100A leakage is connected with a few square wires, how is it converted between them, is there a form

With more than 16 square copper wire or more than 25 square aluminum wire, mainly according to the empirical formula, ten under five, one hundred on two, four, three times and a half, copper wire upgrade calculation, through the pipe, temperature.

Eight, nine fold. The empty opening 100A you said is suitable for 25 square aluminum wire or 16 square copper wire, and the carrying current of 25 square aluminum wire is 25 * 4 = 100A, and the copper wire is upgraded, so the copper wire can be selected as 16 square meters.

In the selection of power cords, in fact, as long as you remember a few simple formulas, these problems will be solved. When choosing the power cord, the power consumption of the equipment must be known, with this known condition, the formula of three-phase alternating current power is used to find the current, the formula:

p (electric power) 3 380 (three-phase voltage) i (current) cos, in the formula cos is the reactive power loss of the inductive load, conservative to take the constant:

3 This is a minimum of mathematical common sense, and the current (i) is derived:

i p (power) 3 380, with the current, find the diameter of the power cord (note, this is the diameter of the wire, not the cross-sectional area, the specifications of the power cord are all expressed by the cross-sectional area). Wire Diameter Formula:

d, and then use the diameter of the wire to find the cross-sectional area of the wire, which is the mathematical formula: radius radius; Okay, that's it, the specifications of the power cord used have been found.

Quite simply, there are two formulas to remember, one:

P (electrical power) 3 380 (three-phase voltage) I (current) cos

Another formula: d.

Because (single-phase) power = current and voltage, it can carry about kilowatts of power.

100*220*1000=22kw can bring 22 kilowatts 220V equipment.

Single-item covenant; 20kw, approx. of three items; 40kw.

The 100A leakage protector means that the maximum current that can withstand 100A can be bought in one phase. You can add up the load of the electrical appliances.

The vertical cross-sectional current density of the national standard copper wire is: 6a mm

100a÷6a/mm²=

So: about 17mm of copper wire is required.

There is a magnification formula, the general current can be selected to 10 for small magnification, that is, 1 square pass 10 ampere is no problem, the current can only be selected 2, such as 240 square aluminum wire can only pass about 500 amperes, you 100 amperes choose about 4 to 5 it, it is recommended to use 25 square aluminum wire or 16 square copper wire on the line. But if the distance is more than 80 meters, it should be bold. Generally, every 100 meters of lengthening requires doubling the square of the cable cross-section.

For example, if your distance is 1000 meters, 100 ampere current will require 150 square copper core cable.

Yes, generally after knowing the power, you can check the meter by calculating the current, such as in the "Electrician's Manual". For example, the power of 11OOW, the calculated current is: 1100 220V=5A, check the wire above the square copper core wire in the electrician's manual, because the interception current of the square copper core wire is 13A.

Totally affordable.

The safe ampacity of the wire is related to its material, and you must check the meter to know the accuracy. If you approximately, you can estimate it according to the following: copper wire, 6-7a square under 10 square meters.

10 to 20 square is 4-5a square.

20-50 square is 3-4a square.

50 to 350 square is 1-2a square.

In general, it is best to choose when there is sufficient redundancy, but not too much.

100A current can choose 25 square millimeters of copper wire, which is a relatively safe current load.

With a thick wire that can be stuffed into the wiring hole of the leakage switch, five 4 square stranded copper wires are hinged with the thick wires one by one according to the electrical wiring specifications.

After passing the multi-strand wire into the line nose, press it with hydraulic pliers, the line nose is best to use 100A silver plating, and then use a 200w electric soldering iron to fill the tin, which is absolutely reliable.

It is better to find a suitable wire nose first and press it with hydraulic pliers before installing it. Tin may also work.

Now there is that kind of cold-pressed terminal on the market, also called the wire nose, which is the kind of pure copper, and the specification is 35 square meters, one or two yuan a piece.

An air switch, also known as an air circuit breaker, is a type of circuit breaker. It is a switch that automatically disconnects whenever the current in the circuit exceeds the rated current.

