How should students and parents deal with the alienated Olympiad?

Because the requirement is the smallest and the whole number, A-1 is 1km, 1-2 is 2km, A-2 is 3km, and the distance between any two schools is not equal to each other, so 2-3 is 4km at least, A-3 is 7km, 1-3 is 6km, and so on, 3-4 is 5km at least, A-4 is 12km, 1-4 is 11km, 2-4 is 9km; 4-5 minimum 8km, A-5 20km, 1-5 19km, 2-5 17km; 5-b minimum 10km

a-b 30km

1 3 6 8 5 2

These sets of distances can be satisfied, and the answer is 25km

The answer to this question seems to be wrong.

My answer is 1+2+4+8+16+32=63 analysis process:

The core basis is that no two schools can be equal in distance from each other.

First, assume that the distance between A and the nearest school is 1 (then calculate the distance between the schools in the future), then 2, then it cannot be 3 (because 3=1+2), it can only be 4, then the minimum is 8 (because 7=4+2+1, 6=4+2, 5=4+1), and so on, and then 16, 32.

The whole kilometre is a condition.

Knowing the distance that someone has traveled between any two schools, then you can know which two schools are different means that any two schools are different distances, and each of the 7 schools has a 1 2 3 4 5 b

A to 1 is definitely 1 km (in a straight line, the shortest again) 1 to 2 is definitely 2 km.

2-3 Note that it is not 3 km (because A to 2 is 3 km), but by inertia, this section should be 4 km.

Then 3-4 5 km.

4-5 is not 6 km but 7 km (because 1 to 3 is 6 km) 5-b 8 km.

But there is another problem: 3 kilometers must not appear, 1 to 3 can be avoided in 6 kilometers?

Try swapping 2 to 3 and 3 to 4.

Derive a to 1 1 km.

1 to 2 2 km.

2 to 3 5 km.

3 to 4 4 km.

4 to 5 6 km.

5 to b 7 km.

1+2+5+4+6+7=25 draw a picture and see it quickly.

Olympiad training mainly depends on the teacher, and the training class likes to brush up on questions too much! My child doesn't like it very much, but now he is a first-line famous teacher and teaches very well!

In fact, the main thing is to look at the teacher of the tutorial class, the tutoring of the Olympiad must have a good math teacher to guide and improve, so that you need to take the child to listen to it in person, and personally feel the quality of a teacher, so that the psychology of the class is more down-to-earth, 100 education can be auditioned here, you can go to understand.

Jing Rui, one-on-one, I heard that there are no elementary school students in the back.

Of course, it's the Kawagoe Training School, and they really do a good job in mathematics, and they don't dare to say anything about other subjects, but the Olympiad is definitely one of the best.

Isn't there any other requirement for this question?

This code must be able to separate schools and districts, so well, it can be designed like this:

mnll where m takes 1 5, which represents different districts, nn is a two-digit number, representing the school number, and ll is also a two-digit number, which is the student number, and the student number can be according to each school.

The single digit indicates gender.

The tens and hundreds, representing the serial numbers 01 to 60

Thousands indicate the school.

The number of 10,000 indicates which district.

Mom comes home in the normal 40 minutes. The average speed is 10000 40 = 250 meters per minute and go home 6 minutes early. That is, 6*250=1500 meters.

20 minutes out of school. The average speed is 1500 20 = 75 meters without points. It takes 5000 75 = 67 minutes to go home by yourself, and 67-40 = 27 to get out of school early

23 minutes earlier.

Because my mother rides a bicycle for 40 minutes back and forth every day, I arrived home 6 minutes early today, and walked 3 minutes less each way, that is, there were still 3 minutes away when I met Xiao Zhu, and I was out of school after 3 minutes according to the usual, but at this time Xiao Zhu had already walked for 20 minutes.

There are several benefits of learning Olympiad math for primary school students.

For a student who is more than capable of learning the content of the school classroom, proper learning of the Primary School Olympiad can have the following benefits.

