Elementary Mathematics Encounter Problems Requires Unary Equations .

Let the distance between the two vehicles meet twice as x kilometers, and list the equation according to the distance relationship between the two encounters of car B: 54 + x + 42 + 42 = 3 * 54 x = 24 kilometers.

When they met for the first time, the two cars drove a total of 54 kilometers between AB and B, and the second time they met, the two cars drove a total of 3 distances between A and B, so B drove 3*54=162 kilometers, because they met at a distance of 42 kilometers from point A, so AB and the two places were 120 kilometers apart, and the difference between the two meeting points was 24 kilometers.

Yes, you can see by drawing a line diagram, you can also assume first, I don't think this problem is very good, he doesn't seem to say the total length, use the equation to solve!

with a one-dimensional equation.

Solve the encounter problem.

The key is to memorize the equiquantitative relation of the encounter problem, let the two velocity quantities be velocity A and velocity B, and the distance between the two is distance A, and distance B has the following equiquantitative relation:

Speed A + Speed B) Encounter Time = Total Distance;

Speed A Encounter Time + Speed B Encounter Time = Total Distance;

Journey A + Journey B = Total Distance;

Distance A Speed A = Distance B Speed B;

When solving the problem, read the question first, and after reviewing the problem clearly, determine which equivalence relation series equation to use, then set the unknowns, and then use the algebraic formula containing the unknown number mother for each quantity of the equivalence relationship.

Expression, and finally substitute the equivalent relation, you can complete the column equation, and the final calculation is simple, but you must remember to check it.

Set up the express train to meet after X hours.

Since the slow train runs for 30 minutes first, that is, hours.

So I went first. (65+85)x=

The solution is that x=9 and 47 60 are approximately equal to.

So: the express train runs 9 and 47 60 hours after the two cars meet (meet after hours).

This problem can be solved using equations and equations.

Equation: Solution: If the two cars meet when the express car is driving x hours, then the equation can be listed

65x+85x=1500-65×1|2.Simplify, get:

65x+85x=Merge similar items to get:

150x=coefficient into one, get:

x=587|60

Answer: The express bus travels 587|Met at 60 hours.

Equation: (1500-65 1|.)2）÷（65+85）=（

587|60 (hour).

Answer: The express bus travels 587|Met at 60 hours.

Set up the express train to meet after x hours.

65+85)x+65×1/2=1500

150x+150x=

x = 9 and 47 60

The express train traveled 9 and 47 60 hours after the two cars met.

Let the two cars meet after x hours From the inscription, 65 (x 85 x = 1500 The solution is x = 9 and 47 60 (about equal to Answer: After an hour two cars meet.

Solution: Set up express trains to meet for x hours. 65( x) 85x=1500 x=587 60(km) Thank you for adopting and have a great holiday.

The fast train is 20km faster than the slow car, and the slow train travels 65 more than the fast train in 30 minutes.

Idea: Then first calculate what is the 30-minute distance of the slow car, this is very simple, don't say much, and then use 1500 to subtract the 30 branches of the slow car, and then this is the distance where the slow car and the fast car will start to meet, and divide this distance by (fast speed + slow speed) to calculate the time.

Process: (1500-65 1 2) (85+65)=9 and 47 60 The equation is the same as that guy At least I can tell the problem solution idea very well Let me be adopted once Thank you!

Corrected that the pool is 50 meters, not 50 cm

A and B swim opposite each other from both ends for 5 minutes at the same time, A per second, B per second, and they swim a total of (1+ meters.

450 50 = 9 laps.

The first encounter was when the first lap was swam, and the second encounter was when the third lap was swam on the shore.

Then meet every 2 laps. So they met a total of 5 times.

I guess it's 50 meters.

They swam together. 1+ meters.

By Death Reckoning ...

The first time on the first lap.

The second time was on the third lap.

So every two encounters. So 5

Set the slow train should depart first x hours, then.

448/80=(448-60x)/60

x=28/15

That is, the slow train departs first 28 to 15 hours.

Solution: Set the slow train to depart for x hours first, then.

448/80+x=480/60

56+x=80

x=24

Set up a slow train to depart first x hours.

448/60＝448/80+x

Solution x 28 15

Set to depart first x hours:

448/80+x=448/60

x = 448 60-448 80 = 28 15 hours.

Solution: Set up the two cars to meet an hour after the express train departs.

A: The two cars met 3 hours after the express bus departed.

28 minutes = 7 15 hours.

Let's say two cars meet x hours after the express train departs.

x+7/15)*60+80x=448x=3

Encounter Questions:

1. The two cities are 308 kilometers apart, and two trains drive out of the two cities at the same time, and meet three hours later, and it is known that the speed of car A is faster than that of car B 1 3, and the speed of car B is obtained.

