Find regular math problems and ask for the process Thank you

1/1 + 1/2-1 = 1/2

1/3 + 1/4 - 1/2 = 1/12

1/5 + 1/6 - 1/3 = 1/30

Then 1/7 + 1/8 - 1/4 = 1/56

1/2-1/6 + 1/1/12-1/7 + 1/30 - 1/8 + 1/56 =

1/1 + 1/2 1-1-6 + 1/3 + 1/4 1-2/1 - 1/7 + 1/5 + 1/6 1-3/1-1 + 1/8 + 1/7 + 1-1/8 1-4/4

1/1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/7 + 1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1/8 + 1-1/3 + 1-1/8 of 1/8

1/1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/7 + 1-1-1-1-1/2 1-1-1/3 1-1/4 1-1/6 - 1-1/7 - 1/8

1 out of 5

From the first three formulas, we can get 1 part (2n-1) + 1 part of 2n - 1 part n = 1 part (2n-1) (2n), so that the formula can be decomposed 1 56 = 1 7 + 1 8-1 4, 1 30 = 1 5 + 1 6-1 3 can be brought into the original to obtain a formula, and then decompose 1 12 according to this method to find the answer.

What are the first four graphics.

Uh: Let's see if that's okay

The first triangle: invert the digits and tenths of the numbers on the three corners respectively

Add to 75 The same is true for the second triangle: upside down to add up to 104

So the third triangle:

If you add it upside down, you get 128, and that is what you want.

128, the top is (2+4+1)*10+(1+1+3)=75, and the lower left corner is (6+2+1)*10+(2+3+9)=104

Therefore, the lower right corner is (6+2+4)*10+(1+6+1)=128

119 75 = 12 + 31 + 32 104 = 26 + 16 + 62 The remaining three numbers are 14 + 14 + 91 = 119

The answer is 210

The law is n*(n-1)*(n-2).

n is the first number.

It's hehe...

First of all, you can see if there is an additive relationship between them. For example: 2, 6, 10, 14...

Again, there is a relationship between multiplication and non-multiplication (squared). For example: 8, 32, 128, 512...

Or a few squares of x. Such as: 1, 2, 4, 8, 16....2 to the nth power) or the reciprocal to the nth power or something.

Most of the rest are quadratic functions.

Here's a trick

The judgment is a function of several times: that is, the latter number is subtracted from the previous number, and then the difference between the two is subtracted. Subtracting a few times to get the difference is equal is a function of several times. In junior high school, there are generally no more than 3 times

For example: 0 2 8 18

In total, it is subtracted twice before it is equal, so it is a quadratic function.

The above is digital.

As for the graphic ones, look at them carefully (preferably from left to right) and then convert them to digital ones. OK Problem solved

You have to look at the graph in conjunction with the graph, and generally look at the law of addition, subtraction, multiplication and division, and sometimes the graph is half of the graph or added to a graph.

To find the law on the left, we need to study the relationship between numbers and figures. For example, (the first number is multiplied by three, minus sixteen, and then multiplied by three......, the number in parentheses is 44. Now you try this:,180,1080,(

In fact, generally you find the relationship between two adjacent numbers, mainly more than the type of contact points, sometimes these problems do more, the rules are actually easier, after all, many rules are similar.

Make more connections, look at some example questions with answers, and gradually do it, which is to cultivate a feeling.

This should be observant. There are still some rules to memorize.

The first number prevails, the number next to it is its single digit, and the number below is its ten digits multiplied by the single digit.

The number below 58: (58-8)*8=400

The single digit of 69 is 9, and the following number: (69-9)*9=540

The rule is: 23*3-(3*3)=60

So, the first empty is 400, the second empty is 9, and the third empty is 540.

I think the first one should be 400, the last one has 9 above and 540 below.

(Top Left - Top Right) * Top Right = Lower number.

The first 400

The second 9, the third 540

There are many kinds of rules, and the answers are not the same, this kind of problem, you can list some equations to solve. For example, you can think of this as a*n-1 (a denotes the value of the nth-1st number, n denotes the nth number in this law): 274*6-1

Two two-digit numbers are multiplied, and the sum of the two two-digit digits is 0, and the first digits are the same, the product is equal to the product of the first digits multiplied by the sum of the first digits + 1 multiplied by 100, and then the mantissa multiplied by the product of the mantissa multiplied by the mantissa number.

For example, 11*19=1*(1+1)*100+1*9=200+9=20912*18=1*(1+1)*100+8*2=200+16=21623*27=2*(2+1)*100+3*7=600+21=621 and so on, do you understand?

Looking at it separately, 1 2, 7, 20, 1 2 to 7 increased by 13 2, 7 to 20 increased by 13, and the next one should be increased by 26, that is, 20 + 26 = 46

Then 3 and 1 2 to 10 also add 13 2, so the next one also adds 13, then 10 + 13 = 23

So the last two empty spaces are, in turn

8 17 5

The sum of each column and each row is 30

These numbers add up to 30 in any column or row! For example, the first row: 8 + 17 + 5 = 30

So the number of spaces = 30-12-16 = 2

All are 9 9 * 2 9 * 2-3 (9 * 2-3) * 2 ...So the last two empty 54-3=51 51*2=102