How big is the gravitational pull of the sun and what is the gravitational pull of the sun on the ea

The mass of the Sun is about 2 10 kilograms, which is about 330,000 times that of the Earth, so its gravitational pull is also 330,000 times that of the Earth.

The most direct physical quantities that express the strength of a celestial body's gravitational field are the gravitational acceleration and escape velocity on its surface. Like Earth, the near-ground gravitational acceleration is and the escape velocity (second cosmic velocity) is .

The gravitational acceleration and escape velocity of Jupiter's surface (Jupiter is a gaseous planet, and its gravitational field is calculated based on the surface of the clouds we see with a telescope) is much greater than that of Earth. Gravitational acceleration expresses the mass-weight relationship caused by the strength of the gravitational field on the surface, specifically, if a person's weight is 98 pounds on Earth, then he will weigh it on the surface of Jupiter - note that this is weight, and the mass is constant.

The Sun is a star and is fundamentally different from Earth and Jupiter – it has a huge volume and mass. The gravitational acceleration on the surface of the Sun (photosphere) is up to 275 m s, and the escape velocity is up to 620 km s.

The gravitational pull of the Sun is 330,000 times greater than that of the Earth. According to the gravitational formula, the gravitational pull of the Sun on the Earth can reach 35 trillion tons. If an object is subjected to the gravitational pull of the Earth and the Sun, the Sun's gravitational pull on this object is twice that of the Earth.

f=g·m1·m2/r^2=。

The gravitational force between the sun and the earth is the contribution of the product of the masses and the square of the distance, and the attraction between the two satisfies the formula, which Newtonian mechanics interprets as the interaction and reaction force of these two forces, which naturally satisfies the three laws of the ox.

The gravitational effect is inversely proportional to the square of the distance. Its essence is that the gravitational effect is radially isotropic and the spherical surface is equivalent to divergence. The gravitational effect emitted by the mass substance, the sum of the sum (integral) at each point on the surface of each of the closed bodies that surround it, is the same independent of distance, that is, the sum of the surfaces of the closed body, that is, the total amount, is equal and unchanged, independent of the shape of the closed body.

Let the closed body be a sphere, then the total amount is the surface area x the components of each point, and the components of each point are the total surface area, and the surface area is proportional to the square of the distance (half longitude). The component of each point on the surface is equal to the square of the total distance.

So at each point, the gravitational effect is inversely proportional to the square of the distance.

Therefore, the gravitational effect is proportional to the mass product of both sides and inversely proportional to the square of the distance, and together with the gravitation constant, Newton's second law is obtained, the formula for the vertical gravitational force of universal land:

f1=f2=g mi mj r=gm1m2 r, equal.

The gravitational pull of a black hole is very large, and the gravitational scope is also very large, because its basic theory is that the escape speed exceeds the speed of light, and no chemical in the universe can exceed the speed of light, so people think that no chemical can theoretically escape from a black hole. But there is also a limitation, in the black hole at the center of the galaxy, its gravitational scope extends even to the entire solar system, but not all the solar system is sucked in, this is because the black hole is really not too destructive in the region, this destructive category is called the event horizon, and there are indeed no chemicals within the event horizon that can escape the black hole.

This horizon is its gravitational semi-longitude, also known as Schwarzschild radius r=2gm c 2, where g is the gravitational parameter, m is the mass of the black hole, and c is the speed of light). All chemicals that enter this gravitational half-meridian will fall into the black hole, and the mass of the Sun is not large enough to become a black hole, but it is possible to evolve into a white dwarf, and the minimum mass of a planet to become a black hole is twice the mass of the Sun.

The event horizon is the category of green leaf nets that cannot be escaped by the gravitational pull of the black hole, which exceeds the aperture of the black hole. As long as it is outside the event horizon, it is impossible to be sucked into a black hole. Naturally, it is also necessary to have a certain lateral speed, and it is not possible to stay around the horizon without moving.

The horizon is within the horizon, because the gravitational force is large, and even the speed of light cannot escape, but outside the horizon, because the distance is farther, the gravitational force is reduced, and outside the horizon, it can only escape, only the light is bent.

Therefore, this critical value is the area where the light can escape and cannot escape is called the event horizon, that is, the objects within the horizon are always invisible, so they look black, which is the definition of the black hole category, the black hole itself does not shine, does not return to light, all black holes can not be seen, but the gravitational effect of the black hole can form some electron-optical conditions, and then the black hole's wheel corridor can be displayed. If a cloud of gas in interstellar space were to approach a black hole, they would slowly approach the black hole in a spiral fashion. As the gravitational pull of the black hole accelerates, the friction between the fast-moving gas clouds diffuses strong radio waves, which create a visible accretion disk around the black hole.

Just like the gravitational pull of the earth on people, the epidemic can firmly suck people on the ground, which means that gravity is also very strong, and the gravitational force of black holes is also like this. No scientist has been able to calculate the extent of a black hole's gravity, so it could be infinite.

The gravitational pull of a black hole can engulf an asteroid with a gravitational range of 1008 covering a large area of starry sky.

