Use VB to program a program that outputs the calendar for that month

Updated on technology 2024-04-12
7 answers
  1. Anonymous users2024-02-07

    Form on the total number of days to put text1 text2 text3 command1 private sub command1 click(). dim daycount as long day of the week on the first day.

    dim weeknum as long

    Output. dim outtext as stringtext1 is the total number of days.

    daycount = val(

    text2 is the day of the week for the first day.

    weeknum = val(

    dim i as long

    outtext = "Monday" & vbtab & "Tuesday" & vbtab

    outtext = outtext & "Wednesday" & vbtab & "Thursday" & vbtab

    outtext = outtext & "Friday" & vbtab & "Saturday" & vbtab & "Sunday" & vbcrlf

    for i = 1 to weeknum - 1outtext = outtext & vbtabnextdim k as long

    for i = 1 to 7 - weeknum + 1outtext = outtext & i & vbtabk = k + 1

    nextouttext = outtext & vbcrlffor i = 1 to daycount - kif i mod 7 = 0 then

    outtext = outtext & vbcrlfend if

    outtext

    end sub

    private sub form_load()= 31

    2end sub

  2. Anonymous users2024-02-06

    After entering a month of the year, the screen outputs a calendar for that month, with one row per week, starting on Sunday and ending on Saturday.

    import ;

    public class year

    return false;

    Return how many days there are in a month and year.

    public int getday(int year ,int month);Leap year month.

    int day1=;Ordinary month.

    if(}/**

    The 1st of the month is the day of the week.

    public int getweek(int year,int month)

    Print it out, quack.

    public void showprint(int year,int month)

    for(int j=1;j<=day;j++)

    j+"\t");

    public static void main(string args)}

  3. Anonymous users2024-02-05

    import ;

    public class year

    return false;

    Return how many days there are in a month and year.

    public int getday(int year ,int month);Leap year month.

    int day1=;Ordinary month.

    if(}/**

    The 1st of the month is the day of the week.

    public int getweek(int year,int month)

    Print it out, quack.

    public void showprint(int year,int month)

    for(int j=1;j<=day;j++)

    j+"\t");

    public static void main(string args)}

  4. Anonymous users2024-02-04

    I've only made calendars and learned.

  5. Anonymous users2024-02-03

    The landlord is so interesting. After writing it, I said it was in C. 55555555555...

    When you're done, run it in C++ IDE and see how it looks.

    #include

    The first day to get the entered year and month is the day of the week 0 6*

    int getdate(int y,int m);

    Determine whether the input is a leap month, if yes, it returns 1, otherwise it returns 0*

    int leap(int y);

    Print the input month calendar*

    void print(int y,int m);

    int main()

    int getdate(int y,int m)

    w=(w+days)%7;

    return w;*Returns the day of the week on the 1st of the entered month*

    void print(int y,int m)

    if(leap(y)) month[1]=29;

    printf("sun\tmon\ttue\twed\tthu\tfri\tsat");

    int i,j;

    for(i=0;ifor(i=w,j=1;j<=month[m-1];i++,j++)

    printf("********************===="

    int leap(int y)

  6. Anonymous users2024-02-02

    import ;

    public class demo

    int week=sumday%7;

    Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday");

    int k=0;

    for(k=0;k<(week+1)%7;k++)int s=1;

    while(s<=daymonth(mouth))"\t"+s);

    k++;s++;

    if(leapyear(year)&&mouth==2)}public static boolean leapyear(int year)

    public static int daysum(int year)public static int daymonth(int month)

    return day;}}

  7. Anonymous users2024-02-01

    private sub command1_click()dim mymonth as integerdim myyear as integermyyear = val(

    mymonth = val(

    datediff("d", myyear & "-" & mymonth & "-" & "1", myyear & "-" & mymonth + 1 & "-" & "1")

    end sub

    private sub form_load()= year(date) 'text1 = 1'text2.

    " 'text3 enters the number of days corresponding to the month ="Check"

    end sub

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