A ten digit figure of 7 to the power of 2011?

Updated on educate 2024-04-21
8 answers
  1. Anonymous users2024-02-08

    The 10 digits of 7 to the power of 2011 are 4, I calculated it with a VBA in Excel, scientific notation.

    There are 1700 bits for the full results, as follows:

    The procedure is as follows: sub macro 1().

    m = 7 '3 of 2 4038 = 2019n = 2011'To the nth power.

    w = 189 'The number of 9-digit cells in the budget result.

    j = 2 'From the second line, multiply the second to start the calculation.

    cells(1, w) = m 'Place cardinality.

    do while j <= n '

    for i = w to 1 step -1cells(j, i) = cells(j - 1, i) *mnextfor i = w to 2 step -1a = int(cells(j, i) / 1000000000)b = cells(j, i) -a * 1000000000cells(j, i) = b

    cells(j, i - 1) = cells(j, i - 1) +a

    nextj = j + 1

    loopend sub

  2. Anonymous users2024-02-07

    7 to the 1st power, the last number is 7, 7 to the 2nd power, the last two numbers are 49, 7 to the 3rd power, the last two numbers are 43, 7 to the 4th power, the last two numbers are 01, 7 to the 5th power, the last number is 07, 2011 4 = 502 ......3

    So the number of tens to the power of 7 in 2011 is 4.

  3. Anonymous users2024-02-06

    The nth power single digit of 7 is the jujube beam rolling to the cycle, and the nth power of 8 is the Zhachang cycle, 2010 4=502 ......2

    That is, the single digit of 7 to the power of 2010 is the second digit of the number of cycles, the single digit of the power of 98 of 2012 is the fourth digit of the number of cycles, and the sum of their stools is 9+6=15, and the single digit is 5.

  4. Anonymous users2024-02-05

    Answer: The case of Iwachun is 4. 7 2014=(10-3) 2014 From equation (1), we get -2014*10*3+1007*10-1=-50351 Here we get a negative value, but in fact 7 2014 is a positive number It can be determined that the last two digits are equal to 100-51=49

  5. Anonymous users2024-02-04

    The last two digits are: 07, 49, 43, 01

    2011 4 = 502 surplus 3, so the answer is 43

  6. Anonymous users2024-02-03

    7x7=49

    7x7x7=343

    So 4 in a cycle.

    So for 9

  7. Anonymous users2024-02-02

    The single digit of 7 to the 4th power is 1 7 to the power of 2010 = 7 to the 4th power of 502 multiplied by 7 2

    7 of the 2010 power of the single digit Dan is a model is stupid 9

  8. Anonymous users2024-02-01

    In 2007, the 10-digit value of the n-power deficit is the 10-digit value of the n-power shirt age of 7. 1 time 7

    5 cycles minus 4 to the nth power and the 10-digit number remains the same.

    The value of the 10th place of 2007 of 2007 is the value of the 3rd power of 7.

    The answer is 4

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