Excuse me math 10x 12y 13z 296 1 , 1 9 90x 108y 117z 1854 9x 11?

It seems that some of the numbers have been miscalculated, or the equation has been written incorrectly.

1) The right side of the *9 equal sign should be 296*9=2664, unless it is 206*9=1854

In addition, it doesn't make sense for you to come out of two formulas or three unknowns, your purpose should be to eliminate an unknown after the combination, and provide two methods, the first one is relatively large, and the latter is equivalent to a simple algorithm:

Reckless Algorithm:For example, if we aim at x, we want to be relatively one-step:

The least common multiple of the coefficients in the three equations is 360, therefore.

1) *36 (4).

360x+432y+468z=10656

2) *40 (5).

360x+440y+600z=11760

3) *45 (6).

360x+450y+315z=9540

5)-(4)Get (7).

8y+132z=1104

5)-(6) get (8).

10y+285z=2220

Eliminate y in the same way

7)*5+(8)*4 get (9).

660+1140)z=5520+8880

That is, 1800z = 14400

Z=8 is obtained and Z=8 is substituted back (7).

8y+132*8=1104

Obtain y=6 and replace y=6,z=8 back to (1).

10x+12*6+13*8=296

Get x=12

Of course, the above method has a relatively large value, and it can also be simplified in the calculation first

Clever Algorithm:1)-(2)(4).

x+y-2z=2

1) 2-(3) 2 (5).

x+y+3z=42

are all x+y, (5)-(4) can be solved to get z=8

So x+y=18

1) Morph it a bit:

10(x+y)+2y+13z=296

substitution. 10*18+2y+13*8=296 is solved to y=6, so x=18-y=12

The results were consistent.

The calculation is incorrect, (1) the right side of the 9 medium size should be 2664: 90x+108y+117z=2664;And if we are solving the equation system composed of (1), (2), and (3), we should first eliminate an unknown number, such as (2) 10-(1) 9, to obtain the relationship between y and z, and then substitute it into (1), (2), and (3) to solve the x and y values, and finally find the z value. This problem can also be simple to find the value of z first, such as (2) 2-[(1)+(3)], you can get 10z=80, solve z=8, and then substitute this into two of (1)(2)(3) to obtain the values of x and y (for example, after substituting the z value into (1)(2), you can get x+y=18 by using (1)-(2), and then substitute x=18-y to get x=12, y=6.).

x=48，y=54。

Subtract the product of the pre-Ming formula multiplied by 2 from the latter formula in the question:

2x=96, and the solution is x=48.

Change x=48 generations into the previous formula.

48 + y = 102, the solution is radical and the disadvantages are y = 54.

Summary. x+y=102 13x+11y=1218x+y=102 13x+11y=1218 What is x?

x+y=102 13x+11y=1218 11x+1y=1122x+y=102 13x+11y=1218 11x+1y=11222x=96x=48

x+y=102 13x+11y=1218 x equals 48.

Because the conditional formula is:

13x 21y 8y 19, so there is: 13x 13y 19, and divide 13 on both sides to get :

x＋y＝19／13。

5x+7y+4z=127（1）

4x+8y+3z=122（2）

2x+9y+7z=139（3）

2) x5 - (1) x4 get:

12y-z=102（4）

3) x2-(2) get:

10y+11z=156（5）

5) x6-(4) x5 gets:

71z=426

Z=6 is substituted into (4), and 12y=102+6, y=9 is substituted into y=9, z=6 into (1) to obtain: x=8......

10x+12y=1068, this equation is a binary one-dimensional equation, if it is solved, it also needs an equation about x, y, if simplified, it can be simplified as.

5x+6y=534

11x+9y=49 1 formula.

13x-3y=17 2 formula.

Formula 1 + Formula 2 3 gets:

11x+9y+39x-9y=49+51

50x=100

x=2 is brought into the formula 1 to obtain;

22+9y=49

9y=27y=3 solution: x=2 y=3

13x-3y=17 2 formula.

Formula 1 * 3 + 2 formula * 8 gets: 137x=83 x=283 137 substituted into formula 2: y=350 411

I think of this high split, (1) 4 and (3) 5 because the first identical number multiplied by 10 and 8 is Cong Heng 40, because 10 starts from 1 Qi Zheng closed and gradually is 10 20 30 40 50....And then 8 starts gradually, which is 8, 16, 24, 32, 40. can be drawn.