Where exactly are the bars set up..? Is it set in the middle of the main reinforcement on both sides

Hanging bars. It is also called the second row of reinforcement, which is placed at a position of about 5 centimeters below the main reinforcement of a row, and the erection steel bar that is hoisted by tying wire is arranged on both sides of the outer edge of the compression zone of the beam to fix the stirrups.

and the formation of a reinforced skeleton. If the compression zone is equipped with longitudinal compression reinforcement, the erection reinforcement can no longer be configured. The diameter of the erection reinforcement is related to the span of the beam. Precautions Generally speaking, erection bars.

It is used to erect stirrups in the beam, almost appear in the beam above the three limb hoops, that is, the ribs on both sides are passed, and the middle ribs only have additional ribs (that is, we say the ribs), if there is no erection bar, the stirrups in the middle can not be tied, so there is a erection bar. It can also be said that the corner ribs that are not stressed are frame ribs.

It is the reinforcement that needs to be erected when the beam stirrups are multi-limb stirres, and there are detailed provisions on page 24 of the beam flat method in 03G101-1.

Erection bars. and the waist tendons are both longitudinal, that is to say, they are parallel, and the transverse reinforcement you see is estimated to be the Rachel bars of the Rachel waist tendons.

Or stirrups.

If the beam section is divided into the upper, middle, and lower parts, as the name suggests, the erection bar, as a frame of reinforcement, is located in the upper and lower parts of the beam, regardless of whether the steel bar is compressed or tensiled, including the steel bars at the four corners of the beam section, can be called erection bars.

The waist bar is the steel bar located in the middle. It usually includes the construction of waist tendons (code G when H0 is greater than or equal to 450mm) and torsional waist bars (code N).

Hello, the suspension bar is generally arranged at the intersection of the main beam and the secondary beam. In the software settings, after drawing the main beam and the secondary beam, select the main beam and click on the in-situ annotation, in the following **, the software will automatically identify the width of the secondary beam of the main beam, and then enter the number and diameter of the upper beam in the "hanging bar" column, if there are multiple secondary beams in a span can be separated by slashes. There is also a way to use the [automatic generation of suspension bars] provided by the software, and then enter the suspension bar information and secondary beam reinforcement information, and select the beam that needs to be generated, or you can select the floor that needs to be generated through the whole floor generation.

The suspension bar at the junction of the main and secondary beams is calculated, it is not a structural bar, its configuration is generally ingot-shaped, and the degree of bending is related to the height of the main beam, which can refer to the steel bar construction specification

It is determined by the shear force of the secondary beam at the junction. （p）=2/ sina

p) - shear force; RG - the first grade steel bar is 2400kg cm"2.。The secondary reinforcement is 3800

ag – additional bar area a – 45° or 60°

The suspension bars are set for shear resistance, and their number is calculated based on the shear force generated on the main beam by the concentrated load transmitted from the secondary beam to the main beam. If the shear force is not very large, it can also be solved with additional stirrups.

When there is a relatively large secondary beam resting in the middle position of the main beam, the suspension bar should be arranged in the main beam at the shelving point.

The main and secondary beam handover points are provided with hanging bars in the column and beam on the beam, and the hanging bars are arranged in the beam at the place where the concentrated stress is beared, and the hanging bars are arranged in the beam.

It would be nice to change the calculation settings to 6.

You're a cad, I want to, but I can't.

A beam is defined as a member that is subjected to flexural tension.

Force: shear force and bending moment, the span between the main beam and the main beam is too large, the secondary beam must be added to it, the force is evenly transmitted to the main beam, the secondary beam is through the main beam, that is to say, the main beam should give the secondary beam a stable environment (and the junction of the secondary beam and the main beam is a very important node area, that is, the place where the stress is most concentrated, when the secondary beam is subjected to shear force and torsional force, the secondary beam will transmit the force to the main beam, the main beam in order to strengthen the shear resistance, torsional resistance, it is necessary to set up stiffeners, that is, suspension bars or additional stirrups It is worth mentioning The effect of the stirrups is stronger than that of additional stirrups.

Because the junction of the primary and secondary beams is the place where the stress is most concentrated, especially the shear force generated by the secondary beam on the main beam, the suspension bars or additional stirrups are set to resist the shear force.

Resists lateral deformation, torsional and shear forces and increases stiffness at joints. Improve the stress state of the frame...