The excess CO2 gas is introduced into the following substances, and it does not become turbid

Passage A, Mr. calcium carbonate precipitation, and then calcium bicarbonate precipitation due to excess carbon dioxide disappears Passage B, generate phenol and sodium bicarbonate, because the solubility of phenol at room temperature is very low, so phenol precipitation into C, generate aluminum hydroxide and sodium carbonate, aluminum hydroxide precipitation into D, generate orthosilicic acid and sodium carbonate, orthosilicic acid precipitation

So the answer is a .........But I think the title should be "The final solution is not cloudy" ......It's a bit unscrupulous

c, metaaluminic acid is more acidic than carbonic acid.

A reacts with excess C02 and Ca(OH)2 to form calcium carbonate precipitation, and then CaC03 continues to react with CO2 to form calcium bicarbonate, so that the solution becomes clear.

BC6H5ONA reacts with CO2 to form phenol that is insoluble in water, making the solution turbid.

Cnaalo2 and CO2 react to form aluminum hydroxide precipitate, and the solution becomes turbid.

DNA2SiO3 and CO2 react to form silicic acid, which is insoluble in aqueous solution and becomes turbid.

a Calcium carbonate first.

co2 + ca(oh)2 === caco3 + h2o

Then there is calcium bicarbonate.

CO2 + CaCO3 + H2O === Ca(HCO3)2 (soluble in water).

b Generate sodium carbonate and phenol (principle of strong acid to weak acid).

c6h5ona + h2o + co2 === nahco3 + c6h5oh

Mr. is sodium carbonate excess CO2 and caCO3 is the same as sodium bicarbonate).

C is generated by aluminum hydroxide.

Step 1: Naalo2 + H2O + CO2 === NaHCO3 + HALo2 (metaaluminic acid).

Step 2 : Metaaluminic acid hydrolysis.

halo2 + h2o === al(oh)3

d Excess CO2

Whether the formation is the precipitation of orthosilicic acid (or the principle of strong acid to produce weak acid).

na2sio3 + 2h2o + co2 === nahco3 + h4sio4

Only b is not cloudy.

Select AB to generate phenol which is insoluble in water.

c Double hydrolysis to produce aluminum hydroxide.

d Silicic acid is formed, which is insoluble in water.

It should be sodium phenol.

I hope mine will be helpful to you!!

If the lime water remains clear without white turbidity, it may be due to the following reasons:

1.CO2 itself has a certain solubility in water and can react with water to form carbonic acid

co2 + h2o → h2co3

Such a reaction can cause the clarified lime water to become cloudy, as the resulting carbonic acid forms fine suspended particles. However, if the CO2 carrying HCl is introduced into the clarified lime water, the generated H2CO3 will decompose into water and hydrochloric acid with HCl, so there will be no obvious suspended particles, while the lime water will remain in a clear state.

2.The reaction of HCl with lime water can also generate precipitate, but the total amount of precipitation is small, and saturated solubility can be obtained at very low concentrations. When CO2 is introduced into lime water, the resulting carbonic acid converts Ca(OH)2 into CaCO3 precipitation, which can prevent further reactions.

In summary, although the reaction of hCl and lime water will produce a certain amount of precipitation, these reactions are inhibited under the action of CO2, resulting in no significant change in lime water.

After CO2 is introduced into the calcium hydroxide saturated solution, CaCO3 precipitate will be produced first, and CO2 will be introduced continuously, CaCO3+H2O+CO2=Ca(HCO3)2, and the precipitate will be dissolved.

b.Phenol will be produced after CO2 is introduced into a saturated solution of sodium phenol, and the solubility of phenol is very small, and the solution is turbid.

Cd will not react, and weak acids in solution cannot make strong acids.

After CO2 is introduced into the saturated solution of calcium oxide, CaCO3 precipitation will be produced first, and CO2 will be introduced continuously, CaCO3+H2O+CO2=Ca(HCO3)2, and the precipitate will be dissolved.

b.Phenol will be produced after CO2 is introduced into the saturated solution of sodium phenol, and the degree of dissolved digestion of phenol is very small, and the solution is turbid.

Cd will not react, and the weak acid in the dissolved reed solution cannot make strong acid.

A is not right because calcium chloride is originally a product of CO2 made from marble and hydrochloric acid, and no matter how much CO2 you use

B is not right because the Ca(OH)2 of lime water, excess CO2 will turn Ca(OH)2 into CaHCO3, this thing is not precipitation.

