Sodium peroxide reacts with water on the two line bridge problem.

Reduced oxygen element.

Not to reach sodium hydroxide.

, but because both sides of the chemical equation are about to drop the same part, the two-line bridge problem is similar to that of aluminum and sodium hydroxide.

Sodium peroxide. It is both an oxidizing agent and a reducing agent, and the oxygen atom of 2mol (-1 valence) loses 2mol of electrons and is oxidized to oxygen, so it is filled with 2 electrons lost.

At the same time, sodium peroxide is also an oxidant, and the oxygen atom of 2mol (-1 valence) gets 2mol electrons and is reduced to -2 valence oxygen ions, so the double line bridge should be valency.

The elevated one loses two electrons, and the one with decreased valency gains two electrons instead of four electrons.

The problem is that the reduced oxygen does not reach the sodium hydroxide, but the water, but because both sides of the chemical equation offer the same part, the two-line bridge problem is similar to that of aluminum and sodium hydroxide.

Sodium peroxide is both an oxidizing agent and a reducing agent, and the oxygen atom of 2mol (-1 valence) loses 2mol of electrons and is oxidized to oxygen, so it needs to be filled with 2 electrons.

At the same time, sodium peroxide is also an oxidant, 2mol (-1 valence) of oxygen atoms, 2mol electrons are obtained, which are reduced to -2 valence oxygen ions, so the two-wire bridge should lose two electrons if the valency is increased, and 2 electrons are obtained when the valency is reduced, instead of four electrons.

The first one is correct, because the reduced oxygen element does not reach the sodium hydroxide, but the water, but because both sides of the chemical equation offer to the same part, the water is not written, and this two-line bridge problem is similar to the one between aluminum and sodium hydroxide, and the oxidized or reduced element must be found.

The second to be exact.

Because if it is a double-line bridge, it is necessary to write out who oxidizes and who reduces.

The total reaction is as follows, 2Na2O2+4H2O2=4NaOH+O2. Sodium peroxide.

Sodium peroxide can be seen as:Hydrogen peroxideThe reaction of salt, sodium peroxide and water is actually the hydrolysis of salt, but this hydrolysis can be carried out to the endNa2O2+2H2OL=2NaOH+H2O2, H2O2 is unstable, 2H2O2=2H2O+O2.

Learn chemistry well

To observe is to observe. Famous physiologist Pavlov.

On the walls of his laboratory are six large thought-provoking characters, Observe, Observe, Observe. Watt.

The steam engine was invented after being beneficially inspired by a keen observation of the sight of water vapor impulsing the lid of the kettle.

These all illustrate the importance of observation.

In chemistry experiments, we should cultivate our own good observation habits and scientific observation methods, which is one of the important conditions for learning chemistry well. So how to observe the experiment, first of all, we should pay attention to overcoming the interest of observation in curiosity and fun, we should clearly observe what and why, and observe the experimental phenomenon in a planned and purposeful way under the guidance of the teacher.

Observation should generally follow the sequence of before, during, and after the reaction, and the specific steps are: The color, state, and smell of the reactants. Reaction conditions. Various phenomena in the reaction process. The color, state, and smell of the reaction product.

Finally, under the guidance of the teacher, the observed phenomena are analyzed, judged, synthesized and generalized, and scientific conclusions are drawn, accurate concepts are formed, and the purpose of understanding and mastering knowledge is achieved.

For example, in the fourth experiment in the introduction, basic copper carbonate is heated in a test tube.

The purpose of observation is whether a new substance is formed after the basic copper carbonate is heated, and the observation content and methods are: 1. Before the reaction: basic copper carbonate is a green powdery solid. 2. In the reaction, the condition is heating, and the phenomenon in the process of change is that the green powder gradually turns black, and the test tube wall gradually has a water mist to form, and the lime water is clarified.

Gradually muddy. 3. After the reaction: all the green powder in the test tube turns black, water droplets are generated on the wall of the test tube, and the clarified lime water is all turbid. After analysis, it was found that the basic copper carbonate was heated to form new substances, black copper oxide, water and carbon dioxide.

Finally, compared with the previous three experimental phenomena, it is summarized that other substances are formed when the change occurs, and this change is called the concept of chemical change.

Reduced oxygen element.

Not to reach sodium hydroxide.

, but reaches the water, but due to the chemical equation.

Both sides offer the same part, so the two-line bridge problem is similar to that of aluminum and sodium hydroxide.

Two-line bridge method. This method can not only express the direction and total number of electron transfers, but also the valency of the elements.

Relationship between lifting and oxidation and reduction.

The arrows of the double line bridge start at the atoms or ions of the reactants of the element in question, and the arrows point to the atoms or ions of the corresponding element in the product after the valency change occurs. ** The total number of electrons "lost" or "gained", the rise and fall of valency, and the "oxidized" or "reduced" element should be indicated.

Two-line bridge writing steps:

Labeled valence: Clearly indicate all redox reactions that have occurred.

The valency of the elements of the constant, the elements of constant valence are not standardized valency.

