A hollow copper ball, put into the water just suspended in the water, the density of copper is 8 9X1

Key point: The copper ball is suspended in water, and the gravity of the copper ball is known.

Analysis: The suspension of an object in water means that the object is completely immersed in water and can be stationary, that is, the buoyancy and gravity are balanced. So what is buoyancy?

Buoyancy is the gravitational force of that part of the water that is squeezed out by the object. According to the density and buoyancy of the water, the volume of the copper ball can be found. After the volume of the copper ball is known, the volume of the pure metal part of the copper ball is calculated according to the density of the copper metal, and after deducting the volume of the metal part, the volume of the hollow part is left.

v copper ball = f float ( water * g ) = n (10 3kg m 3 * 10 m s2) = m 3 = l).

v Pure copper = g copper ball ( copper * g) = ( *10 m s2) =

v hollow = v copper ball - v pure copper =

Since the copper ball is suspended in water, the buoyancy is equal to the gravitational force is equal to.

Copper ball mass = gravity 10 = kilograms.

Copper ball volume = mass density = 890 cubic meters.

The volume of the hollow part is not determined by known conditions.

The copper density is 8930kg m3

The density of water is.

Let the volume of the hollow part be V2 and the solid part be V1

Then 8932v1 (v1+v2)=

Solution v2 (v1+v2)=

Volume of copper balls:

v Copper guess positive ball = m water.

The volume occupied by Xiaoming copper in a copper ball:

v copper = m copper.

Then the hollow part of the body spike repents and accumulates:

v = v copper ball -v copper = m water - m copper.

Let's bring in the data yourself

(1) Because the copper ball is placed in water, it happens to be in a suspended state.

So g = f float = density of water * g * volume of copper ball = 1g * 1cm 3 * 10n kg * unit self-ization).

2) Solid copper ball, should use the volume of the copper ball * the density of copper, and then subtract the gravity of the hollow copper ball, so that there is a difference, is the mass of the hollow part, and the volume of the hollow part is obtained by removing the density of copper with the mass of the hollow part.

m=g/g=

Density of copper = v = m Density of copper =

Volume of the hollow part of the copper ball =

(1) Because the copper ball is placed in water, it happens to be in a suspended state.

So g = f float = density of water * g * volume of copper ball = 1g * 1cm 3 * 10n kg * unit self-ization).

2）m=g/g=

Density of copper = v = m Density of copper =

Volume of the hollow part of the copper ball =

g Copper = Find out the density of copper.

Utilizing buoyancy = density.

Multiply by the potato letter disorder. g multiplied.

The volume v of the copper ball can be obtained from the volume of the ball as several stops v1

The volume of copper v2 is then obtained by dividing by the density of copper

v1-v2 gives the volume of the hollow part.

The volume of the copper ball: v copper ball. m

Water. Volume of copper in a copper ball: v copper. m

Copper. Then the volume of the hollow part: vv copper ball.

v Copper. m slag this. m

Copper. Several hidden beams collapsed according to their own brought into the stove round

Levitation means that buoyancy is just equal to gravity, and buoyancy is equal to the gravitational force of the water being discharged.

This allows you to hollow the volume of the copper ball.

The mass is 89g, and the volume occupied by copper can be obtained.

Thus the volume of the hollow part of the copper ball is obtained.

I can't remember the density of copper, so I can't figure out the specific answer.

The density of copper is.

It can be known that the volume of copper in the ball is: 89

Because the mass of copper = the density of water * the volume of the ball.

89=1*v

So v=89cm3

Therefore, the volume of the hollow part of the copper ball = 89-10 = 79cm3, I hope the above information can be helpful to you.

Because the mass of the copper ball is 89g, it happens to be suspended in the water, the volume of water discharged is 89cm3, the density of copper is, the volume of copper = 89, and the volume of the hollow part of the copper ball = 89-10 = 79cm3

(1) Because the copper ball is placed in water, it happens to be in a suspended state.

So g = f float = density of water * g * volume of copper ball = 1g * 1cm 3 * 10n kg * unit self-ization).