Math problems in elementary school only 3 questions .

Correct Answer: 1Let the speed of car A be V A, then the speed of V B is V A + 30, 10 * (V A + V A + 30) = V A * 1 + 1060, from which it is obtained that V A = 40 km hours, and the distance between the two cities of A and B = 40 * 1 + 1060 = 1100 km.

2.A = 6 B 5, B = 4 C 5

Then A: C = 6 5 * (4 5): 1 = 24:

25 So choose C3Let the number of attendees at the beginning be x, then the number of attendees will be 1x 91x 9-1)*10=x+1, and x=99, and the number of people in this unit = 99 + 11 = 110.

The answer is as follows:1

Speed difference between two vehicles: 1060-1030=30 (kilometers per hour);

The speed of the slow train is: (1060-30x10) (10x2-1)=760 19=40 (kmh);

The sum of the speed of the two cars is: 40x2+30=110 (kilometers per hour);

The distance between ab and the two places is: 110x10=1100 (km).

Because A has more than B's 1 5, then A is B's (1+1 5)=6 5, and because B is less than C's 1 5, then B is C's (1-1 5)=4 5, and C is B's 5 4

So A: C = 6 5:5 4

24:25, therefore, should choose C

Let the initial number of attendees be x, then the column formula is: xx(1+1 9)=(x+1)x(1+1 10).

Solution: x=99

The total number of people in this unit is: xx(1+1 9)=99x10 9=110 (people).

*2 meters.

2. Red pen 3*36 (3+5+4)=9.

Yellow pen 9 (3 5) = 15.

Blue pen 15 * (4 5) = 12 pcs.

3. The length of the bottom side of the cube is 3 4 meters.

Then the square volume is 27 64

The first problem is calculated by equiangular proportionality, x=2

2 Set the blue pen 4x, the yellow pen 5x, the red pen is 3x, 12x=36, then the blue 12, the yellow 15, hong 9

3 The bottom area pushes out the side length 3 4, and the volume is cubic = 27 64 cubic meters.

1.A quarter of a flat angle is equal to (one-half) of a right angle

2.A 16-meter-long wire, first used three-quarters of the way, then a quarter of a meter, and then a quarter of a meter, and there is still (m.)

3.There are one-sixth more boys than girls in Class 62, and there are six fewer girls than boys. There are (36) girls in the second class of the sixth grade and (78) in the whole class.

1. 1 4 = 45° of a flat angle; 45 ° = 90 ° 1 2. So the answer is 45° = 90° of 1 2

1-3 4) = 4 m, 4 (1-1 4) = 3 m. So there are still 3 meters left.

3、。。36 and 78 people.

1. One-half.

2. Sixteen times three-quarters minus one-quarter =

1. Solution: According to the original plan, the speed from city A to city B is v 240 6 = 40 km h.

After the breakdown, if the original plan is carried out, the time required to get from city A to city B is 6 hours.

If the car arrives in City B as originally planned, the car will travel at 120 km/h for the second half of the journey.

If you arrive in City B as originally planned, the car should pick up speed of 48 40 8 km in 12 hours during the second half of the journey.

2. Solution: Let it take x hours to catch up, and list the equation as.

12x7+12x＝54x

Solution x 23, solution: Let the speed of car A be x kilometers per hour, then the speed of vehicle B is 7 8x kilometers per hour. The equation is listed as.

Solution x 64

So the two places are kilometers apart.

Question 1: The original plan was 240 6 = 40km h (this car is a tractor) Now the situation: 120km (half walked) first, it costs 35 hours (including half an hour of repair time).

120km hours left 120

Question 2: After n hours, you can catch up:

12*7+n*12=54*n n=2

If you change to a child's thinking, it should be: 42km faster per hour, and a total of 12*7=84km has been walked, so it will take two hours to catch up.

However, I would recommend giving children algebraic thinking. Learn ahead of time.

Question 3: A: a km h

B: 7a 8 km h

The distance between the two places is S km

s=So, the velocity of A is 64 km h, and the speed of B is 56 km h, and the distance between the two places is 120*

Please give

1. Everyone didn't look at the problem, but asked how much to speed up, so it was 48-40=8

The gap to be chased by 2 is 12x7=84 that goes first, and 54-12=42 84 42=2 per hour

3 car A is 1/8 more than the car, in the hour, car A travels 52 kilometers more than the car, so when the speed of car A is 52*8 kilometers, the distance between the two places is 64*kilometers.

Question 1 There are 120 kilometers left to go in 3 hours to 30 minutes (i.e., hours), so if the speed is 80 kilometers, it is twice as fast as the original speed of 240 6 = 40 kilometers.

Question 2 The PLA has traveled 84 kilometers more than the communicators, and the communication is much faster than the PLA 42 kilometers per hour, so the time is 2 hours.

Question 3 Car A is 1/8 more than car A, and in an hour, car A travels 52 kilometers more than car A, so when car A's speed is 52*8 kilometers, the distance between the two places is 64*kilometers.

Languages organize themselves.

1 240 2 (6 2 -30 60)-240 6 = 8 kmh.

Hour 352 (1-7 8)*(1+7 8)=780 km.

1. 240 2=120 km Hour 120 km *7 (54-12).

Divide by 1 minus 7/8 of the difference to get the speed of car A is 64, then the speed of B is 64 * 7/8 = 56

Set x pots trumpet flowers Orchids are 3x pots x+3x=840 so x=210 trumpet flowers 210 pots orchids 630 pots.

Set the original box x kg 5x-15 * 5 = 2x x = 25 each box weighs 25 kg.

Tons of water saved every day.

Trumpet flowers account for 1 (3+1)=1 4 So trumpet flowers total 840*1 4=210 pots.

From the question, it can be seen that each box takes out 15 kilograms for a total of 75 kilograms, which is exactly 3 boxes, so each box of biscuits weighs 75 3 = 25 kilograms.

Total water saving tons So tons of water saved every day.

1 If the trumpet flower is x, then the orchid is 3x x + 3x = 840 x = 210

2 Suppose x kg 5 (x-15)=2x x=25 per box

3 (t.)

840 4=210 (pots) Trumpet flowers 210 pots.

5-2=3 15 3=5 (kg) Originally, each box of biscuits weighed 5 kg.

tons) average tons of water saved per day.