Can 18dm and 26dm and 12dm form a triangle?

The sum of any two sides is greater than the third side to form a triangle. Whether the sum of the two smallest numbers is greater than the largest number is enough. 18+12=30 26, so 18-12-26 can form a triangle.

can form a triangle.

Because 26dm>18dm>12dm, and 18+12>26, 18dm and 26dm and 12dm can form a triangle.

18, 26, 12 can form a triangle. Because the sum of any two sides is greater than the length of the third side.

So it can form a triangle.

Then we can know that 18dm, 26dm, and 12dm can form a triangle.

Whether it can be composed or not depends on whether it meets the requirements: the sum of the two sides is greater than the third side, and the difference between the two sides is less than the third side. After inspection, it meets the requirements, so it can be composed.

Yes, the sum of any two sides is greater than the third side.

If the sum of any two sides is greater than the third side, and the difference between any two sides is less than the third side, a triangle can be formed.

18+12 26,26-12 18, the sum of any two sides is greater than the third side, and the difference between any two sides is less than the third side. Meet the above triangular formation conditions.

So the three sides of 18, 26, and 12 decimeters can be surrounded by a triangle.

The necessary condition for forming a triangle is that the sum of the lengths of any two sides must be greater than the third side.

And 12dm+9dm<30dm, these three line segments cannot form a triangle.

No. The condition for forming a triangle is that the sum of any two sides is greater than the third side.

12+9<30, so not eligible.

No, whether the three line segments can form a triangle can be determined by whether the sum of any two sides is greater than the third side, here it is obvious that 12 + 9 = 21 30, so it is not possible.

The sum of the two sides is greater than the third side.

12+9 30 so can not be composed.

The greatest common divisor of 18, 15 and 12 is 3

The maximum edge length of a cube is 3 decimeters.

A rectangular block with a length of 18dm, a width of 15dm, and a height of 12dm can be made into a 18*15*12 (3*3*3)=120 cube block prop.

Solution: 8+12=20 (decimeter).

12-8 = 4 (decimeters).

The length of the stick you take is between 4 decimeters and 20 decimeters (excluding 4 decimeters and 20 decimeters), and the length of the re-taken stick may be:

5 dm, 6 dm, 7 dm, 8 dm, 9 dm, 10 dm, 11 dm, 12 dm, 13 dm, 14 dm, 15 dm, 16 dm, 17 dm, 18 dm.

Why can't we pick 20 if we round the number of decimeters