Senior 3 Chemistry Review Practice Questions with Answers .

In fact, there should be more chemistry review questions for your senior high school students, and they are more targeted.

It is recommended that you take out the papers of the previous exams and figure out the wrong questions one by one, which can be regarded as practice.

d, H2 less Cl2 more Naclo, Naclo3, electron conservation ratio 1:7, altogether.

2) 100ml volumetric flask with glass rod.

4) The amount of H+ in 20ml is concentrated in 100ml.

Finally, prepare 100ml of solution, take out 20ml to generate can be obtained so the total SO2 has. The amount of the substance of the total gas collected is. So again no2

3) Analysis: S reaction obtains, the number of lost electrons is Hno3 reaction to obtain the number of electrons lost is too little, so H2SO4 will be generated in the original product, and it can be concluded that the number of electrons transferred by S reaction to generate H2SO4 is, that is, the amount of substances that obtain H2SO4.

3) Answer: Collected gas NO2 SO2 Hypothesis III is true.

5) 3S + 14Hno3 = 2SO2 + H2SO4 + 14NO2 + 6H2O (the coefficient is directly substituted into the amount of the substance, which is reduced in approximation).

1) 4SO2 + 28NO2 + 9O2 + 18H2O = 4H2SO4 + 28HNO3 (SO2: NO2 = 1:7 reaction, write 2 reactions first, and then add).

(1)ai2(so4)3 k2so4 kai(so4)(2)ai3+ +4oh- == aio2- +2h2o[ai3+ ]== 1:4

ai3+]== mol/l

3) 3[ai3+] k+] == 2[so42-]3* +k+] == 2*

k+] == mol/l

4) The concentration of potassium ions in the solution after the reaction ==

Hello, I am Mr. Xiaoxiao, who has provided consulting services to more than 100 people, I have seen your question, and now I am sorting out the answer, it will take about three minutes, please wait a while If my answer is helpful to you, please give a thumbs up, thank you

What is the question? Which type?

Compare the heart] [compare the heart] [compare the heart].

Questions. <>

Let me see. The first line of defense is ** and mucous membranes.

Then the second space is to phagocytose and kill germs, because it is a substance that is lysozyme and phagocytic cells.

The third void is the antibody, because it is against the vaccine, and then the body produces antibodies.

Then the 4th null is characterized by a faster and more intense reaction and a large number of antibodies produced.

I hope my answer is helpful to you, and if you think my service is not bad, you can give me a follow-up and a like.

Compare the heart] [compare the heart] [compare the heart].

Then, for biology questions, then remember to go through the textbook a few times and try to memorize some important knowledge points.

Questions. <>

Cow, brother, 31.

The change in signal that occurs from the presynaptic membrane and then protrudes from the posterior membrane is a chemical signal to an electrical signal.

Group B was injected with epinephrine prepared with normal saline.

Group C was injected with the same quality of epinephrine and insulin.

Then make a note of the results.

It was concluded that epinephrine and insulin have an antagonistic effect in regulating blood glucose concentrations.

I hope my answer is helpful to you, and if you think my service is not bad, you can give me a follow-up and a like.

a.The equilibrium constant is the same for the same temperature.

b.The middle start is 1mol N2 3mol H2 The middle start is N2 H2 NH3 If NH3 is completely converted into N2 and H2 There are 1mol N2 3mol H2 in the container and the same So the volume fraction is 1 7

Algorithm: Radiate calories that are converted 1 4

There is n2 left and h2 is left to generate n2

Volume fraction: cThe reaction does not start from 0mol NH3, so the heat released q is less than dThat's right.

1） mg(oh)2 + nh4cl = mgohcl + nh3 +h2o；Absorbs water vapor.

2) It should be cooling down (I guess this).

There is no picture below, and the next one will not come out.

(1) Mg(OH)2+NH4Cl=Heating=NH4OHCl+NH3, dry ammonia.

2) Prevent the aluminum chloride in the D device from dissolving and inverting the suction device C

3) Produces a white precipitate.

4) The amounts of ammonium bisulfate and ammonium sulfate in the solid sample were x and y, respectively

According to the data in **, it can be seen that the solid sample obtained by evaporation is a mixture of ammonium sulfate and ammonium bisulfate. Sodium hydroxide reacts with ammonium bisulfate first and then with ammonium sulfate when it reacts with them.

**The first set of data indicates that ammonium bisulfate and ammonium sulfate react completely, the second set of data indicates that ammonium bisulfate completely reacts and ammonium sulfate does not, and the sodium hydroxide in the second group fully reacts.

nh4hso4+2naoh=na2so4 + 2h2o+nh3↑

x 2x x

nh4）2so4+ 2naoh = na2so4 + 2h2o+2nh3↑

y 2y 2y

115x+132y=

17x+17*2y=

x = y = the amount of ammonium bisulfate in the solid sample = 2*, the amount of ammonium sulfate = 2*

Ammonium bisulfate consumes the amount of sodium hydroxide substance =

Ammonium bisulfate reacts with sodium hydroxide to produce ammonia gas = 17g mol*

The amount of ammonium sulfate reacted with sodium hydroxide to form ammonia = (

So the amount of substances containing sodium hydroxide in 16ml of sodium hydroxide solution =

The amount of the substance of the sodium hydroxide solution used =

The amount of ammonium bisulfate-containing substances in the gram solid sample = 4*, and the amount of ammonium-sulfate-containing substances = 4*

Let the amount of sodium hydroxide consumed by the ammonium bisulfate reaction be x, the mass of ammonia produced is y, and the mass of ammonium sulfate to produce ammonia is z

nh4hso4+2naoh=na2so4 + 2h2o+nh3↑

x yx=y=（nh4）2so4+ 2naoh = na2so4 + 2h2o+2nh3↑

zz=a=y+z=