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Anonymous users2024-02-07Oh, the meaning expressed by the landlord is not clear, which three are divided into? How many first, second and third class places are there?
It can be done.
The 6 yuan change was taken out first, and the remaining 5 people were divided into 70 yuan.
The first, second and third prizes are at least one person per level, and there are two people left. There can be 6 types of distribution. The number of people in the first, second and third classes is different.
311 yes, 131 yes, 113 yes, or or.
221 words cannot be divided.
212 yes, 122 yes, or.
That's about that.
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Anonymous users2024-02-061 first prize, 56 yuan for one person, a total of 56 yuan.
2 second prizes, 16 yuan per person, a total of 32 yuan.
2 third prizes, 6 yuan per person, a total of 12 yuan.
Add up to a total of 5 people, 100 yuan.
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Anonymous users2024-02-05Five, six, thirty, and the remaining seventy and five parts are fine.
Seventy fifths, 0 10 10 10 40
Add 6 to each of the above groups
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Anonymous users2024-02-04One 36, one 26, two 16, one 6
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Anonymous users2024-02-03A hundred dollars is still called a bonus? Or five people?
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Anonymous users2024-02-02With so many answers, how do you use the equation? At least I didn't learn until I graduated from college. Is there a problem with the topic? Or is primary education so high-end now?
Well, I'll try to list it with an elementary school student's equation.
Since everyone's mantissa is 6, this question only needs to consider the case of ten digits. 100-5x6=70, with 70 of the tens remaining for allocation.
In the first case, the highest gear is 60+6=66, then the tens of the second gear are 70-60=10, that is, the second gear is 10+6=16, and the third gear is three 6s, that is, 66+16+6x3=100
In the second case, the highest gear is 50+6=56, then the tens of the second gear are 70-50=20, that is, the second gear is 20+6=26, and the third gear is three 6s, that is, 56+26+6x3=100
In the third case, the highest gear is 50+6=56, then the ten digits of the second gear are (70-50) 2=10, that is, the second gear is 10+6=16, and the third gear is two 6s, that is, 66+16x2+6x2=100
In the fourth case, the highest gear is 40+6=46, then the tens of the second gear are 70-40=30, that is, the second gear is 30+6=36, and the third gear is three 6s, that is, 46+36+6x3=100
In the fifth case, the highest gear is 40+6=46, then the ten digits of the second gear are (70-40) 3=10, that is, the second gear is 10+6=16, and the third gear is a 6, that is, 46+16x3+6=100
In the sixth case, the highest gear is 30+6=36, then the ten digits of the second gear are (70-30) 2=20, that is, the second gear is 20+6=26, and the third gear is two 6s, that is, 36+26x2+6x2=100
In the seventh case, the highest gear is 30+6=36, and there are two people in this file, then the ten digits of the second gear are 70-30x2=10, that is, the second gear is 10+6=16, and the third gear is two 6s, that is, 36x2+16+6x2=100
In the eighth case, the highest gear is 20 + 6 = 26, and there are three people in this file, then the ten digits of the second gear are 70-20x3 = 10, that is, the second gear is 10 + 6 = 16, and the third gear is a 6, that is, 26x3 + 16 + 6 = 100
For the sake of my hard answer, give more points, I'm going crazy.
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Anonymous users2024-02-01I just read other people's answers, and it seems that I think a little singlely.
6 is the mantissa number, 5 people are 30, and there are 70 left
These 70 points again, and the answer seems to be more than the one mentioned on the first floor.
It seems that there is no more.
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Anonymous users2024-01-31Analysis 1: The last digit of each person's bonus should be 6, and the least person's bonus should not be less than 6 yuan. 100-5*6 is equal to 30 yuan, and there is 70 yuan left.
10 yuan per person, 20 yuan left. Divide the 20 yuan among two people. At this time, there are only two grades, and then take out 10 yuan out of one of the 16 yuan and distribute it to the other 16 yuan, and the result is that there are three 26 yuan, one 16 yuan, and one 6 yuan.