1. Promote the overall improvement of school performance and cultivate good thinking habits;

2. To enable students to gain psychological advantages and cultivate self-confidence;

3. It is conducive to the development of students' intelligence;

4. Mathematics is the foundation of science, and learning Olympiad mathematics is very beneficial to the student's learning of physics and chemistry after entering Orange Grade Qiao junior high school (many key middle schools recruit students who are good at Olympiad mathematics for this reason).

5. The enrollment of many key middle schools depends on whether the student's Olympiad results are excellent.

However, for a student who is struggling to learn the content of school textbooks, regardless of the current situation, the greed for more and the fastest will not only fail to learn, but may also bring negative psychological pressure; If you know that you are not suitable for learning Olympiad mathematics and do it reluctantly, you will lose your self-confidence because of it, and finally even hate learning.

Olympiad learning is a kind of intellectual game, you should do what you can, and never treat it as a burden.

It is not objective to say that the Olympiad is not good, the benefits of the Olympiad for cultivating students' mathematical thinking and developing intelligence are very obvious, and many students have risen sharply in various subjects (not just mathematics) in school after learning Olympiad, and can always be far ahead.

From the original question, it can be seen that 428 20 16 are all multiples of 4, so when the number of groups with only 25 people is a multiple of 4, the conditions can be met (think for yourself).

Set: A group of 16 went to Group X.

When the number of groups of 25 is 4: 20 people go to 24-x-4=20-x20-x) 20+16x+25 4=428 solution: x=18

When the condition is not satisfied.

So: a group of 16 went to 18 groups.

Solution: Assuming that these 24 groups are all 16 people, there should be a total of 24 16 384 (people), which is actually 428 384 44 (people) more than it

Now there is one less group of 16 people, if there is one more group of 25 people, there will be 25 16 9 more (people), if there is one more group of 20 people, there will be 20 16 4 (people) more

So the number of groups of 9 25 people 4 The number of groups of 20 people 44 Because 44 and 4 are even numbers, the number of groups of 25 people can only be even2, 4 When the number of groups of 25 people is 2, the number of groups of 20 people is (44 9 2) 4 groups).

So the number of groups in a group of 25 cannot be 2.

When the number of groups of 25 is 4, the number of groups of 20 is (44 9 4) 4 2 (groups).

At this time, the number of groups of 16 people is 24, 4, 2, 18 (groups), so a group of 16 people goes to 18 groups.

I'm wrong. The title goes like this:

A school visited the aquarium with a total of 428 students, 25 in groups, 20 in groups, and 16 in groups. I went to a total of 24 groups, and asked: How many people went to 16 groups?

The answer is the same as the brother above:

Solution: Assuming that they are all in a group of 16 people, 428 16 = and because 16 is only multiplied by a number with 3 or 8 is 8, so it is 18 groups of 16 people who are pickpocketed.

Assuming that the rest are all Chunlu brothers in a group of 20 people, then there are 20*6=120, so 16 people are 18 groups, 2 groups of 20 people, and 4 groups of 25 people.

If you are bored in a group of 16 people, you may go to 3 groups, 8 groups, 13 groups, 18 groups!! Specifically: set up a group of 16 people to go to group x, from the question, the school went to a total of 428 people, and the number of surplus sales was 8, so a group of 16 people had to go to 3, 8, 13, 18, 23, 28....Experience vertical skin game count, 16 28 448 428 so 28 and greater than 28 excluded!

23 16 388, 428 388 60, because both a group of 25 and a group of 20 people exist, so the remaining 60 people do not meet the conditions, and they are also excluded! The remaining 3, 8, 13, and 18 are verified in the same way, and it can be seen that they are eligible!! Get the results!

Assuming they are all in a group of 16, you need 428 16=

In Gyeongju, because 16 is only multiplied by the mantissa with 3 or 8 is 8, so 16 people are 18 groups, assuming that the rest are all 20 people in groups, then there are 20 * 6 = 120, so 16 people are 18 groups, 20 people are selling 2 groups, and 25 people are 4 groups.

