Solve the equation Solve the equation 4 x 1 2 x 11

Equation 4 x + 1-2 x =11

Can be reduced to 2 2) x + 1-2 x =112 (2x)+ 1-2 x =11

2^x)^2+｜1-2^x｜=11

Let 2 x=y, then the equation is .

y^2+｜1-y｜=11

When 1-y 0, it can be turned into.

y^2+1-y=11

y^2-y-10=0

Solution. y1=(1+41) 2,y1=(1-41) 2(round off) solution 2 x=(1+41) 2.

x1 = log is the logarithm of 2 (1 + 41 under the root).

When 1-y 0, it can be turned into.

y^2-(1-y)=11

y^2+y-12=0

Solution. y3 = 3, y4 = -4 (rounded).

Solution 2 x = 3.

x2=log, with 2 as the base 3 logarithm.

4^x+|1-2^x|=11

Move the item to |1-2x|=11-4x

Then there is 1-2x=11-4x or 1-2x=-(11-4x) to get x=5 or x=2

Since x=5 is not on topic, it should be discarded.

So x=2

1.1-2 x>=0 i.e. x<=0, there is (2 x) 2-2 x-10=0, resulting in 2 x=(1 + root number 41) 2

x is the logarithm of 2 (1 + root number 41) 2, and since x<=0, there is no solution to this situation.

2.1-2 x<=0, i.e., x>=0, there is (2 x) 2+2 x-12=0, and 2 x=3 is obtained

x is the logarithm of 3 with 2 as the base.

When x>0, 2 x>1

So |1-2^x|=2^x-1

So 4 x+|1-2^x|=11

4^x+2^x-1=11

Let 2 x=t, so t>0

t^2+t-12=0

t=3 or t=-4 (discarded).

So x=log2 (3).

When x>0, 2 x>1

So |1-2^x|=1-2^x

So 4 x+|1-2^x|=11

4^x+1-2^x=11

Let 2 x=t, so t>0

t^2-t-10=0

t=(1+√41）/2

x=log2 [(1+√41）/2]

Let 2 x=t>0 , 4 x=t 2>0

Original = t 2+|1-t|=11

Then t 2-t-10=0 or t 2+t-12=0 gives t=(1+41 or t=3

So x=log2[1+41 or log2 3

4^x+|1-2^x|=11

Move the item to |1-2x|=11-4x

Then there is a good band 1-2x=11-4x or 1-2x=- (which is greater than 11-4x) to get x=5 or x=2

Since x=5 is not on topic, it should be discarded.

So Euchroe x=2

Summary. Solve equation 12-(x+4)=2(x-1)12-(x+4)=2(x-1)12-x-4=2x-2-x-2x=-2-12+4-3x=-10x=10 3

Solve equation 12-(x+4)=2(x-1).

Solve equation 12-(x+4)=2(x-1)12-(x+4)=2(x-1)12-x-4=2x-2-x-2x=-2-12+4-3x=-10x=10 3

So, if we solve equation 12-(x+4)=2(x-1), we get that x=10 3 is the numerator on the left and the denominator is <> on the right

1-2(x-1)=1+(x+2)

How to calculate this question.

1-2(x-1)=1+(x+2)1-2x+2=1+x+2-3x=0x=0

2 (x-2)+4 x=11 x(x-2) multiplied by x(x-2) to get 2x+4(x-2)=112x+4x-8=116x=8+116x=19x=19 6 test sharp fluid: x=19 6 substitute into the left side of the original equation = 2 (19 6-2)+4 (19 6)=2 (7 6)+4 (19 6)=12 7+24 19=12*19 133+24*7 133=396 133 right edge = 11 [19 6*(19 Hyo Ki Bi 6-2)...

The solution is as follows: 12+x x 1 4

4 (12 + x) = x (according to the properties of the fractional equation, the numerator and denominator are cross-multiplied, and the equation holds)

48+4x Remnant Shirt X

48+3x＝0

x -16 Finally, the result of x is substituted into the original formula. The design is correct.

That's how to solve this equation. Hope it helps. acres of ruined brigades.

12+x x=1 round limb 4 How can this equation be solved?

This equation does not hold up.

The unknowns are canceled out. That's right!