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1-[(c365 45) (365 45)] is calculated by calculating the probability that no one has the same birthday, and then subtracting it from 1 to get the probability that at least two people have the same birthday.
That is, the probability that one out of 45 people has the same birthday.
c365 45 means 45 different days out of 365 days, i.e. 45 people.
The total number of possible birthdays for each person, and then divide by the total number of possible birthdays for 45 people, which is 365 45, which is the probability that everyone has a different birthday.
People who say that the topic is not clear are not understanding it themselves.
This topic is asked"The probability that someone was born on the same day, month, and year in the same year"That is, the probability that no one has the same birthday is removed from any two identical probabilities, and there is no ambiguity. Because the meaning of the same, as long as the minimum conditions are met, as long as there are 2 people who are the same, it is naturally the same!
There is no question of two or several.
If you follow the two several questions. The title should also explain: whether there is only the probability that two birthdays are the same or any two birthdays are the same, or only three birthdays are the same probability or three birthdays are the same, and so on!
And the probability in this question is actually the sum of the above probabilities!
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1-365 to the 45th power c365:45
If it takes place in the same class at school, assuming the same year, the rate is very large, two people in a class, the rate is 1 365, the first person is born on any day is 100 100, the second person is 364 365 for the remaining 364 days of the year, and the rate on the same day is 1 - 364 365 = 1 365
The rate of three people in a class is about 2,365, the first person is born on any given day is 100,100, the second person is 1,365 on the same day of the year, the third person is about 365 for the rest of the year - "1+(1-1 365)" is about 363,365, the first two people account for 1+ (1-1 365) for a year, and the rate of "1+(1-1 365)" is 365 for the first two
Because 1 365 is smaller, three people are less than 2 365, and 45 people are less than 44 365 If the society is randomly distributed, considering the problem of the year, if the population distribution is evenly distributed in 70 years, it may be less than 44 70 in the same year, and even smaller in the same month and day.
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This is a question that is generally mentioned in textbooks of probability theory and mathematical statistics.
The calculations are cumbersome.
I remember that the example problem in our book was a class of 64 people with a probability of having the same birthday at least 97%.
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1-365 to the power of 45 c365:45 should be.
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Does the landlord want to ask; Among the 45 people, there is a probability that two were born on the same day, the same month, and the same year?
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The question is not very clear, and the probability of how many people are going out at the same time on the same day should be asked.
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That's right upstairs. You don't have to say how many people have birthdays at the same time!
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The explanation upstairs is very good, and the specific calculation is better to calculate it yourself.
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Fate is a very wonderful thing, in life, I think it is difficult to meet a person with the same year, the same month and the same day, but sometimes I will let myself meet, everyone is more curious about this, I want to know the probability of 2 people born on the same day, the same month, and the same day, what is the probability of meeting the same birthday?
Now from the software and professional calculations, the probability of two people born in the same year, the same month, and the same day is around, from which we can see that the probability is still relatively low, if you can really meet people who are born at the same time, then it is a great fate, and it is also an encounter worth cherishing.
The probability of having a birthday on the same day needs to be measured according to the year, if it is a leap year, then the probability of a birthday on the same day is 1 366; If it is not a leap year, then the probability of encountering the same birthday on the same day is (3 4) * (1 365) + (1 4) * (1 366); On February 29, the probability of two people on the same day is (3 4) * (0 366) + (1 4) * (1 366) = 1 1464. It is a probability that there is a certain change, which needs to be analyzed in a comprehensive manner, and if you really don't know, you can also calculate it through software.
Generally speaking, it is relatively rare to meet people born on the same day and month in the same year, these people are more similar in life experience, personality and other aspects, if they meet, then they are still more compatible, and they may become good friends.
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Excluding leap years, assuming 1 year and 365 days, the algorithm is as follows:
There are 365 possibilities for the first person's birthday.
The birthday of the second person, assuming that it is not the same day, the probability is 364 365 The birthday of the third person, assuming that it is not the same day, the probability is 363 365 The birthday of the 50th person, assuming that it is not the same day, the probability is 316 36550 people, the probability of not having the same birthday is (364 365)*(363 365)*....316/365)=
That is, the probability of having the same birthday is:
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The probability that two people will be born on the same day, month, and year is 1 365;
Probability reflects the probability of a random event occurring. A random event is an event that may or may not occur under the same conditions. For example, from a batch of ** and defective goods, randomly draw a piece, "draw **" is a random event.
Suppose n experiments and observations are carried out on a random phenomenon, in which event a occurs m times, that is, the frequency of its occurrence is m n. After a lot of trial and error, it is common for m n to get closer and closer to a certain constant (see Bernoulli's law of large numbers for this proof). This constant is the probability of event a occurring, which is often denoted by p (a).
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It's a privilege that I'm one of those percent, and I've been looking for half a year, and I've finally found someone on the same year, month, and day.
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Hello, it is a pleasure to serve you. I am good at language translation, preschool education, career comprehensive, a total of more than 100 hours of 1v1 consultation, please later, I am quickly sorting out the answer for you, reply to you within 5 minutes, please don't worry about [heart] [heart] [touch your head].
If you just say that you were born in the same year, the same month, and the same day, I can still count it for you, but if you add the same name, it depends on what the name is, if you call Li Shuzhen, there are millions of people in Shanghai, and it is easy to meet people born in the same year, the same month, and the same day, if your name is very strange, there may not even be a person with the same name.
According to the current living maximum of 110 years old, the probability of the same year is 1 110 (I don't know what year you are so the same calculation, I think you should be younger, then the actual probability will be much greater, maybe 1 70, or 1 60, the results of the census are accurate, these are estimates), the probability of the same day in the same month is 1 365, and the probability of being born on the same day of the same year is 1 40150
According to China's population of 1.3 billion, there are about 32,379 people with you, which is estimated to be a little larger than this number, which is still a lot.
If your questions have been answered, I hope to give a like, if there are unanswered questions, you can leave a message on this page for consultation, I hope it can help you, I wish you a happy life.
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If all 50 people are born in the same year, then the probability of not appearing in the same life is c(50,365) 365 50, and the probability of being born in the same year, month, and day is 1-c(50,365) 365 50
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1-[(c365 100) (365 100)] is calculated by calculating the probability that no one has the same birthday, and then subtracting it from 1 to get the probability that at least two people have the same birthday. That is, the probability that someone in 100 people has the same birthday as Liang Wangtian c365 100 means that it is to take out 100 different days from 365 days, that is, 100 people each.
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It is possible to have everyone's birthday on any of the 365 days of the year. are equal to 1 365, then select n people, and the probability that they will have different macro and simple days is 365*364*363(365-n+1) 365 to the nth power.
Therefore, the probability that at least two people in n people have the same birthday is p=1-365*364*363(365-n+1) 365's n-times mountain pants.
Here the value given n is 50, and the probability of substitution is p=
This can be used as a formula in the future!
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