How to calculate the number of meters for a meter with a current transformer

1.low-voltage metering watt-hour meters;

The dial reading is multiplied by the current transformer multiplier.

Columns such as; The transformer is; 100；5 (marked above), then the magnification of the transformer is 20 times, you multiply the reading by 20.

2.high-voltage metering watt-hour meter;

The dial reading is multiplied by the current transformer multiplier and then multiplied by the voltage transformer rate.

Because the current coil of the watt-hour meter cannot be directly connected to the high-voltage power supply for sampling, a voltage transformer is added (in fact, it is a transformer, generally, turning 10,000 volts into 100 volts). In this way, the magnification of the voltage transformer is 100, that is; Multiply another 100.

If you don't know the model of the transformer in the distribution cabinet (if you can't open the box), you should look at the distribution drawing;

ct；Stands for current transformer.

bt；Stands for Voltage Transformer.

Number of tables in the previous month)]*400 5) = Electricity consumption in this month.

Before CT conversion: P1 = line * I line 1

After CT conversion: P2 = line * I line 2

Because according to the current transformer becomes 400 5, I line 1 = 80 * i line 2 is substituted into the above formula: p1 = 80 * p2

400 5A current transformer 80 (times).

Actual Electricity: kWh).

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<> how to calculate the meter power of the two current transformers, the closure is as follows: 1. The formula for calculating the meter degree of the current transformer: the actual primary current = the secondary electric car draft laughing flow x transformer ratio 5 turns.

2. The degree of the watt-hour meter = the number of words x the voltage conversion ratio x the current transformation ratio 5 turns. 3. For example, the conversion ratio of the current transformer is 1500 5 (the transformer name plate is on it), the main line is around 5 times, and the transformer becomes 300 5, at this time, if the meter goes 5 degrees, the actual electricity should be 300 degrees. If the meter goes 1 kilowatt-hour, the actual amount of electricity is 60 kilowatt-hours.

Hello dear, how to calculate the power of the meter with transformerThe formula of the meter to calculate the power is: when the meter connected to the current transformer is used to calculate the electricity consumption, the calculation method is: actual electricity consumption = ammeter reading * multiple of the current transformerThe watt-hour meter measures the electrical work, that is, the product of power and time, and the unit is kw * h

When a current transformer is used, the current of the watt-hour meter is actually the current of the transformer, and the actual current of the circuit is the output current of the transformer * the multiple of the transformer, assuming that the ratio of the transformer is n, then the current flowing through the current coil of the watt-hour meter is the actual current. Hope it helps. If my answer is helpful to you, please give a thumbs up (in the lower left corner), I look forward to your like, your efforts are very important to me, and your support is also the motivation for my progress.

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Summary. The calculation method is: actual electricity consumption = ammeter reading * multiple of the current transformer, the watt-hour meter measures the electrical work, that is, the product of power and time, and the unit is kw * h

When the current transformer is used, the current of the watt-hour meter is actually the current of the transformer, and the actual current of the circuit is the output current of the transformer * the multiple of the transformer, assuming that the transformation ratio of the transformer is n, the current flowing through the current coil of the watt-hour meter is 1 n of the actual current, so the actual electricity consumption is n times the value measured by the watt-hour meter. Hope it helps.

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The calculation method is: actual electricity consumption = ammeter reading * multiple of current transformer The electric meter measures the electrical work, that is, the product of power and time, and the unit is kw*hWhen the current transformer is used, the current of the watt-hour meter is actually the current of the transformer, and the actual current of the circuit is the output of the transformer, and the flow * mutual inductance multiple, assuming that the transformation ratio of the transformer is n, then the electric bright current flowing through the current coil of the watt-hour meter is 1 n of the actual current, so the actual electricity consumption is n times the value measured by the watt-hour meter.

Now the current stupid transformer is 250 5a, and the meter shows 158 degrees, so the actual degree of dismantling should be 250 * 5 = 50 * 158 = 7900, right?

Now my current transformer is 250 5A, the meter shows 158 degrees, so the actual degree should be 250 * 5 = 50 * 158 = 7900 for liquid? Hello dear, when converting the amount of electricity from 250 5 current transformer to 250 (250 5). I hope I can help you.

Electricity consumption = (stop code of electric energy meter - minimum electric energy meter) current transformer rate.

The degree read by the watt-hour meter = (this month's reading, last month's reading) multiplied by the current transformer rate, is the actual power consumption of this month.

When measuring the large current of alternating current, in order to facilitate the measurement of the secondary instrument, it needs to be converted into a relatively uniform current, and the voltage on the line is relatively high as scattered rock, such as direct measurement is very dangerous. The current transformer plays the role of converter and electrical isolation.

For analog ammeters, the secondary current of the current transformer is mostly amperage (e.g., 5A, etc.). For digital instruments, the signal of mining samples is generally milliampere (0-5V, 4-20mA, etc.). The secondary current of the miniature current transformer is milliampere, which mainly plays the role of a bridge between the large transformer and sampling.