There are 10 application questions for the pursuit problem, which is difficult in the sixth grade

Updated on educate 2024-03-03
11 answers
  1. Anonymous users2024-02-06

    1. The output value of a fertilizer factory this year has increased by 20% compared with last year, an increase of 5 million yuan over last year, and how much is the value of this year?

    2. The school has a circular lawn, its diameter is 30 meters, how many square meters is the area of this lawn? If you place a pot of chrysanthemums every 1 57 meters along the perimeter of the lawn, how many pots of chrysanthemums should you prepare?

    3. Use 28 meters of iron wire to form a rectangle, the ratio of the length to the width of this rectangle is 5:2, what is the length and width of this rectangle?

    4. A bottle of oil is 4 5 kilograms, 3 10 kilograms have been used, and how many kilograms are used is exactly 1 2 of this barrel of oil

    5. A barrel of oil poured out 2 3, just poured out 36 kilograms, how many kilograms of this barrel of oil was there?

    6. A book has a total of 100 pages, Xiao Ming read 1 5 on the first day, 1 4 on the second day, and the remaining 3 days, how many pages did he read on the third day?

    7. A manuscript was originally planned to be copied in 5 days, but it was copied in only 4 days, and the actual work efficiency was improved by several percent compared with the plan?

    8. Xiaojun bought a set of discounted clothing at 72 yuan per set, which was 8 yuan cheaper than the original price. How much discount is this outfit**?

    9. At the same time, the price of two kinds of toys in the toy store is 120 yuan, one can earn 25%, and the other loses 25%. If you ** these two toys at the same time, whether it is a loss or a profit, such as a loss, how many yuan to lose, such as earning, how much to earn?

    17. Xiaohong's father deposited 5,000 yuan in the bank for current savings, and the monthly interest rate is, how much after-tax interest will he get after 4 months? How much is the total amount of principal and interest that can be recovered?

    Hope, thank you.

  2. Anonymous users2024-02-05

    1.The front wheels of a roller are cylindrical, with a wheel width of 3 meters and a diameter of meters. Its front wheels rotate for a week, how many square meters of road rolling area?

    2.Splitting a 20 dm long cylindrical piece of wood along the bottom diameter increases the surface area by 80 square decimetres. What is the surface area of this cylindrical piece of wood?

    3.A cylindrical pool, the circumference of the bottom surface is meters, the depth of the meter, and the ground meter inside the water. How many tons of water does a cistern hold? (1 square meter of water weighs 1 ton).

    4.A ** machine is sold for 196 yuan after a 7% discount, what is the original price of this ** machine?

    5.The original price of a basketball was 180 yuan, and now it is 7% off**. How much cheaper is it now?

    6.The company's actual coal consumption is 5% less than planned, saving 150 tons, how many tons of coal was originally planned?

    7.There are 80 members in the choir of Red Star Primary School, and the boys are 60% of the girls.

    8.Students make flowers. The safflower is 90% of the yellow flower, and the safflower is 15 less than the yellow. How many safflowers and yellow flowers are there?

    9.There are 20 poplars on campus, and the number of fir trees is 60% of that of poplars.

    10.A factory has already processed 80% of a batch of parts, and there are 24 left. How many parts are in this batch?

  3. Anonymous users2024-02-04

    Fast, medium, and slow cars set off from the same spot at the same time and chased a cyclist in front of them along the same road. It is known that the speed of these three cars is 80km per hour for fast cars and 60km per hour for slow cars, and the three cars take 7min, 8min and 14min respectively to catch up with cyclists. What is the speed of the middle car?

    The speed of the cyclist is x kilometers per hour.

    80-x)×7/60=(60-x)×14/60(80-x)×7=(60-x)×14

    560-7x=840-14x

    7x=280

    The speed of the car in x=40 is:

    75 kmh.

  4. Anonymous users2024-02-03

    From the question, it can be seen that the distance taken by B from the beginning of chasing A to catching up with Jia is equal to the distance taken by catching up with A and returning to point A, that is, the time taken by these two processes is also equal, so the distance taken by A in these two processes is also equal to (15-3) 2=6

    That is, B begins to chase A to catch up with A.

