3) = 300 km.

The composite formula can be listed as: 180 (20% + 2/5) = 180 (3/5) = 180 (5/3) = 300 km).

3.420 (3/4 2/3 1) 175 (km).

1. Apprentice x 4 1 (200-x)-5 1 x=14 x=2, A B x meter away (:x=2:(2+3) x x(3 4)+420x(3 2)-420=Wishing for a good heart.

1., apprentice do x

200-x)/4=x/5+14

50-x/4=x/5+14

x/5+x/4=50-14

9x/20=36

x = 80 2 180 (3/5) = 180 (5/3) = 300 km.

3420 (3/4 2/3 1) 175 (km) 2626

The first problem is that if the master does x apprentices and does y, x+y=200 4 1x-5 1y=14, the simultaneous equation can be solved: the master does 120, and the apprentice does 80.

The second is to set the whole process to x 180+5 1x=5 3x untie x =450

The second question tells you.

I'm different from them, I'm going to keep it simple.

180 3 = 60 5 * 60 = 300 meters That's right.

Others are easy, too.

Higashinoyoshi: It's very simple, it's from the winter vacation homework, right?

2 If a-2 0 then x a+2, and x 2 3, so 2 3 x a=2

If a-2 0 then x a+2, and x 2 3, so x a+23 can be obtained by arranging: x-2y+z=9 2x+y+3z=10 3x-2y-z=3 solve the system of equations to get x=2 3 y= 7 3 z=11 3

I know how to do it, I don't want to write the process, the process is so troublesome.

1.When x=3, y=3, z=0 or x=3, y=2, z=1, the minimum value is 21

According to the meaning of the question, it can be seen that when z is the maximum, the result of the problem is the maximum, so when x=y=z, x,y,z is 2

So the maximum value is 24.

3333*3333+9999*8889

1/3*x+1/4*x+5=x

x-7/12*x=5

5/12*x=5

x=5*12/5

x=1218*5/7 - 5*4/7.

3333 * 3333 + 9999 * 8889 simple algorithm.

9999 * (1111 + 8889) = 99990000 one-third x + quarter x + 5 = x

17/12x=5

x=60/17

18*5/7 - 5*4/7.

5/7 gives 5 7 (18-4) = 10

27*Simple Algorithm27*

3333*3333+9999*8889

1/3x+1/4x+5=x

4x+3x+60=12x (simplify the unknown term with fractions first) 5x=60

x=1218*5/7 - 5*4/7.

10 (I'm a simple solution for elementary school students).

One. =1900 20%, 380 (yuan);

Answer: Mr. Zhang's personal income tax is 380 yuan

II. 1How many trees in total.

2.Winter jujube trees account for 60 percent

3.Jujube trees account for 40 percent

4.Three solutions: five years ago, the per capita housing area of the city was x square meters (1 + 25%) x =

1. Column equation: 10%*(x-3500)-105=200 solution x=6550 Therefore, the income is 6550 yuan.