The total power of 380V is about 100KW machine

Depending on how you wiring the wire, the following is the ambient temperature of 40, the situation when laying through the pipe, about 75 square copper wire is the critical value, and then you have to use the welding machine and other attacks, so you should take a slightly larger, mind 95 square meters. I don't know what a 2-phase device is, but it should be connected to the 3-phase device separately to keep the 3-phase balance, because you have a three-phase unbalance, so there is a voltage on the neutral line. It should not be big, the specifications can be selected to be smaller, personal opinion, I don't know if it's right or not, just for reference.

To add, those you said are called single-phase power supply, a phase wire and a neutral wire, two-phase power supply refers to the two phase wires (such as small welding machines) leakage switch depends on how you choose the configuration, if you use the leakage protection switch seat as a switch, the current level is 400A, the setting current is 300A, and the decoupling current is 75mA or greater. If you use leakage for the shunt, the main switch can be switched with a knife switch or opened empty. Then the trip current of the shunt can be selected as 30mA.

It is best to use three-phase five-wire paper for the line. Because you have more jog tools in it. It is still necessary to add a protection line to improve the sensitivity of the leakage protector.

With 3 * 120 + 1 * 70 cables, other single-phase equipment wiring as far as possible average, the main switch with residual current protection 250A four-pole circuit breaker, its single-phase equipment switches are used leakage switches.

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Hello dear and happy to answer for you. 380V is equal to kilowatts, that is, voltage, three-phase electricity must know the working current, in order to calculate the power W. "Volt"is a unit of voltage"tile"are units of electrical power, which are related to each other, but cannot be equal to each other.

Power = voltage * current, only when the voltage is known, the value of the current can be calculated as power. For example, if the voltage is 380V and the current of 1A is 380*1=380W.

I hope mine can help you and have a great day.

A voltage of 380V is a kilowatt current.

Use the formula: answer type p=iu, i=p u=1000 380=. In a DC circuit (or a resistive load in an AC circuit), power p = voltage u current i.

Power refers to the work done by an object per unit of time, i.e., power is a physical quantity that describes how fast or slow work is done.

Single-phase (two-wire) voltage of 380V (such as electric welding machine, when power factor.

For 1, one kilowatt is equal to amperes;

Three-phase (three- or four-group) 380V voltage (such as electric motor), when the power factor is 1, kilowatt is equal to ampere. The actual power factor is less than 1, so the actual current should be larger than this value.

Only the voltage is given, the power cannot be calculated, and the current value also needs to be known.

380V is equal to, that is, 380W.

380V is the voltage, and the three-phase electricity needs to know the working current in order to calculate the power W. However, volts are units of voltage, and watts are units of electrical power, and they are related, but they cannot be equal to each other. Because, power = voltage * current, power can only be calculated if you know the values of voltage and current.

For example, if the voltage is 380V and the current of 1A is 380*1=380W, it is.

Formula for calculating electrical power:

1. According to the definition of electric power, if the electrical energy W (unit J) consumed in such a long time as t (unit S), then accompany the side.

The electrical power of this appliance is p=w t (definition). This formula is mainly applicable to known electrical energy and time to find power.

2. The electrical power is equal to the product of the voltage at both ends of the conductor and the current passing through the conductor, that is, p=ui, this formula is mainly applicable to the known voltage and current to find the power.

3. In a pure resistance circuit, the definition can be deformed to obtain p=u 2 r, which is generally used to solve the electrical power for parallel circuits or a variable in voltage and resistance.

4. In a pure resistance circuit, the definition can be deformed to obtain p=(1 2)*r, which is generally used to solve the electrical power in a series circuit or a variable in the current and resistance. <>

800kw=80 0000w

1 kW = 1000 watts; 1 MW = 1000 kW. In daily life, kilowatts are commonly used as the unit of punching fingers. 1kw is 1 kilowatt-hour of electricity, that is, 1 kilowatt-hour = 1 kilowatt-hour = 1 kilowatt-hour 1 hour = 1000 watts 1 hour, that is, 1000 watts (W) of electrical appliances, with an hour's electricity consumption is one kilowatt-hour of electricity.

Kilowatts, which were the power units of electricity in the early days, now have a tendency to extend to the power units of the entire field of physics. Electrically, kilowatt-hours are exactly equal to degrees, but the names are different. Watt is the unit of power in the International System of Units.

Watts are defined as 1 joule second, the rate at which energy measured in joules is converted, used, or dissipated per second. In the electrical unit system, it is volts multiplied by amperes per a, referred to as 1 volt-ampere.

Summary. Hello dear, I'm glad to answer for you Is the motor power 300 watts and the output power 80 watts correct? A:

The so-called output power is actually an energy value provided by a device or electrical appliance to the outside world in a certain period of time. For example, if an electric motor outputs a fixed amount of power to the outside world for a fixed period of time, then the tool is called output power. Of course, there is actually some difference between the output power and the actual output power of the motor, because when the power is output outward, there will be some power loss.

Under normal circumstances, the maximum output power of an electrical appliance or motor should be lower than the load capacity of an electrical appliance.

Is it correct that the motor has a power of 300 watts and an output power of 80 watts?

Good. Hello dear, I'm glad to answer for you Is the motor power 300 watts and the output power 80 watts correct? A:

The so-called output power is actually an energy value provided by a device or electrical appliance to the outside world in a certain period of time. For example, if an electric motor outputs a fixed amount of power to the outside world for a fixed period of time, then the tool is called output power. Of course, there is actually some difference between the output power and the actual output power of the motor, because when the power is output outward, there will be some power loss.

Under normal circumstances, the maximum power of an electrical appliance or motor should be lower than the load capacity of an electrical appliance cover.

The gap between the power of this motor and the output power is too big, is it a bit of a false standard?

Yes, 2 pro. The motor heats up in less than a minute.

The motor is particularly hot after a while, the reason is the overload phenomenon of the motor, and the power supply should be pulled off immediately, the cause should be checked, and the fault should be eliminated.

How much power is a 380v motor 16.

Hello, the power of the motor can be calculated by the following formula: power = voltage 2 impedance, where the voltage single dismantling position is volt bucket (v), the impedance unit is Euro Liangmu ( ) and the power unit is watt (w). So, based on the data you provided, the power of this motor is:

p = 380 2 16 9045 watts (W) So, the power of this motor is about 9045 watts.