Analysis 2: If 5 people are 16 yuan each, it is 80 yuan; There is still 20 yuan left, and it is divided between two other people, and these two people will get 26 yuan. At this point there are two levels.
Taking 10 yuan from one of the 16 yuan, and adding it to the one who gets 26 yuan, or the other 16 yuan, becomes three grades, so there are two results: 36 26 16 16 6 and 26 26 26 16 6, and the former result has four grades and does not meet the requirements. Therefore, there is still only one division.
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Anonymous users2024-01-302 third prizes, 6 yuan each, 2 second prizes, 26 yuan each, 1 first prize, 36 yuan, then: 2 6 + 26 2 + 36 = 12 + 52 + 36 = 100 yuan 167
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Anonymous users2024-01-29The third prize is 6 yuan for 2 people.
The second prize is 26 yuan for 2 people.
The first prize is 36 yuan for 1 person.
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Anonymous users2024-01-28100 yuan bonus 5 points, each level of bonuses have the number "6", (1) suppose there is a person bonus ten digits is 6, the single digit is not 6, then the other four people are 6 single digits, the result can not be calculated 100, so a person bonus ten digits is 6, single digits are not 6 This situation does not exist.
2) Because the situation of (1) does not exist, then the single digit of the 5 person bonus can only be 6, so the sum of the single digits of the 5 person bonus is 30, and the sum of the ten digits of the 5 person bonus is 70.
Then there are 8 ways to distribute the prize. Hope.
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Anonymous users2024-01-271 first prize, 56 yuan for one person, a total of 56 yuan.
2 second prizes, 16 yuan per person, a total of 32 yuan.
2 third prizes, 6 yuan per person, a total of 12 yuan.
Add up to a total of 5 people, 100 yuan.
It should be this.
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Anonymous users2024-01-261. The number of processing digits is 6: 100-5 6=70
2. Divided into different thirds and five numbers: 7 = 0 + 0 + 0 + 1 + 6 = 0 + 0 + 1 + 3 + 3 = 0 + 1 + 1 + 1 + 4 (starting from the smallest number).
3. So, the bonus division is )
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Anonymous users2024-01-25I. 1 46, 1 36, 3 6;
II. 1 36 2 26 2 6;
III. 1 46 3 16 1 6
a(10x+6)+b(10y+6)+c(10z+6)=100a+b+c=5,1\1\3,1\2\2,1\3\1,2\2\1,2\1\2,3\1\1,3\1\1
then x+y+3z=7, x+2y+3z=7....3x+y+z=7
and x>y>z, then there are only the above three solutions.
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Anonymous users2024-01-24The first class is 46 yuan, the second class is 36 yuan, and the third class is 6 yuan per person.
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Anonymous users2024-01-231. The number of processing digits is 6: 100-5 6 = 702, divided into different thirds, five numbers: 7 = 0 + 0 + 0 + 1 + 6 = 0 + 0 + 1 + 3 + 3 = 0 + 1 + 1 + 1 + 4 (starting from the smallest number) 3, so, the bonus division is ) Follow-up:
How do you list the formula?
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Anonymous users2024-01-22x+y+z=100, y-x=10a, z-y=10b, a+b less than or equal to, z=36, y=26, z=6 verify the first place 36 + two second place 52 + two third place 12 = 100
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Anonymous users2024-01-211. The number of processing digits is 6: 100-5 6=70
2. Divided into different thirds and five numbers: 7 = 0 + 0 + 0 + 1 + 6 = 0 + 0 + 1 + 3 + 3 = 0 + 1 + 1 + 1 + 4 (starting from the smallest number).
3. So, the bonus division is )
It is still necessary to price according to the watermark and version of the wrong coin, and one of them was auctioned for a sky-high price of more than 5 million before.
Then you can do it, 1000 yuan can only pay the store deposit, do a drop-shipping, slowly do it will always have an effect, you have to insist.
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