Please use the elementary school equation to solve, and the elementary school solution equation to s

This question does not need to be solved with equations.

240 190) 2 25 (square centimeters) ......240 190 is to add the area of the two bottom surfaces, so, 25 is the area of the bottom surface.

Because: 5x5 25

So the bottom side of the original cuboid is 5 cm long.

The height of the original cuboid is:

190 25x2) (5x4) 7 (cm) So, the volume of the original cuboid is: 25x7 175 (cubic centimeters) I hope these can help you, if you are satisfied with the answer, please be timely, thank you.

Let the square side be x centimeters.

2x 2 = 240-190 = 50 square centimeters.

x = 5 cm.

v = (190-2 25) 4 5 25 = 175 cubic centimeters.

Solution, speed

Let the sides of the square be x centimeters.

Then: 2x squared = 240-190 = 50 square centimeters.

Find: x = 5 cm.

Then: the volume of the original cuboid = (190-2 25) 4 5 25 = 175 cubic centimeters.

The bottom square area is 25 square centimeters, and the side length is 5 centimeters.

The height is 7 cm.

25*7=175 cubic centimeters.

Find such a box, cut any parallel bottom surface, and you will find that the area of the two cuboids is two more than the area of the original cuboid.

Bottom area = (240-190) 2 = 25 then the bottom edge length is 5cm.

Side area = (190-25*2) 4 = 35cm Cuboid volume = Side area * Edge length = 35 * 5 = 175cm If you are not satisfied with the answer to the cold tomb and what answer do you want? Is there a 2-element equation in elementary school?

The techniques for the fifth grade of primary school are as follows: 1. Solve equations based on the relationship between the parts in addition.

2. Solve the equation according to the relationship between the parts in subtraction In subtraction, it is decelerated = difference + subtraction. 3. Solve the equation according to the relationship between the parts in multiplicationIn multiplication, one factor = product another factor. For example:

List the equations and find the solution to the equation. 4. Solve the equation according to the relationship between the parts in the division. After solving the equation, it is necessary to verify that the solution is true through a test.

To see if the number on the left side of the equation is equal to the number on the right side of the equation, the value of the unknown number is substituted into the original equation. If the numbers are equal, the value is the solution of the original equation, and if the numbers are not equal, it is not the solution of the original equation. An equation is an equation that contains unknowns.

It is an equation that expresses the equality relationship between two mathematical formulas (such as two numbers, functions, disturbance unions, operations), and the value of the unknown number that makes the equation hold is called the "solution" or "root". The process of finding the solution of an equation is called "solving an equation". By solving the equation, you can avoid the difficulty of reverse thinking, and you can directly list the equation containing the quantity you want to solve.

Equations come in many forms, such as binary equations, etc., and can also be formed into a system of equations to solve multiple unknowns. In mathematics, an equation is a statement that contains an equation of one or more variables.

Solving the equation involves determining which values of the variable make the equation true. Variables are also known as unknowns, and the value of the unknowns that satisfies equality is called the solution of the equation.

What grade are you?

Equal to x = 30 minus 6x equals 12

30-6x=12

x=plus equals.

x = 7 times more.

x = less than a multiple of a number.

Let's say: This number is x.

x = 212 chickens in my aunt's house, 44 more than 3 times the number of ducks, and how many ducks.

Set: Duck x only.

3x+44=212

x=56A: 56 ducks.

Make a rectangle with 44 cm of wire, to make the length is 14 cm, then. How many centimeters is wide.

Set: The width is x cm.

2（14+x）=44

x = 8 A: The width is 8 cm.

Chickens and rabbits in the same cage, chickens are 13 less than rabbits in the Ming banquet, chickens and rabbits have a total of 262 legs, Zhaohuai Nian chickens and rabbits have how many legs.

Set: If there are x chickens, then rabbits have (x+13), chickens have 2x legs, and rabbits have 4 (x+13) legs.

2x+4（x+13)=262

x=352x=70,4(x+13)=192Answer: Chickens have 70 legs and rabbits have 192 legs.

Add 2/5 to a number and subtract 1/4 to result in 17/20, find out what this number is. [Solve with equations]. How to solve.

The basis for solving equations in elementary school: the basic properties of equations.

The basic property of the equation: the same number is added or subtracted from both sides of the equation at the same time, and the equation still holds.

For example: x+12=50

Solution: x+12-12=50-12

x=38

The principle of solving elementary school equations is mainly based on the principle that "both sides of the equation are added and subtracted or multiplied and divided by the same number (except 0), and the equation still holds".

Add or subtract a number on both sides of the equation at the same time, and the equation does not change; The whole on both sides of the equation is multiplied or divided by a number at the same time, and the equation does not change.

In the case of a one-time equation, first deform the equation by moving x to the left of the equal sign and the number to the right.

The coefficient of x is then reduced to 1.

Using the principle of balance equilibrium, which is the basic property of equations, both sides of the equation are added, subtracted, multiplied, and divided (not a number of 0) at the same time, and both sides of the equation are still equal.

Depending on the nature of the equation, it is OK [add or subtract a number on both sides of the equation at the same time, and the equation still holds], e.g. x-2=7

Add 2 to both sides of the equation

x-2+2=7+2x=9

1. Primary schools generally do not learn equation solving, so there is no so-called primary school equation.

2. If there is, please list the corresponding examples, so that it can help you more specifically.

Please remember to adopt it in time, thank you.

Apply the original understanding of the equation. Both sides of the equation add or subtract the same number, and the result remains the same. x ten 3 = 5

x ten 3 a 3 = 5 a 3 = 2

Quadratic or cubic, or Yuanfang?

If all the chickens in the cage are considered to be chickens or all rabbits, then the calculated feet are a few fewer than the actual feet, and divide it by 2 to get the number of rabbits; If you look at it as a rabbit, then you can count how many feet there are more than the actual feet, and divide it by 2 to get the number of chickens.

For example, there are 24 chickens and rabbits in the cage, 76 feet, and how many chickens and rabbits are there?

1. Think of it all as a chicken: because the head is 24, the feet are 24*2=4876-48=28

So 14 rabbits and 24-14 chickens = 10.

2. Think of it all as a rabbit: 24*4=96

So 10 chickens and 24-10 rabbits = 14.

Clear enough, right... Give it points! ~