The 2006 and 2007 Hope Cup Mathematics Competition questions are urgently needed

Updated on educate 2024-03-19
5 answers
  1. Anonymous users2024-02-06

    1、。Extract the common factor.

    Score column items. Xueersi Hope Cup Public Welfare Class First Lecture Example 2 Adaptation Questions.

    3、。Find the pattern of the 5th question of the first test in 09.

    In cyclic decimals, move the dot representing the cyclic section to a new position where the number in the 2011th digit after the decimal point of the new cyclic decimal is 6, then the new cyclic decimal is

    Number theory. Find the law 6, .

    Geometric stereogram diagram.

    The third lecture of Xueersi Hope Cup Public Welfare Class is the eraser method learned.

    Training 100 Question 5.

    The diagram of the square shown in Figure 1 is filled in the serial number. Travel issues.

    Define a new operation.

    Xueersi Hope Cup Lecture 1 Example 2 Extended Questions.

    " is a new operation that stipulates: a b a c b d (where c, d is a constant), e.g. 5 7 5 c 7 d. If 1 2 5, 2 3 8, then 6 1000 is calculated

    9, A;. Percentage application questions.

    Xueersi Hope Cup Public Welfare Class Third Lecture Example 2 Extended Question: The original price is 100 yuan.

    Count. Estimates

    Geometric curved area.

    14、efgh。Geometry.

    Clocks and watches. Xueersi Hope Cup Public Welfare Class 3rd Lecture Example 5 Extended Questions.

    2012 Hope Cup Training 100 Question 52 Original Question.

    At 7:10 a.m., his mother woke up Xiaoqiang and asked him to get dressed and get ready for school. But Xiaoqiang saw that the hands of the clock in the mirror had not yet pointed to the moment of getting up. Xiaoqiang thought it was a point at that time.

    Count. Count enumeration.

    Engineering issues. Average; 221。

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  2. Anonymous users2024-02-05

    Because 3-2x > = 0

    So 3 > = 2x

    So x < = 3 2

    And because x > = m

    So 3 2 > = x > = m

    So m < = 3 2

    So, choose B

  3. Anonymous users2024-02-04

    As PD perpendicular to OA at point D, extend DP at OB at E, angle PEO=45 degrees, CE=2 from PC=2, and because OP is an angular bisector, DP=2;pe=2 2, so, oc=od=de=2+2 2

  4. Anonymous users2024-02-03

    c Grade 8 "Hope Cup" preliminaries test answers.

    1、a 2、d 3、c 4、c 5、c 6、a 7、a8、c 9、a 10、c+ 12、k>324、a, (a-3)/(a-1) ,15

  5. Anonymous users2024-02-02

    The analysis of the second test question of the 2010 Mathematics Hope Cup in the second year of junior high school is still in 2011.

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