Grade 6 math problem, urgently know the surface area and diameter of a cylinder, find the volume

Bottom round area: 1*1*

Side area: Ground circumference: 2*

Height and length: volume = 3*

From the diameter of the bottom surface, it can be found that the bottom area is a square decimeter.

The side area can then be found.

The circumference of the base is.

It is possible to find the height.

Then you can find the volume.

The base area multiplied by the height multiplied by 3 equals.

2 2 = 1 radius.

1*1* bottom and cover area.

Side area. Height. 1*1*cubic decimeter).

The formula for cylindrical surface area is: s=2 rh+2 r2

And r=2 2=1, substituting the above equation to get h=3

So the volume v = r 2 * h = cubic decimeters.

The formula for surface area is 2 r*h=2* r*h=4 r=1

H=4 is obtained with a volume of r*r*h

Substitution data: r*r*h=

First, calculate the perimeter of the bottom surface from the diameter of the bottom surface.

The height is then calculated from the bottom circumference and surface area.

Then use the diameter to calculate the bottom area.

Multiply the area in use by the high volume.

Volume is base multiplied by height, divided by 2 = high, and multiplied by volume!

2 divided by 2 radius.

Square into 2 and subtract the preceding one.

Divide by 2 to get high.

2 2 = 1 radius.

1*1* bottom and cover area.

The height of the side area is 1*1*cubic decimeters).

The base area is 100 5 = 20, so the original volume is 20x20 = 400 (cubic meters).

Dizzy: Look at the book yourself, it's all in the book.

1 base area formula r square side area 2rh volume is r square h2 r square = 2rh

That is, r=h

r2 r=

r cubic = 8

r=2 then surface area.

Practice the rest on your own.

In the first question, let the radius of the bottom surface of the cylinder be r and the height of the cylinder be h, then its side area is equal to the sum of the two base areas.

2（πr*r）=2πr*h

r=h, the volume of the cylinder is cubic decimeters.

r*r*h=

r = 2 cylinder surface area s = 2 ( r * r ) + 2 r * h = the other 2 questions are similar.

The radius is x, the high position y, the subsoil area = x*x*pai, the side area = 2*x*pai*y, and the volume = x*x*pai*y

1:2*x*x*pai=2*x*pai*y->x=yx*x*pai*y=>x*x*x=8->x=y=2-> surface area = square decimeters.

2: x*x*pai=2*x*pai*y->x=2yx*x*pai*y=>x=2,y=1-> surface area = square decimeter 3:2*x*x*pai*y->x=y2*x*x*pai+2*x*pai*y=>x=y=2-> volume = cubic decimeter.

Let the radius of the bottom surface be x and the height be y

x2 multiplied by y=volume.

2πy=2πx2

Bring it yourself.

Let the radius of the bottom surface be x and the height be y

x2 multiplied by y=volume.

2πy=2πx2

The side area can be calculated as a variable rectangle, the length is the perimeter of the base, the height is the height of the cylinder, the volume is the base area * the height, and the surface area is equal to the sum of the three surface areas, which should be calculated.

Circumference of the bottom surface of the cylinder = cm).

The bottom area of the cylinder is s=(cm).

Cylinder volume v=cm).

Let the diameter of the cylinder be d, the height will be reduced by 2cm, and the reduced surface area will be s= d* h=

So d = 3cm, so volume v = r2 * h = cubic centimeter.

I found that the base area of the box is equal to half of the cylinder (side area), and the height of the box is equal to the radius of the cylinder. Thus, the volume of the cylinder = (half of the side area of the radius).

1 2 6 square decimeters).

The base area of the box is equal to half of the cylinder (side area), and the height of the box is equal to the bottom radius of the cylinder. In this way, the volume of the cylinder = (3).

Side area. High; base area; High;

1.Correction: The sum of their surface areas is greater than the surface area of the original cylinder.

2.A cube with a side length of at least 6 cm is required.

3.The floor area of this pool is square meters. The area of plastered cement is square meters.

1.The sum of the surface areas is greater than the original area.

Let the bottom area of the large cylinder be S1, the side area is S2, the original area is (S1) 2+S2, the bottom area of the small cylinder is the same as the large cylinder, and the sum of the side areas is the same as that of the large cylinder (the large cylinder is cut into two, in fact, two circles are added) The new area is (S1) 2 2+S2

3.Covers an area of 9 cement area of 21

1. False, the sum of the surface areas of the two cylinders is large, and there are two more base areas.

2. The edge length is slightly greater than 6cm

3. Covers an area of square meters of plastered cement.

The first question is wrong.

The answer to the second question is 216

The third question is the area of the three bottoms in the plus side.

The first question is wrong because there are two more base areas.

One wrong, two 216 three bottom area in the plus side area.