A group of 25 must be an even number, because it is impossible to multiply 3 for a group of 16, so a group of 25 can be 50 100 150 200 250 300 350 400

The difference from 428 is 378 328 278 228 178 128 78 28

Then the sum of a group of 16 is 8

Therefore, the mantissa of the group must be 3 or 8, and the mantissa must be 48 208 268 when the mantissa is cleared of 3

The mantissa 8 is 128 288 348

Then there is a subtraction one by one, such as the middle vertical: 378-48 = 330 is not divisible by 20. Therefore, the number of ten strokes should be even.

I think that whether the mantissa is 3 or 8, the ten digits of the product are even.

Based on the above extrapolation, the answer is 3 13 23 8 18

Went to 8 groups. Solution: A group of 25 people went to Group X, a group of 20 people went to Group Y, and a group of 16 people went to Group Z.

From the meaning of the title: x+y+z=24;

25x+20y+16z=428:

So x=24-y-z

Substituting x=24-y-z into 25x+20y+16z=428 gives 5y+9z=172

So y=20, z=8

Write a program to calculate this.

If 428 people. The correct answer is:

Group of 25 people: A total of 4 groups in the morning.

Group of 20 people: 2 groups in total.

Group of 16: A total of 18 groups are sold.

Total: 24 groups.

for(int ii = 1;ii<24;ii++)for(int jj = 1;jj<24;jj++)for(int kk = 0;kk<24;kk++)int temp = 25*ii+20*jj+16*kk;

int group = ii+jj+kk;

if(temp ==428 &&group ==24){"Group of 25 people, total:"+ii);

Group of 20 people, total:"+jj);

Group of 16 people, total:"+kk);

Total:"Sell + group+"");

Because the front is 25, 20, then the number of people in the 16-person group is either 3 endings, or 8 knots, and the number of 16 is only 8 endings,,,,,, so 16 people have 3 groups or 8 groups or 13 groups or 18 groups or 23 groups,,, 3, 8, 13, 18, 23

Changsha Weichu Jingcai Education and Training School is a 5A-level teaching base dedicated to extracurricular training in primary and secondary schools, and the school is positioned as a high-end - high-end quality, high-end effect, high-end service and high-end environment. The school has always adhered to the student-oriented philosophy. Since its establishment, the high-quality teachers, remarkable teaching effect and perfect service quality have been highly praised by parents, students and all walks of life.

The school has always been committed to youth growth education, putting social responsibility and integrity in the first place, and won the "Excellent Extracurricular Counseling Education Institution" and "Top Ten Extracurricular Tutoring Institutions" in the Changsha Primary and Secondary School Extracurricular Tutoring Institutions Public Credit List and Top Ten Selection Activities. Xiangchun Road Teaching Point: No. 305 Xiangchun Road, No. 2 Workers' Cultural Palace (80 meters east of Mingde Middle School).

My child is also learning Olympiad mathematics in the palace construction Olympiad Garden. **Teacher Peng 14789936955Hope it works for you!

As far as I know, the best school in Changsha should be Gongjian Happy Olympiad School. Gong Jian Olympiad Happy Palace Department is a professional school founded by Gong Jian, a senior Olympiad teaching expert. Gong Jian Happy Olympiad is taught by Gong Jian as the bishop, and a number of excellent Olympiad teachers with rich teaching experience and Shenshu children's coaches are coached.

Years of teaching have been well received by students and parents, and enjoy a good reputation in the society, and are a well-known brand of Olympiad teaching.

Gong Jian is a member of the Mathematical Olympiad of the Chinese Mathematical Society, a member of the Mathematics Olympiad Middle School Group of the Chinese Society of Education, a master of mathematics education from Central China Normal University, and the former chairman of the Changsha Primary School Mathematics Teaching Professional Committee. In the 2008 Olympic year, the masterpiece "Junior High School Bilingual Happy Olympiad Classic Training" was awarded the first-class work of the "Asian Cup".