Can you tell me the answer to your question, why some IP addresses can t be aggregated?

For example: the range is 0-63; The range is 64-127; The range is 128-191, and the first two can be aggregated into a range of 0-127 (subnet mask Luzi.

One less place, double the address).

If the third one is included, then it can only be 24, so that it is included, and if 192 26 is used somewhere else, there may be conflicts. Aggregate the last two first, and the result will be 24.

IP address. Aggregation is the merging of two small networks into one large network, mainly by modifying the subnet bits. In layman's terms, it is combined into one network segment.

To calculate the address after the IP address is leaked before aggregation, in fact, it is to compare the network prefixes of several IPs, how many bits are in the same part, and how many bits are the aggregated IP.

For example, a routing table.

There are 4 routing entries with the same interface and their destination network addresses.

a：b：c：d：

Analysis: The same parts are, a total of 16 bits are the same, and the 3rd group is replaced with binary. Compare again:

The comparison shows that the total 19 bits are the same, then, the aggregated IP (network prefix) is, that is, because there are 19 bits the same, the subnet mask network number is 19 bits, so it is, so choose C answer.

The big brother who was adopted, according to you, can't aggregate anything, which means that it can't be aggregated, and the aggregation result is included according to your statement.

The range is 0-63

The range is 64-127;

The range is 128-191

The first two can be aggregated into a range of 0-127If the third one is included, then it can only be 24, so that it is included, and if 192 26 is used somewhere else, it may conflict.

Aggregate the next two first, and the result will be 24

There is nothing wrong with the two upstairs, the situation is different, the strategy is different.

If an organization gets an IP address and designs the network by itself, the address is divided from top to bottom, so it must be aggregated.

However, if you look at it from the outside, if you don't know whether that organization has a whole IP address, you can't aggregate the unused addresses.

， ，000000/26

Aggregation is to find the same number of bits, the first and second first 26 bits are the same, can be merged into, this and the third cannot be merged.

Available addresses. 25 is 2 7-2 = 128-2 = 126

128's is 2 6-2 = 64-2 = 62

Altogether for 188 available.

Which why can't it be compared with the third (*.).128) Aggregation? The reason is that the original IP address is 26, and the number of hosts is 2 6=64, so the first (*..)

0) with the second (*..)64) can be aggregated within the same network segment. And the third (*..)

128) is assigned to the next network segment, so it cannot be aggregated.

The answer is to change the binary, IP binary after running the operation with. Get.

Change IP. The mask is the same number of digits in front of the IP binary. 22,,, the answer isExtended MaterialsIP address translation.

Every host on the Internet has a unique IP address. The IP protocol uses this address to pass information between hosts, which is the basis for the Internet to function. The length of the IP address is 32 bits (there are 2 32 IP addresses in total), divided into 4 segments of 8 digits each, expressed in decimal numbers, each segment has a range of 0 255 digits, and the segments are separated by periods.

For example, an address can be thought of as two parts: a network identifier number and a host identifier, so an IP address can be divided into two parts, one is the network address and the other is the host address. IP addresses are divided into 5 categories: A, B, C, D, and E, and they are applicable to the following types: large networks; medium-sized networks; small networks; multi-eye addresses; Spare.

Commonly used are B and C.

Resources.

When aggregating IP addresses, select the smallest IP address for aggregation. These IPs will be summarized in the routing table in the future, and you should know the next 22!! It's the mask that gets longer, it's VRML, if you don't think you understand, you can split these 3 IP addresses and split them into 1 1 in hexadecimal system.

And then you will get the result of your own manual summary will also look like this!!

Swap binary, IP binary after running with the operation. Get.

Change IP. The mask is the same number of digits in front of the IP binary. 22,,, the answer is

The answer is right. After binary, the first 22 bits are the same as the network bits. CIDR stands for classless inter-domain routing, which aggregates small networks into large networks.

There is a benefit to saving addresses. It turns out that the broadcast address and network address in the network have become usable host addresses. Because their host bits are no longer all 0s and all 1s after aggregation.

Therefore, after the aggregation network, only the network address and the broadcast address cannot be used as the host address.

are the two subnets drawn from ;

Rather, it is a subnet drawn out of ;

These three themselves belong to two different subnets, so the first two can be aggregated, and the latter cannot be divided.

After aggregation, the number of IP address blocks is 2(32-26)-2=62, wherein all 0s and all 1s cannot be used, and the number of available addresses is 2(32-27)-2=30 if they cannot be aggregated. So the total number of addresses available is 62 + 30 = 92.

That's the answer.

But I don't think I think all three can be aggregated: the number is 126

There are different versions of the answer to this question, but I think it should be 126

Because the difference among the three addresses is the last 8 bits. The binary of the last 8 bits in the first address is 00000000, the last 8 bits of the second address is 00100000, and the last 8 bits of the third address are 010000000

To aggregate three binary numbers, you need to find the same bit as the network bit, and only the first bit is the same in the problem, that is to say, the network address after aggregation has 25 bits. Then the host address takes up 7 bits. There are 2 to the 7th power, which is 128 IPs, but there is a network address in these 128 bits, and a direct broadcast address cannot be assigned, so the assignable IP index is 126

0 = 00000000

The sum of the three numbers is 0.

Method 2: 28 here is the number of subnet masks 1, and IPv4 subnet masks are 32 bits.

The conversion of the mask to binary is 1111 0000, which is simplified. The mask of 28 in the question is converted to 1111 0000 in binary

The available IP addresses under the subnet mask are the inverse part of the code, that is, 0000, and the available IP addresses are 15 addresses after removing the starting address. Add 15 available addresses and add 15 IP addresses.

I'm confused with the landlord.。。