Ask for ten defactoring questions, and a few more with overall thoughts, don t be too simple. To ans

Factoring xy 6 2x 3y (x-3)(y-2).

Factoring x2(x y) y2(y x) (x+y)(x-y) 2

Factoring 2x2 (a 2b) x ab (2x-a)(x+b).

Factoring a4 9a2b2 a 2(a+3b)(a-3b).

Factoring x3 3x2 4 (x-1)(x+2) 2

Factoring ab(x2 y2) xy(a2 b2) (ay+bx)(ax-by).

Factoring (x y) (a b c) (x y) (b c a) 2y(a-b-c).

Factoring a2 a b2 b (a+b)(a-b-1).

Factorization(3ab)2 4(3a b)(a 3b) 4(a 3b)2 [3a-b-2(a+3b)] 2=(a-7b) 2

Factorization(a3)2 6(a3)(a+3)(a-3).

Factoring (x 1)2(x 2) (x 1)(x 2)2 -(x+1)(x+2).

The cubic of 4a (the square of 4a - 1).

a squared - 3).

1.If x +2x is considered as a whole, x +2x can be seen as a, then the formula 1 can be seen as a +2(a+1)=a +2a+2=(a+1) +1

This is equal to (x +2x+1) +1=(x+1) 4+1 (I couldn't play x+1 to the power of 4).

2.(x-y) -y-x)+1 4 can be seen as.

y-x）²-2×1／2×（y-x）+（1/2）²

According to a-2ab+b mask modification = (a-b).

So the equation can be decomposed into (y-x-1 2).

m^2-n^2+2(m-n)

m+n)(m-n)+2(m-n)

m-n)(m+n+2)

kilograms, brother give points.

The circumference c 2 r is 2 times the product of radius and pi.

The volume of the cone v=1 3 r h.

4x²-22x+10=2（2x²-11x+5）=2（x-5)(2x-1)

a+2)(a2+4)(a-2)-(a2+8)(a2-2)

a2+4)(a2-4)-(a2+8)(a2-2)

a^4-16)-(a^4+6a2-16)

6a24a^2b^2c+12ab^3c^2

4ab^2c(a+3bc)

Verify. 4ab^2c(a+3bc)

12a^2b^2c+12ab^3c^2

a^2+b^2+c^2+2ab+2bc+2ca

a^2+2ab+b^2)+(2bc+2ac)+c^2

a+b)^2+2c(a+b)+c^2

a+b+c)^2

a^3+b^3+c^3-3abc

a^3+3a^2b+3ab^2+b^3+c^3)-(3abc+3a^2b+3ab^2)

a+b)^3+c^3]-3ab(a+b+c)

a+b+c)(a^2+b^2+2ab-ac-bc+c^2)-3ab(a+b+c)

a+b+c)(a^2+b^2+c^2+2ab-3ab-ac-bc)

a+b+c)(a^2+b^2+c^2-ab-bc-ac)

a^2(a-b)+b^2(b-a)

a^2(a-b)-b^2(a-b)

a-b)(a^2-b^2)

a-b)^2(a+b)

x+1)(x+2)

x-1)(x-2)

x-3)(x+2)

x-2)(x+3)

1.Generally, when factoring a factor, you can first look for the common factor that can be seen at a glance; When it is not easy to see the common factor, you can use the "packing method" - the so-called "packing method" refers to focusing on the big picture and forming the "big factor";

2.Try the zero-root method, substitute a specific value, and find a zero-value point by gradually approximating. If it is a higher order polynomial, it can be lowered by "short division". The so-called "short division" is to take the found zero factor as the divisor.

3.More practice is the guarantee to find the sense of the question; It is necessary to have the habit of summarizing and summarizing, and to know a certain type of question. In the future, when solving the problem, the first type, and then the method, has formed a set of effective problem-solving methods, of course, can not be too limited to a certain type of question type with a certain method, effectively achieve "multiple problems and one solution and one problem with multiple solutions".

It is generally the cross multiplication.

x^2+2x+1

x 1x 1

x+1）^2

Don't you know the formula?

First formed into ax square -bx+c=0

x=-b -4ac 2a under the root number

1、(a-b)*(a+b)*(y-x)²

5ab(b-c-5ac)

3、p(p-1)(a-1)

4、(n+4m)^2

5、a(a-2b)^2

6、(ax-8)^2

7、-(a-6b)^2

8、(2m-13n-10)^2

9、-2m(m-6)^2

10. A 2-5b 2 = (a - root number 5 * b) (a + root number 5 * b - x 2 = (root number 2-x) (root number 2 + x).