The air switch is a very important electrical appliance in the low-voltage distribution network and the power drive system, which integrates control and a variety of protection functions. In addition to completing the contact and breaking circuits, it can also protect the circuit or electrical equipment from short circuits, serious overloads and undervoltages, and can also be used to start the motor infrequently.

The circuit breaker is selected according to the power of the consumer.

Calculate the total power of the home first, and then select the leakage switch according to the power.

With power, voltage is equal to current. For example, if the total power of electrical appliances is 4kw, then 4000 220 = 18a.

The rated current of the leakage switch is required to be greater than the load current.

In general, the choice of total leakage switch is calculated as a multiple of the load current, 18A*.

There is no leakage switch for 27a, so.

The leakage switch should be selected for 32A. The leakage action current is selected as 30mA.

This elastic dark compress is not the same as the light compression! 6 square with 32 household choice C type. 4 square square choice with c16, I choose more conservative, hehe, safety first.

Household, and general places to protect the main leakage of people for the current of 30 mAThere are others as well. 50 100 leakage.

Calculate the leakage switch selection: current = power voltage... For example, 1000W 220V = Select 10A leakage switch...

According to the calculated current to select the leakage switch, the general leakage switch "load times cable selection (copper).

6-20a25 4mm2

32 6mm2

40-50 10mm2

63 16mm2

80 25mm2

100 35mm2

125-140 50mm2

160 70 mm 2

180-225 80--95mm2

Leakage switch is a general term for leakage protector and switch. For household electricity, the operating current of the leakage protector is not more than 30 mA. For switch selection, it depends on the load in your home.

When the load is determined, the current is known, and then the size of the wire is selected according to the current and the occasion in which the wire is laid. Of course, for some places, the need coefficient should also be considered.

The 100A leakage switch, the single-phase 220V can withstand 25 kilowatts, the cable needs 16 square copper wires, the three-phase 380V can withstand 40 kilowatts, and the cable is also 16 square meters.

If 100A is commonly used, choose at least 35 square ones, and if it is a spare one, you can choose 25 square ones.

In terms of cost, you can also choose 25 square or even 16 square meters, but this will reduce the service life of the wire.

How much current can be withstood by a copper core cable is calculated.

Calculation of wire cross-sectional area and safe ampacity.

Calculation of wire cross-sectional area and safe ampacity.

1. The safe ampacity of the general copper conductor is determined according to the maximum temperature, cooling conditions and laying conditions of the allowable core.

Generally, the safe current carrying capacity of copper wire is 5 8a mm2, and the safe current carrying capacity of aluminum wire is 3 5a mm2. "Key Points".

Generally, the safe current carrying capacity of copper wire is 5 8a mm2, and the safe current carrying capacity of aluminum wire is 3 5a mm2. Such as: the recommended value of the safe ampacity of copper wires, the safe ampacity of copper wires.

Recommended value 4 8a mm2 = 32a

2. Calculate the cross-sectional area of the copper wire using the recommended value of the safe ampacity of the copper wire 5 8A mm2, and calculate the upper and lower range of the selected copper wire cross-sectional area s: s== copper wire cross-sectional area (mm2

i--- load current (a).

3. Power calculation: General loads (which can also be used as electrical appliances, such as lights, refrigerators, etc.) are divided into two types, one is resistive load, and the other is inductive load. The formula for calculating resistive loads is: p=ui

The formula for the calculation of the fluorescent lamp load is: p=uicos, where the power factor cos = of the fluorescent lamp load.

The power factor of different inductive loads is different, and the power factor cos can be taken when the household appliances are calculated in a unified manner. That is to say, if all the appliances in a household plus the total power is 6000 watts, the maximum current is.

i=p/ucosф=6000/220×

However, under normal circumstances, it is impossible to use electrical appliances at home at the same time, so add a common factor, and the common coefficient is average. So, the above calculation should be rewritten as:

i=p common factor ucos =6000

That is, the total current value of this family is 17A. Then the main gate air switch can not use 16A, should use greater than 17A.