    A walked 6 kilometers.

    B walked 3 + 6 = 9 km.

    So the velocity ratio of A and B is 6 9 = 2 3

  5. Anonymous users2024-02-02

    The speed of the bicycle is x kilometers per hour.

    24--x)*6=(20-x)*10

    x=1424-14)*6 (19-14)=12 hours.

  6. Anonymous users2024-02-01

    Let the speed of the bicycle be x, the time that has been traveled when the three cars depart is y, and the slow car to catch up with z hours.

    x(y+6)=24×6

    x(y+10)=20×10

    x(y+z)=19z

    Get: x=14, y=30 7

    Substituting gives z=12 hours.

  7. Anonymous users2024-01-31

    1.If they drive in the same direction at the same time and meet in 72 minutes, how many meters does A and B travel each other per minute?

  8. Anonymous users2024-01-30

    AB distance is 540 meters.

    The ratio of the speed of A and B shows that A walks slower and B walks faster.

    First of all, we need to assume some situations, suppose A starts from A and goes to B; B departs from B and goes towards A.

    Then, for their second encounter, you need to consider the first scenario in two ways: after the first encounter, A continues to walk forward, but before B or meets B again. (This situation has been calculated and does not match the known data of the title, so this possibility is ruled out).

    The second type: After the first encounter, A meets B when he turns back to A and then turns back to A.

    If you need to analyze the process specifically, you can continue to come to me.

  9. Anonymous users2024-01-29

    Depending on the time, the distance is proportional to the speed.

    Yes: 7:11=420:sB.

    s B = 420 11 7 = 660m

    AB distance between two places s=(660+420) 2=540m

  10. Anonymous users2024-01-28

    There are 11 types of integer (small) number basic application problems (two-step and multi-step compound application problems are composed of these 11 basic problems):

    Relation between total and partial number: (addition and subtraction).

    the number of one part + the number of other parts of the total; For example, there are 30 boys and 20 girls, how many are there?

    Total number of parts of the number of parts of the number; For example, there are 50 students in the class, including 30 boys, and how many girls are asked.

    Compare the relationship between the size of two numbers: (addition and subtraction).

    Larger-Smaller Difference number; For example, find out how many boys are more than girls or how many fewer girls are than boys.

    Larger number - the number of the difference is the smaller number; For example, there are 30 boys and 10 more girls than girls.

    Smaller number + difference number Larger number; (Examples omitted below).

    Relation of the whole to the parts: (multiplication and division).

    The total number of copies of each copy (i.e., the average score).

    Total Number of copies per copy (i.e., including and except).

    Number of copies per serving x number of copies of the total.

    Multiplier relationship: (multiplication and division).

    The number of multiple times of the number of times of the number of times (find how many times one number is a multiple of another number).

    The number of multiples of multiples of a number of doubles (knowing how many multiples of a number is, find this number).

    The number of times x the number of multiples of multiple (find out how many times a number is).

    There are also 3 kinds of fractions (percentages), positive and negative proportional problems, simple equations, number divisibility problems, and geometric ...... to find perimeter, area, and volume

  11. Anonymous users2024-01-27

    The hound found a running hare in front of it 10 meters away, and immediately chased after it, the hound has a large slow step, it runs 5 steps, the rabbit has to run 9 steps, but the rabbit moves fast, the hound runs 2 steps, the rabbit can run 3 steps, and asks the hound how many meters to run at least to catch up with the rabbit.

    Solution: From "the hound runs 5 steps, the rabbit runs 9 steps" and quickly knows that when the hound is a meter per step, the rabbit is 5 9 meters per step. From the "hound runs 2 steps, but the rabbit can run 3 steps", it can be seen that at the same time, the hound can run 2a meters, and the rabbit can run 5 9a 3 5 3a meters.

    Thus, it can be seen that the speed ratio of the hound to the rabbit is 2a:5 3a 6:5, that is to say, when the hound runs 60 meters, the rabbit runs 50 meters, and the difference of 10 meters is just after the chase.

    A: Hound runs at least 60 meters to catch up.

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