An 8 digit signed complement indicates a range

Updated on amusement 2024-03-17
13 answers
  1. Anonymous users2024-02-06

    The range is: 128 to 127

    According to the complement. The above conclusions can be deduced from several provisions:

    If all binary digits are 0, it means the number 0

    If the highest digit (i.e., the sign bit) is 0, it means a positive number.

    If the highest digit is 1, it means that it is a negative number, and the absolute value of the negative number.

    How much? Add 1 to each binary bit (including the sign bit) to get a binary number.

    Think of this number as an unsigned number, and its value is the absolute value of the negative number mentioned above.

    For example, binary.

    The highest digit is 1, so it represents a negative number. How much is it negative? We take all eight of its bits and get 01111111, and then add 1 to get 10000000

    Think of this number as an unsigned number with a value of 128, so 100000000 in the computer represents -128

    There are 128 8-bit signed numbers with the highest bit (i.e., the sign bit) of 1, so it can represent 128 negative numbers; There are 128 8-bit signed numbers with the highest digit of 0, but the one with all 0s represents the number 0, so only 127 positive integers can be represented in total.

  2. Anonymous users2024-02-05

    8-digit word length signed integer complement range: 1000

    0000b~0111

    1111b ground truth range: -1000

    0000b~+111

    1111b, ie.

    128d~127d

    16-bit word length signed integer complement range:

    0000b1111b ground value range:

    0000b~+0111

    1111b, ie.

    32768d

    32767d

  3. Anonymous users2024-02-04

    8 binary bits can be represented.

    states; The range of representation of 8-bit unsigned numbers is.

    0 255 of all.

    Number; The range of representation of 8-digit signed numbers is.

    128 127 of all. Number;

  4. Anonymous users2024-02-03

    The 8-digit character length original code represents the signed fixed-point decimal brightness and brightness truth range: , i.e.: -127d 128)d 127 128)d.

    8-digit word length complement.

    The range of fixed decimal places is represented by the wide sign: i.e.: -1d 127 128)d.

    Some information about the complement:

    Complement (2's complement) is a binary.

    The method of expressing the number of numbers is also a way to change the positive and negative signs of a number, which is often used in computer science. in the Taiwan region.

    It is often referred to as a double complement.

    The complement of a number is the inversion of the number (i.e., a complement or inverse code, and then add 1 to the result, which is the complement of the number). In a complement system, a negative number is represented by the complement of its positive counterpart.

    The biggest advantage of the complement system Shankai is that it can be added or subtracted, without using different calculation methods because of the positive and negative numbers. As long as one kind of addition circuit can handle all kinds of signed number addition, and subtraction can be represented by the complement of one number plus another number, so as long as there is an addition circuit and a complement circuit can complete a variety of numbered addition and subtraction, it is quite convenient in circuit design.

    In addition, the complement system has only one representation of 0, which is different from the complement system (in the complement system, 0 has two representations), so it is only necessary to compare the number once to determine whether the number is 0 or not.

  5. Anonymous users2024-02-02

    The N-digit complement indicates that the range of the Origin is:-2^(n-1) ≤x < 2^(n-1)。

    The representation range of the 8-digit complement is:-2^(8-1) ≤x < 2^(8-1)。

    The state is respectful: 128 limb x < 128.

  6. Anonymous users2024-02-01

    What is the range of 8-digit complement code?

    The range of representation of the n-digit complement is: 2 (n-1) x < 2 (n-1).

    The 8-digit complement companion is represented in the range: 2 (8-1) x < 2 (8-1).

    Foolish Difference i.e.: 128 x < 128.

  7. Anonymous users2024-01-31

    This range depends on the size of your computer's memory.

  8. Anonymous users2024-01-30

    The 8-digit complement of 15 is in the form of 11110001.

    The decimal number -15 is converted to a binary number first, i.e., -15=-(1*2 3+1*2 2+1*2 1+1*2 0)=-1111). Because the head of the jujube is to be converted into an 8-digit complement, it is necessary to make the number of digits into a multiple of 8 first, that is, to make up 4 0s at the less than 4 high positions, which is 00001111. The highest digit is 1, which is indicated as a negative number.

    i.e. 10001111.

    Then convert it to the complement number, that is, take the reverse plus 1, which is 1110000 + 1 = 1110001. Finally, bring the sign bit, which is 11110001.

  9. Anonymous users2024-01-29

    128 8 digits of the original code and reverse code.

    None of them can be represented, complement.

    It's 10000000.

    This is a special case and needs to be remembered.

  10. Anonymous users2024-01-28

    What is the eight-digit complement of 128?

    The eight-digit complement of 128 is: 1000 0000.

    The original code of 128 does not exist. Find the complement of 128, take the negative plus one, and it will not work.

    You must use the "complement definition" to find out.

  11. Anonymous users2024-01-27

    Complement Bright Burial Range: 1000 0000b 0111 1111b True Value Range: -1000 0000b +111 1111b, i.e. -128d +127d

    Note: 8-bit leak word long mode =2 8 =1 0000 0000b when [x] complement = 1000 0000b, x = [x] complement - module =1000 0000b -1 0000 0000b = 1000 0000b = 128d

  12. Anonymous users2024-01-26

    The 4-bit complement is represented in the range of -8 +7, while the 5-bit complement is represented in the range of -16 +15Therefore, the above operations must be represented by a two's complement of 5 bits or more.

    2d=+10b, and its 5-bit two's complement is 00010; +6d = +110b, and its 5-bit binary complement is 00110;

    2+6=00010+00110=01000, and 01000 is +8 5-bit complement.

    3d=-11b, and its 5-bit binary complement is 11101; -6d = -110b, and its 5-bit complement is 11010;

    3-6=-3+(-6)=11101+11010=10111, and 10111 is exactly the 5-bit complement of -9.

  13. Anonymous users2024-01-25

    The range in which an 8-bit complement can represent numbers is -128 127. The range is -128 127, which must be expressed in a complement. 10000000-11111111 means -128 to -1, 00000000-01111111 means 0-127 The 1111 of the complement 1111 is converted into the original code is 1000 0001, which is -1, and the complement is a way to represent negative numbers in binary.

    The concept of complement is introduced: the complement of a negative number is to add one to the inverse code, while the positive number is unchanged, and the original dust early code of the positive number is the same as the inverse complement. (-128) is used instead of (-0) in the complement, so the complement can be represented in the range:

    128 0 127) 256 in total. Note: (-128) There is no corresponding original code and reverse code, (-128) = 10000000).

    The so-called original code is a binary point notation, that is, the highest bit is the sign bit, "0" means positive, "1" means negative, and the rest of the bits represent the size of the value. The inverse code notation stipulates that the inverse code of a positive number is the same as its original code; The inverse of a negative number is the inversion of its original code bit by bit, except for the sign bits.

    The complement notation stipulates that the complement of a positive number is the same as its original code; The complement of a negative number is to add 1 to the last digit of its inverse code.

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