0258 Composed of three digits, if it is an odd number or something, you must write a good classifica

Odd numbers 285, 205, 825, 805

Even numbers 502, 582, 508, 528, 258, 208, 802, 852, 250, 280, 520, 580, 820, 850

Multiples of 2 502, 582, 508, 528, 258, 208, 802, 852, 250, 280, 520, 580, 820, 850

Multiples of 5 285, 205, 825, 805, 250, 280, 520, 580, 820, 850

Multiples of 3 258,825,528,582,285,852

is both a multiple of 2 and a multiple of 3 258,582,852

It is both a multiple of 2 and a multiple of 5 250,280,520,580,820,850

is both a multiple of 5 and a multiple of 3 285,825

Hello: Odd: 285

Even number: 258

Multiples of 2: 582

Multiples of 3: 528

is both a multiple of 2 and a multiple of 3: 258

is both a multiple of 2 and a multiple of 5: 520

Both a multiple of 5 and a multiple of 3: 285

Odd: 285 205 805 Even: 250 520 280 820 802 852 582 2 multiples:

250 520 280 820 802 852 582 3 Multiples: 258 285 528 582 825 852 5 Multiples: 250 520 280 820 580 850 805 205 825 285 Multiples:

Multiples of 528 582: 250 280 520 820 580 850 Multiples of 825 285

Summary. Pro, the expression is as follows: the four numbers of 0258 can form 18 three-digit numbers.

Pro, the expression is as follows: the four numbers of 0258 can form 18 three-digit numbers.

The calculation process is as follows: 3 3 2 = 18 with the four numbers 0258 to form 18 three-digit numbers.

Why is the answer to this question 48?

Dear, it's definitely not right to make up 16 three-digit numbers.

Yes, the child miscalculated, I think the answer is 48

Dear, you can think of it like this: the number of hundreds can be any one out of 258, there are three possibilities, any one of the three numbers under the remaining line is placed in the ten digits, and there are two possibilities for any one of the remaining two numbers to be placed in the single digit. So there are 18 three-digit numbers.

The answer is wrong.

The total number of the three digits that can be composed of the dust field are: 205, 208, 250, 280, 258, 285, 502, 508, 520, 580, 528, 582, 802, 805, and 820, 850, 825, 852.

Dear, the answer can't be 48, the answer is 18. I've listed 18 three-digit numbers above.

Dear, are you saying that there can also be a number of heavy annihilations! If the number could be repeated, then the answer would be 48. Namely:

3 4 4 = 48 means that the hundred number can be selected from any one of 258, the ten digits can be selected from 0258 and the single digit can be selected from 0258.

0, Jane with stuffy The three-digit number composed of these three numbers has a factor of 2, and 805 is an odd number of hidden tombs;

So the answer is ,805

With the 4 numbers 0258, you can form (18) different three-digit numbers, of which the largest three-digit number is (852) and the smallest three-digit number is (205).

0257 These four numbers form three digits to write three odd numbers, then the last digit is 5 or 7, when the last digit is 5, there are a total of 2 * 2 = 4 three digits, that is

When the last digit is 7, there is a total of 2*2=4 three-digit numbers, i.e. .

8 , 1 , 0 , 5 composed of three digit odd numbers:

A prime number is a natural number that has no other factors than 1 and itself in a natural number greater than 1.

An even number is a natural number that is divisible by 2.

The numbers in this set of numbers that are prime are and 7.

The three digits sought are even, so 2 must be placed at the end.

There are 752 and 572 three-digit numbers that meet the requirements, and there are 2 groups in total.

Of these five numbers, the prime numbers are 2, 5, and 7.

There is only 2 that is both prime and even.

So the single digit of a three-digit number can only be 2.

Therefore there are only two sets of numbers, 572 and 752.

To be divisible by 3: The number that satisfies the sum of the three numbers is divisible by 3, e.g. 2+5+8=15, divisible by 3, so the number can only be selected.

Divisible by 5: the single digit of the number should be 5 or 0, but 0 has been excluded and can only be 5.

So the minimum three-digit number should be 285.

The smallest three-digit number 2 is divisible and must end with 5. Try 205 first and it is not divisible by 3. Try 285 again and find that it works. A285

Pick three numbers in 0258 to form a minimum three-digit number that is divisible by three and five at the same time: 285 Analysis: 1, is a multiple of 5, so the mantissa is 5 or 0

2. It is a multiple of 3, and the sum of the three numbers is a multiple of 3, and only the multiple of 2+5+8=15=3 meets the requirements.

1) 5 and 4 must be at the same time, 540, 450, 504, 594, 954

2) Divisible by 30, satisfying 1) and having to end with 0 is only 540,450

All possible are listed,