Connecting double lines: The same element of the standardized valency is pointed from the reactant to the product with a straight line and an arrow (note: the start and end of the arrow are always aligned with each element).

Standard gain and loss: 1. Number of standard electron transfer or deviation: clearly mark the number of gain and loss of electrons, and the format is "gain and loss The number of atoms that have undergone redox reaction The number of electrons gained and lost per unit atom".

2. Changes in the valence of the standardizer: The change of the valence is always marked, and there are only two ways to write "the valence increases" and "the valence decreases", and cannot be written as "price increase" and "price reduction".

3. Mark the type of element reaction: always mark the reaction that occurs in the element, "oxidized" or "reduced", and the rest are written incorrectly.

4. Check the conservation of gains and losses of electrons: check whether the number of gains and losses is equal, and re-analyze if not.

The reaction is step-by-step.

The first step is the decomposition of Na2O2 and water to generate NaOH and H2O2, and the second step is the decomposition of H2O2, write the equation of the two steps respectively, and then superimpose, taking care that the water does not disappear, because the transferred electrons belong to different parts.

Chemical equation.

Also known as a chemical reaction.

An equation is a formula that uses a chemical formula to express a chemical reaction. Chemical equations reflect objective facts. Use the chemical formula (in organic chemistry, organic matter generally uses the simple structure formula.

The formula that represents the chemical reaction of a substance is called a chemical equation.

The chemical equation not only indicates the reactants, products, and reaction conditions. At the same time, the stoichiometric number represents the amount of each reactant and product substance.

relationship, by relative molecular mass.

Or relative atomic mass can also express the mass relationship between the substances, that is, the mass ratio between the substances. For gas reactants and products, the volume ratio can also be obtained directly from the stoichiometric number.

1.Chemical equations are written about reaction conditions. The general ones are marked with δ above the equal sign. Trim coefficients are mostly not fractions (except for reductions between them).

2.The reaction that can be carried out at room temperature and pressure does not need to write the conditions; However, if the experiment in the title has a specific condition, it is always marked with that specific condition (e.g., heating).

3.When a single condition is reflected, the condition is always written above; If there are two or more conditions, what cannot be written above is written below; When there is both a catalyst and other reaction conditions, the catalyst is always written on it.

Write the equation first.

2Na + 2H2O ==2NaOH + H2 The two-line bridge indicates: the arrow points from Na to Na in Naoh, and it is marked "lose 2E-".

The arrow points from h in h2o to h2 with the mark "get 2e-".

Sodium peroxide. It reacts with carbon dioxide to form sodium carbonate.

oxygen, in which sodium peroxide is both an oxidizing agent and a reducing agent, according to which the direction and number of electron transfers are marked by a two-wire bridge;

Sodium peroxide reacts with water to form sodium hydroxide.

and oxygen; Alumina.

It reacts with sodium hydroxide solution to form sodium metaaluminate.

and water, from which the ionic equation for the reaction is written.

2Na2O2+2CO2=2Na2CO3+O2, using the "two-line bridge method."

The direction and number of electron transfers are marked as:

Na2O2 and H2O generate NaOH and O2, and the ion equation of the reaction is: 2Na2O2+2H2O=4Na++4OH-+O2;

Alumina reacts with sodium hydroxide solution to form sodium metaaluminate and water, and the ionic equation of the reaction is: Al2O3+2OH-=ALO2-+H2O.

Summary. Double-line bridge drawing method for the reaction of sodium peroxide with hydrochloric acid.

Note that sodium peroxide is both an oxidizing agent and a reducing agent<>

Let's see what's going on. You can ask for it.

Every time I write a double-line bridge, I don't know which element to write and how to find it.

Which element price list will you memorize.

Periodic table??? Or is it valence???

For example, some common compounds, or elements have a fixed valency, and you can start from this place.

Valence listOh, that's very important.

Yes, it's a little unfamiliar.

The main starting point of this two-lane bridge is the problem of the rise and fall of the valence.

For example, the estimated valency of sodium is a positive monovalent perturbation, so we can judge the hidden failure and guess that the valency of oxygen is -1 valence, and then look at the valency change of oxygen at the back to write a double-line bridge.

It's best to memorize this, otherwise there will be a lot of questions.

In addition, you must be able to write chemical equations, otherwise you will not be able to analyze the rise and fall of valence.

Therefore, in an equation, which element has a change in valence, write which?

Therefore, for this problem, we must first write the equation of the chemical slag bureau, then we must be clear in the valency foci of common compounds, and finally ask the Yinliangshan question according to the valency rise and fall of reactants and products to write the double-line bridge.

That's right, it's to look at the rise and fall of the valence of that element.

OKKK got it, thanks.

The two-line bridge is to see the loss of electrons, that is, the valency rise and fall of the element, so it is to see the valency change of the element.

Sodium peroxide and carbon dioxide are destroyed.

reaction to produce sodium carbonate.

and water, the transfer of electrons in the reaction:

Among them, Na2O2 is an oxidant or a reducing agent, Na2CO3 is a reducing product, and residual permeation O2 is an oxidation cracking ridge product.