Estimation formula: 2.5 times 9, subtract one straight up and go. Thirty-five times 3.5, double in a group minus five.

The conditions have been changed and converted, and the high-temperature nine-fold copper has been upgraded. The number of pipe roots is two, three, four, eight, seven and six folds full of load current.

35's is fine, with a certain margin.

The current carrying capacity of the insulated conductor is estimated as follows:

Insulated conductor ampacities estimation.

The relationship between the ampacity of the aluminum-core insulated wire and the multiples of the cross-section.

Conductor cross-section (mm 2) 1 1 5 2 5 4 6 10 16 25 35 50 70 95 120

The current carrying capacity is a cross-section multiple 9 8 7 6 5 4 3 5 3 2 5 Current carrying capacity (a) 9 14 23 32 48 60 90 100 123 150 210 238 300

Estimation formula: 2.5 times 9, subtract one straight up and go. Thirty-five times 3.5, double in a group minus five.

The conditions have been changed and converted, and the high-temperature nine-fold copper has been upgraded. The number of pipe roots is two, three, four, eight, seven and six folds full of load current. Description:

1) The formula in this section does not directly indicate the current carrying capacity (safety current) of various insulated wires (rubber and plastic insulated wires), but is expressed by "multiplying the cross-section by a certain multiple", which is obtained by mental arithmetic. As can be seen from Table 5 3, the multiplier decreases with the increase of the cross-section.

2.5 times by nine, up minus one by one line" is talking about 2 5mm' and below various cross-section aluminum core insulated wires, the current carrying capacity of which is about 9 times the number of cross-sections. For example, 2 5mm' wire, the current carrying capacity is 2 5 9 22 5 (a). The relationship between the current carrying capacity and the number of cross-sections of the wire from 4mm' and above is to go up along the wire number, and the multiple is gradually reduced to L, that is, 4.

Thirty-five times three .five, double and double groups minus five ", which means that the current carrying capacity of the wire of 35mm" is 3 5 times the number of cross-sections, that is, 35 3 5 122 5 (a). From 50mm' and above wires, the multiplier relationship between the current carrying capacity and the number of cross-sections becomes two two wire numbers in a group, and the multiples are subtracted by 0 5 in turn. That is, the current carrying capacity of the mm' wire is 3 times the number of cross-sections, and the current carrying capacity of the mm" wire is 2 5 times the number of its cross-sectional area, and so on.

The conditions have been changed and converted, and the high-temperature nine-fold copper has been upgraded. The above formula is based on the aluminum core insulated wire and the open application at an ambient temperature of 25. If the aluminum core insulated wire is laid in an area where the ambient temperature is higher than 25 for a long time, the current carrying capacity of the wire can be calculated according to the above formula calculation method, and then it can be discounted; When using not aluminum wire but copper core insulated wire, its current carrying capacity is slightly larger than that of aluminum wire of the same specification, and the current carrying capacity of one wire number can be calculated according to the above formula method.

For example, the current carrying capacity of 16mm' copper wire can be calculated as 25mm2 aluminum wire.

With 3*10+1*6 square millimeter aluminum core cable can

You choose according to your own line requirements, and the safe ampacity of the wire is shown in the table below.

100A with 25 squares, 10A with squared. But the longer the wire, the smaller the current.

This score looks at several aspects.

1) If it is a wire in a transformer or motor, then it should be calculated according to the overall heating power and heat dissipation area of the product you are making.

2) If it is used as a lead wire or transmission cable, there are two cases: A: single core wire B: multi-core wire.

3) It depends on the temperature resistance level of the wire you choose, there are 75 degrees, 105 degrees, 130 degrees, and higher.

If it is case 1), it has to be calculated specifically, and it depends on your cooling method If it is case 2) 3), we commonly use more wires with 75 degree multi-core wires, 100A, the current density can be about 4A mm 2, and 10A, the current density can be about 6A mm 2.

What do you use it for, copper wire or aluminum wire, and how is the heat dissipation?

25 square insulated copper wire 380V voltage is about the same.