2. Two cars A and B drive out of the east and west at the same time, car A travels 56 kilometers per hour, and car B travels 48 kilometers per hour. The two cars met at a distance of 32 kilometers from the midpoint, how many kilometers are the east and west kilometers apart?

3. A and B start from place A and C from place B, and the three people start in the same direction at the same time, A walks 45 meters per minute, B walks 55 meters per minute, and C walks 65 meters per minute. Encounter B first, and then meet A after 2 minutes. How many kilometers are A and B apart?

1. Two cars A and B drive out of AB at the same time. A travels the whole journey of 5 11, and if A travels kilometers per hour, B travels for 5 hours. Find how many kilometers apart between the two places

2. A passenger car and a truck drove out of A and B at the same time. The speed of the truck is four-fifths of that of the bus, and after a quarter of the journey, the truck meets the bus for another 28 kilometers. How many kilometers are A and B apart?

3. A and B travel around the city, A travels 8 kilometers per hour, and B travels 6 kilometers per hour. Now the two people set off from the same place at the same time, and after B meets A, they travel another 4 hours back to the original starting point. How long does it take for B to go around the city?

4. A and B walk from A to B at the same time, when A walks the whole 1 4, B is still 640 meters away from B, when A walks the remaining 5 6, B walks 7 10 of the whole journey, how many meters is the distance between the two places of A?

5. Two cars, A and B, drive opposite each other from A and B at the same time, and go in opposite directions. Car A travels 75 kilometers per hour, and vehicle B travels in 7 hours. The distance between the two cars is 15 kilometers after 3 hours, how many kilometers are A and B apart?

A and B and you personally walk in opposite directions from A and B at the same time, 80 meters away from place A, after meeting them, they continue to move forward, return immediately after reaching their destination, and meet again at a distance of 100 meters from place A. a b How many metres apart the two places.

A train travels 168 kilometers per hour, the other train travels 176 kilometers per hour, these two trains respectively from the two stations A and B at the same time in the opposite direction, after 3 4 hours of travel is still 1 4 of the total length of each other, what is the length of the road between the two stations A and B? (Solve the problem using the proportional method.)

A and B travel opposite each other at the same speed, and it takes 8 seconds for a train to pass by A, and then 7 seconds to pass B 5 minutes later.

The express train takes 4 hours to travel from A to B, and the slow train takes 5 hours to travel from B to A. The two cars drove opposite each other from the two places at the same time, and the two cars met at a distance of 24 kilometers from the midpoint, and the distance between A and B was found.

Untie; Let this road have xkm, and the equation is listed according to the question:

2/5)x=5+7

Solution: x=30

A: The road is 30km long

Solution: Set up factory B with x people, and list the equation according to the question:

2/5)x+100=400

Solution: x=750

A: There are 750 people in factory B.

Solution: Let the ** of the turban be x-yuan, and list the equation according to the meaning of the question:

x*2+(1/2)x*2=39,6

Solution: x=13,2

1/2)x=

Answer; The ** of the pillow towel is yuan, and the ** of the head turban is the yuan.

Solution: Let the boy have x people, and the equation is listed according to the question

If there is a problem, there are more boys than the total number, and if boys make up five-eighths of the total number, the conclusion is true.

Solution: Let the boy have x people, and the equation is listed according to the question

x=(5/8)*(x+x-10)

Solution: x=25

x-10=15

A: There are 25 boys and 15 girls.

Solution: Let this bucket of water have xkg, and the equation is listed according to the problem

1 3) *x = seventeen and three-quarters - twelve and one-quarter.

Solution: x=15

Answer; The bucket weighs 15kg

1. Solution: Set up this road x kilometers.

2/5x=5+7

x = 302, solution: set up factory B x people.

2/5x+100=400

x = 7503, solution: set pillow towel x yuan.

2x+2×2x=

x = pillow towel element, headscarf element.

1) Set the road length to xkm

5+7=2/5x

2) Set the number of factory workers to x people.

Let 400 = 2 5x+100

3) Set the price of the pillow towel to be x yuan, then the headscarf ** is 2x yuan.

x+2x=4) if the boy is x then the girl is (x-10).

x=4 /5*(x+x-10)

1] Road length x, 5 + 7 = 2 5x

2] B factory y, 2 5y+100=400

3] pillow towel z, z+1 2z=

4] Total x, 5 8x+5 8x-10=x

5] I didn't understand.

Set Dad to pick up Xiao Ming in x minutes.

200x=300

x = minutes. Because Xiao Ming walks 60 meters per minute, it will be 300 meters after 5 minutes, and then find the equation, and the solution of the equation is OK.