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1.Silver chloride is a strong electrolyte that is difficult to dissolve and can only react with iron at high temperatures and without water.

2.When the solubility of two substances varies greatly with temperature.

3.Clarified lime water (Ca(OH)2) reacts with NaOH to form Ca(OH)2 microsoluble, so there is precipitation, and due to the alkalinity of the clarified lime water, the litmus turns blue, and there is no reaction with HCl.

4.Reactive metal oxides react with water to produce oxygen.

cao+h2o=ca（oh）2+o2

Just think about the reaction of Na2O with water, O(O....

1 No, you can't. 2. Looking at the rate of change of the dissolution curve, the two should be very different before they can be purified by cooling crystallization.

3 HCl + clarified lime water Invisible phenomenon NaOH + clarified lime water solution turbidity litmus +

The aqueous solution of clear lime turns blue.

4 Water and calcium oxide are exothermic when they react in a beaker, and the gas is H2O

1 No, you can't. When the solubility of 2A is small, A is in a saturated state, and B has a large solubility and is not saturated, so it must be constantly filtered out to check whether there is B in the product

3 two identification method, HCL, NAOH and litmus are mixed with each other, the two species that can change color are NAOH and litmus, the other is HCL, and the two kinds of discoloration react with the clarified lime water respectively, the liquid is not discolored is Naoh, and the purple is litmus.

4 h2o cao ca(oh)2 heat The heat energy released makes the air expand, and the balloon naturally becomes larger and pulls.

Each smallest ring possesses an average of 1 oxygen atom.

Since each silicon atom is shared by 12 rings, each ring only occupies 1 12 of the silicon atom, and because there are 6 silicon atoms on each smallest ring, the average number of silicon atoms possessed by each smallest ring is: 6 * (1 12) = And because SiO2 crystals are made up of silicon atoms and oxygen atoms press 1:

2, so the number of oxygen atoms is one.

Looking at the structure of crystalline silicon first, the structure of silicon dioxide can be seen as formed without inserting an oxygen atom into the silicon bond.

Since each silicon silicon bond is shared by 6 smallest rings. So in the silica structure: each oxygen atom is shared by 6 minimum rings, each smallest ring accounts for 1 6, and 6 oxygen atoms can be counted in a minimum ring.

So the number of oxygen atoms possessed by each minimum ring is: 6 * 1 6 = 1

One should be counted, and the other should be evenly apportioned. The second floor answered well, if you can't think of it, make a model yourself, count.

What is the red substance in the product of copper oxide reduced with carbon?

fe2o3+3co=2fe+3co2

The oxidizing agent is Fe2O3

The reducing agent is CO

The oxidation product is CO2

The reduction product is Fe

The ratio of the quantity of the substance is the ratio of the coefficients before the reaction.

Look at the gains and losses of electrons.

Fe2O3 + 3Co == 2Fe + 3CO2 Oxidant Reducing agent Reducing product Oxidation product.

fe2o3 + 3co= 2fe + 3co2

Oxidant Reducing agent Reducing product Oxidation product.

The ratio of the quantity of matter is 1:3

The valency of iron in iron oxide is +3, and the valency of the reduced iron is 0, so iron oxide is the reduction product of oxidant generation, the carbon in carbon monoxide is +2, and the carbon dioxide carbon produced is +4, so carbon monoxide is a reducing agent carbon dioxide is an oxidation product.

Therefore, the amount of the oxidant to the reducing agent is 1:3

The amount of oxidation products to the reduction product is 3:2