C is not right because, this itself does not reflect when it passes through and does not precipitate D Yes, the reason is that the generated NaHCO3 is melted in water, but because it is a saturated sodium carbonate solution, the solubility of NaHCO3 is less than that of Na2CO3, so it is precipitated

AB produces calcium bicarbonate ......Soluble in water.

d, sodium bicarbonate will be generated, which requires the participation of water, the solution is saturated, and the water needs to react, so it will become a supersaturated solution......There will definitely be precipitation.

CaCO3 precipitate will be generated when it is just passed, but CaHCO3 will be generated as soon as CO2 is more, this product is soluble in water, probably the formula is CaCO3 + CO2 + H20 CaHCO3, A, B have Ca, so they are not right, d saturated sodium carbonate Na2CO3 and C02 form slightly soluble NaHCO3, so there must be a precipitation, probably the formula is Na2CO3 + H20 + CO2 NaHCO3, no trimming, I hope it will help you.

AB can form bicarbonate, which is calcium bicarbonate, which is soluble in water.

Saturated sodium carbonate, here emphasizes the saturated sodium carbonate solution, when carbon dioxide is introduced, the concentration of carbonate in the solution increases, because of the homoionic effect, so there is sodium carbonate precipitation.

A calcium chloride and b lime water are not emphasized to be saturated solutions, when their concentration is relatively small, even if the carbon dioxide introduced reaches the saturation level, it cannot guarantee that the concentration of calcium carbonate reaches the saturation level. At the same time, we also know that the solubility of carbon dioxide is very small.

a.Correct, the amount of gaseous matter at the same temperature, pressure and volume is equal, and the mass ratio is equal to the molar mass ratio of 28:44:48 = 7:11:12

b.Incorrect, the ratio of oxygen atomic substances of the same mass = 1 28 * 1 : 1 44 * 2 : 1 48 * 3

c.Correct, the density ratio of the gas at the same temperature and pressure is equal to the ratio of molar mass 28:44:48 = 7:11:12

d.Correct, when they all contain 1mol of oxygen atoms, the ratio of the amount of the three gaseous substances is 1:1 2:1 3 = 6:3:2

Silicic acid precipitate is selected. na2sio3+co2+h2o=h2sio3↓+na2co3

b.Al(OH)3 pellets are obtained. 2naalo2+co2+3h2o=2al(oh)3↓+na2co3

The acidity is weaker than that of HCl, so it will not get BaCO3 precipitation.

d.NaHCO3 precipitate was obtained, and the solubility of Na2CO3 was greater than that of NaHCO3. Na2CO3 (saturated solution) + H2O + CO2 = 2NaHCO3

The last one will not be cloudy and will produce sodium bicarbonate, which is best dissolved.

a. Hydrochloric acid is a strong acid, and carbonic acid is a weak acid, so carbonic acid cannot be prepared from hydrochloric acid, that is, carbon dioxide and calcium chloride do not react, and there is no precipitation and precipitation in the end, so a is selected;

B. Carbon dioxide reacts with calcium hydroxide to form calcium carbonate, calcium carbonate is a poorly soluble electrolyte, so a small amount of CO2 gas into Ca(OH) will generate calcium carbonate white precipitate, so B is not selected;

c. The acidity of carbonate is greater than that of aluminum hydroxide, and the carbon dioxide is passed into the solution of sodium metaaluminate, which will produce a white precipitate of aluminum hydroxide, so C is not selected;

d. Sodium silicate can react with carbonic acid to form sodium carbonate and silicic acid, silicic acid is white and insoluble in water, so D is not selected

So choose A

c、③⑤

Na2CO3 + CO2 + H2O = 2NaHCO3 consumes water and produces substances with less solubility, so some solids cannot be dissolved and precipitate.

Na2SiO3+CO2+H2O=Na2CO3+H2SiO3 (precipitate).

BaCl2 solution Ba(NO3)2 solution cannot precipitate because weak acid (carbonic acid) cannot make strong acid.

The Ca(OH)2 solution precipitates first, and finally precipitates and dissolves.

CBACL2 solution and Ba(NO3)2 solution were selected to generate acid and dissolve. Saturate Na2CO3 to produce NaHCO3.

The Na2SiO3 solution should generate H2SiO3.