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Anonymous users2024-02-07These are examples, and you can do the answers by yourself after doing a good job of the questions. Example questions are good for drawing inferences from one another. Example 1
Untie. Original = (
Key to solving the problem and hints].
The commutative and associative properties of addition are used, because in combination with and sum is exactly the integer 10. Example 2
Untie. Original formula = 933 - (157 + 43) = 933 - 200 = 733
Key to solving the problem and hints].
According to the nature of subtraction to remove parentheses, the sum of these numbers can be subtracted by subtracting several numbers in succession. Therefore, the sum of questions 157 and 43 is exactly 200. Example 3
Key to solving the problem and hints].
The subtraction 998 in this question is close to 1000, we will turn it into 1000-2, according to the subtraction to remove the parenthesical nature, the original respect or formula = 4821-1000 + 2, so that it can be calculated deliciously, after the calculation is proficient, 998 becomes 1000-2 This step can be omitted. Example 4
Untie. Original = (
Key to solving the problem and hints].
Using the commutative and associative properties of multiplication, because exactly 10 is obtained, and 125 is good to be accompanied by 100. Example 5
Untie. Original = Key to Problem Solving and Hints].
According to the multiplicative distributive law, the sum of two additions is multiplied by one number, and each addition can be multiplied by this number separately, and the resulting product can be added. Example 6
Untie. Original = Key to Problem Solving and Hints].
According to the nature of subtraction to remove parentheses, the sum of several numbers can be subtracted from a number, and these numbers can be subtracted continuously, because 9123 minus 123 is exactly 9000, and it should be noted that after subtraction removes the parentheses, the original addition has now become subtraction. Example 7
Untie. Original = Key to Problem Solving and Hints].
This solution is an inverse application of the multiplicative distributive law. That is, several numbers are multiplied by the sum of a number, and the sum of these numbers can be multiplied by this number. Example 8
Untie. Original = 9999 (1000 + 1) = 9999 1000 + 9999 1
Key to solving the problem and hints].
In this problem, 1001 is treated as 1000+1 and then simplified according to the distributive property of multiplication.
Key to solving the problem and hints].
In this problem, the two-time multiplicative distributive law is used, so we should not only satisfy the success of the first simple calculation, but also continue to find a reasonable and flexible algorithm until the end of the whole problem.
Key to solving the problem and hints].
This question uses the nature of subtracting twice to remove brackets as needed. Example 11
Untie. Original = (
Key to solving the problem and hints].
The problem in this question can't be mistaken for the first time it can't participate in the calculation, so copy it down and see if there is a chance later. The result of the first calculation happens to appear, so that the second calculation can be made. Example 12
Untie. Original = 4 8 125 25
Key to solving the problem and hints].
Break 32 into 4 8, so that both 125 8 and 25 4 give a whole hundred, a whole thousand.
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