I sincerely ask for a detailed explanation from the master, and I am very grateful

Life is long, but life is not very smooth.

cua=(3,4,6),cub=(1,6),cuancub=(6)cuaucub=(1,3,4, e.g. circle 6).

Right angles and acute angles, no right angles, right angles.

Wait, there's no time left for the oak to bury the ants.

(1) Solution: Substituting m=1 into y=x+m.

m=-1, so the analytic expression of the primary function is y=m-1

Let y=0 be substituted.

So m=1, so a(1,0).

Let m=0 so y=-1

So b(0,-1).

2) Solution: Because OA=1 OB=1 AOB=90°

So ab = root number 2

3) Solution: s aob=1 2*oa*ob

Substitute the point (2,1) into the function y=x+m

The analytic formula of the m=-1 function is y=x-1

The image intersects with the x-axis and the y-axis with points A and B.

Substituting x=0 into y=-1

Substituting y=0 into x=1

So a(1,0) b(0,-1).

ab²=oa²+ob²

ab = root number 2

s△aob=1/2oa ×ob

What are you kidding, the easiest question, ask your classmates!

Insert 2n-1 positive numbers a1, a2 ,.. between 1 and 9a2n-1 makes the 2n-1 numbers an equal proportional sequence, then:

These 2n+1 numbers are also proportional, i.e., 9 1 q 2n, and the solution is: q=9 (1 2n), so that m=1,2,3,4,5......2n-1, then:

a1=q，am=q^m

The aftermath and mn of the sequence are 2n(2n-1) 2=n(2n-1).

an=a1*a2...a2n-1=q^(n(2n-1))=3^(2n-1)

Insert 2n-1 positive numbers b1, b2 ,.. between 1 and 9b2n-1, so that the smooth 2n-1 numbers into a series of equal differences, then:

The number of 2n+1 is also equal, i.e., 9 1 2n*d, and the solution is: d=4 n

b1=1+4/n，b2n-1=1+4/n+(2n-2)*4/n=9-(4/n)

bn=b1+b2+..b2n-1=s2n-1=(b1+b2n-1)(2n-1)/2=5(2n-1)

f(n)=9an+4bn+17=9*3^(2n-1)+4*5(2n-1)+17

3*9^n+40n-3

f(n+1)-f(n)=-8*3*9^n+40

8(3*9^n-5)=16(3*9^n-5)/2

Since 3*9 n is multiplied by (n+1) odd numbers, the result is an odd number, so (3*9 n-5) is an even number, so (3*9 n-5) 2 is a positive integer;

And when n=1, (3*9 n-5) 2=11 is prime, so 16 is the greatest common divisor of f(n+1)-f(n).

Therefore, the existence of m is such that f(n)=9an+4bn+17 is divisible by m, and the maximum value of m is: m(max)=16.

Inductive proof: f(1)=3*9+40-3=64=4*16;The conclusion is valid.

Assuming that the conclusion is true for f(n), then:

f(n+1)=f(n)+16(3*9 n-5) 2 is also true for the conclusion.

Therefore, it is true for all n. Proven.

The first question, choose B, because Bayi Street is perpendicular to Nanjing Road, Bayi Street is 400 meters, Nanjing Road is 300 meters, so Huancheng Road is 500 meters. Huancheng Road is perpendicular to Shuguang Road, Shuguang Road is 400 meters, and because, the angle between Xi'an Street and Huancheng Road is equal to the angle between Huancheng Road and Nanjing Street, so the two triangles are congruent, so the distance from the bookstore to the intersection of Bayi Street and Xi'an Street is 300 meters = the length of Nanjing Road, so the distance between the bookstore and the intersection of Nanjing Road and Huancheng Road is 200 meters (500-300), so Xiao Ming first walked to the intersection of Nanjing Road and Huancheng Liangyin Road 300 meters, and then walked to the bookstore 200 meters, sharing 500 meters.

In the second question, only 1, 2 in the two angles are equal may not be right angles, 3 squares are equal, the rubber banquet may be positive and negative, not equal 4, it is not specified that c is the hypotenuse.

6 ounces + 10 ounces = 1 catty.

1 ounce = gram.

6 (two) + 10 (two) = 1 (catty), in ancient times, one catty was 16 taels, and half a catty and eight taels came from this.

6 oz + 10 oz = 1 lb.

6 taels + 10 taels = 1 catty (in ancient times, 16 taels was called 1 catty).