The gravitational pull of a black hole is infinite, and many surrounding matter will be attracted by the black hole, and the range of gravity is impossible to estimate.

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Question 1: How strong is the gravitational pull of the sun? The magnitude of the force is related to the mass and distance of the two objects that are attracted to each other.

The greater the mass, the greater the gravitational pull. The smaller the distance, the greater the gravitational pull. The space station can float in the air because the space station rotates at a certain speed, and the astronauts are not sucked back to the ground, because the mass of the astronauts is too small, and after reaching a certain altitude, the gravitational force between the space station and the earth is too small to be basically negligible, so it is not sucked back.

Weightlessness is also due to the large distance, and the gravitational force is negligible, but it is not without gravity.

Question 2: How big is the gravitational force between the Sun and the Earth The average gravitational force between the Sun and the Earth: f=gmm r 2= ( n=

Question 3: What is the gravitational pull of the Sun on the Earth The average value of the gravitational force of the Sun and the Earth: f=gmm r 2= ( n=

Question 4: How much does the sun's gravitational pull control There are no obvious boundaries, and all objects in the solar system are subject to the sun's gravitational pull. Moreover, gravity is a long-range force, and theoretically, only if it is not infinitely far from the sun, it will be subject to the sun's gravitational force.

Question 5: What is the gravitational range of the solar system The boundary radius of the solar system is determined

1.With Pluto's orbit as the boundary, it is about 40 astronomical units.

2.According to the comet's origin hypothesis, the Kuiper Comet Belt is 50 1000 AU; The Oort cloud, which is 100,000 astronomical units light-years.

3.According to the heliopause, it is 100 160 AU.

4.The theoretically calculated gravitational range of the solar system is 15,230,000 astronomical units.

Note: 1 astronomical unit is about 100 million kilometers.

1 light year is about a kilometer.

The gravitational pull of the Sun is mainly due to its large mass, which accounts for the mass of the Sun in the entire solar system, and it is because of the strong gravitational pull that other planets orbit the Sun. Although the gravitational pull of the sun is strong, other planets also have a certain centrifugal force, so when the two forces are canceled, the planet will not be sucked by the sun.

The reason why the gravitational pull of the sun is high is because the mass of the sun is large, according to the formula of gravitational force, the greater the mass, the greater the gravitational force, and the mass and gravitational force are directly proportional. The mass of the sun accounts for it in the entire solar system, and the mass of stars in the universe is calculated based on the mass of the sun, which is the basic unit of measurement.

Because of the strong gravitational pull of the sun, other planets orbit the sun, and although the sun has a strong gravitational pull, it cannot drive the entire solar system to move. There is not only one force in the universe, such as gravity, but also centrifugal force, and the combination of various forces can make the movement in the universe uniform.

Other planets attracted by the Sun's strong gravitational pull also have a certain centrifugal force, which is the result of the balance between the forces generated by the rotation of the planets and the forces generated by the inertial motion. The gravitational pull of the sun pulls the planet in the middle, while the centrifugal force pushes the planet outward, so that the two forces cancel out the planet and do not suck it up.

If it is considered that the planets move in a uniform circle around the Sun, then the gravitational pull f of the Sun on the planets should be the centripetal force experienced by the planets, i.e.

f=mv^2/r

where r is the distance between the sun and the planet, v is the linear velocity of the planet's motion, and m is the mass of the planet.

The relation v=2 r t of the period t and velocity v in circular motion

Substituting the above equation is f=4 2(r 3 t 2)m r 2

According to Kepler's description of the laws of planetary motion, r 3 t 2 is a constant, so it can be concluded that the gravitational force between the planet and the sun is directly proportional to the mass of the planet and inversely proportional to the quadratic of the distance from the planet to the sun.

According to Newton's third law, the force of a planet to attract the Sun is equal in magnitude and has the same properties as the force of the Sun to attract a planet. Newton believed that since this gravitational force is proportional to the mass of the planet, it should of course also be proportional to the mass of the sun. Therefore, if you use m'Indicates the mass of the sun, then there is.

f∞m'm/r^2

Written as an equation, it is f=gm'm/r^2

g is a constant, which is the same for any planet.

Newton also studied the motion of the moon around the earth and found that the gravitational pull between them followed the same law as the gravitational pull between the sun and the planets.

Newton studied the gravitational attraction of many different objects that follow the same law, and further extended this law to any two objects in nature, officially publishing the law of universal gravitation in 1687

Any two objects in nature are attracted to each other, and the magnitude of the gravitational force is directly proportional to the product of the masses of the two objects and inversely proportional to the quadratic of their distance.

If m1 and m2 are used to denote the masses of two objects, and r is used to denote their distance, then, the law of universal gravitation can be expressed by the following formula:

f=gm1m2/r^2

The unit of mass is kg, the unit of distance is m, and the unit of force is used as a constant, which is called the gravitational constant, which applies to any two objects, and it is numerically equal to the interaction force when two objects with a mass of 1kg are 1m apart, and the standard slow value of the gravitational constant is g=

Usually taken. g=6367*10^-11nm^2/kg^2